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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#803470 | #9868. GCD | ucup-team3734# | WA | 1ms | 4004kb | C++23 | 893b | 2024-12-07 17:15:47 | 2024-12-07 17:15:55 |
Judging History
answer
#include "bits/stdc++.h"
using namespace std;
using ll = long long;
using ld = long double;
#define all(x) (x).begin(), (x).end()
const int M = 5050;
const ll inf = 1e18;
map<ll, ll> mem[M];
ll gcd(ll a, ll b) {
while (a) {
b %= a;
swap(a, b);
}
return b;
}
ll rec(ll a, ll b) {
// cerr << a << " " << b << "\n";
if (mem[a].contains(b))
return mem[a][b];
if (a == 0 && b == 0)
return 0;
ll g = gcd(a, b);
a /= g, b /= g;
if (a == 0 || b == 0)
return 1;
if (a == 1)
return 2;
ll k = 0;
while ((g = gcd(a, b - k)) == 1)
++k;
return mem[a][b] = min(rec(a - 1, b) + 1, rec(a / g, (b - k) / g) + k);
}
int main() {
#ifndef ONLINE_JUDGE
freopen("g.txt", "r", stdin);
#endif
ios_base::sync_with_stdio(false);
int t;
cin >> t;
while (t--) {
ll a, b;
cin >> a >> b;
cout << rec(a, b) << "\n";
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3912kb
input:
3 3 4 12 20 114 514
output:
3 4 6
result:
ok 3 lines
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 4004kb
input:
990 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 1 10 1 11 1 12 1 13 1 14 1 15 1 16 1 17 1 18 1 19 1 20 1 21 1 22 1 23 1 24 1 25 1 26 1 27 1 28 1 29 1 30 1 31 1 32 1 33 1 34 1 35 1 36 1 37 1 38 1 39 1 40 1 41 1 42 1 43 1 44 1 45 1 46 1 47 1 48 1 49 1 50 1 51 1 52 1 53 1 54 1 55 1 56 1 57 1 58 1 59 1 60 2 3 2 4 2...
output:
2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 4 2 3 3 2 3 4 2 3 3 2 3 4 2 3 3 2 3 4 2 3 3 2 3 4 2 3 3 2 3 4 2 ...
result:
wrong answer 675th lines differ - expected: '5', found: '6'