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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#80268 | #3836. So I'll Max Out My Constructive Algorithm Skills | darielangel | TL | 2ms | 3568kb | C++17 | 1.5kb | 2023-02-23 12:09:16 | 2023-02-23 12:09:17 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
int t,n;
int M[64][64];
int S[64][64];
int B[64][64];
long long V[64];
bool ok;
int x[4]= {-1,0,1,0};
int y[4]= {0,1,0,-1};
vector<int>ans;
struct st{
int F,S,V;
}vec[64*64];
void dfs(int a, int b){
ans.push_back(M[a][b]);
V[a] |= (1<<b);
/*cout<<"-> "<<S[a][b]<<" : "<<B[a][b]<<'\n';
for(int i=0;i<ans.size();i++){
cout<<ans[i];
if(i<ans.size()-1)cout<<' ';
}cout<<'\n';*/
if(ans.size() == n*n){
if(S[a][b]>=B[a][b]){
ok=1;
}
return;
}
int nx,ny;
for(int i=0;i<4;i++){
nx = a+x[i];
ny = b+y[i];
if(nx<0||ny<0||nx==n||ny==n)continue;
if(V[nx] & (1<<ny))continue;
if(M[a][b] >= M[nx][ny]){
S[nx][ny] = S[a][b]+1;
B[nx][ny] = B[a][b];
} else {
S[nx][ny] = S[a][b];
B[nx][ny] = B[a][b]+1;
}
dfs(nx,ny);
if(ok)return;
}
V[a] ^= (1<<b);
ans.pop_back();
}
bool sort(st a, st b){
return a.V > b.V;
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cin>>t;
while(t--) {
cin>>n;
int c=0;
for(int i=0; i<n; i++)
for(int j=0; j<n; j++) {
cin>>M[i][j];
vec[c].F = i;
vec[c].S = j;
vec[c++].V = M[i][j];
}
ok=0;
for(int i=0;i<n*n;i++){
ans.clear();
fill(V,V+n,0);
dfs(vec[i].F,vec[i].S);
if(ok)break;
}
for(int i=0;i<ans.size();i++){
printf("%d",ans[i]);
if(i<ans.size()-1)printf(" ");
}printf("\n");
}
}
Details
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Test #1:
score: 100
Accepted
time: 2ms
memory: 3568kb
input:
1 2 4 3 2 1
output:
4 3 1 2
result:
ok correct
Test #2:
score: -100
Time Limit Exceeded
input:
100 9 30 75 35 51 25 19 76 65 62 11 56 63 60 77 48 28 26 74 16 44 46 41 17 8 66 61 42 29 7 43 38 40 31 27 10 39 52 23 58 80 50 20 33 69 47 79 1 5 49 22 37 71 18 70 54 72 4 64 55 34 12 6 15 14 53 45 13 32 59 73 57 81 36 3 78 24 2 68 9 67 21 7 11 28 2 19 9 41 24 17 34 5 10 42 18 47 33 35 22 8 49 1 29 ...