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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#791313 | #7925. Chayas | PoonYaPat | WA | 1ms | 7712kb | C++14 | 982b | 2024-11-28 18:02:16 | 2024-11-28 18:02:18 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll mod= 998244353;
const int MX=(1<<24)+10;
int n,m,com[MX],val[27][27];
ll dp[MX];
bool can[MX][25];
int main() {
ios_base::sync_with_stdio(0); cin.tie(0);
cin>>n>>m;
for (int i=0; i<m; ++i) {
int a,b,c; cin>>a>>b>>c;
--a; --b; --c;
val[a][b]|=(1<<c);
val[c][b]|=(1<<c);
}
int mul=1;
for (int i=0; i<n; ++i) com[mul]=i, mul*=2;
for (int k=0; k<n; ++k) {
can[0][k]=true;
for (int bit=1; bit<(1<<n); ++bit) {
int x=bit&-bit,lft=bit-x;
if (can[lft][k] && ((val[com[x]][k]&lft)==0)) can[bit][k]=true;
}
}
dp[0]=1;
for (int bit=1; bit<(1<<n); ++bit) {
for (int k=0; k<n; ++k) if (bit&(1<<k)) {
if (can[bit^(1<<k)][k] && can[bit^((1<<n)-1)][k]) dp[bit]=(dp[bit]+dp[bit^(1<<k)])%mod;
}
}
cout<<dp[(1<<n)-1]<<"\n";
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 7712kb
input:
5 4 1 2 4 2 3 5 3 2 4 1 3 2
output:
4
result:
ok single line: '4'
Test #2:
score: 0
Accepted
time: 1ms
memory: 7648kb
input:
4 2 3 1 4 1 4 3
output:
0
result:
ok single line: '0'
Test #3:
score: 0
Accepted
time: 1ms
memory: 7668kb
input:
5 5 3 1 2 2 5 4 5 4 3 3 1 5 1 4 5
output:
2
result:
ok single line: '2'
Test #4:
score: -100
Wrong Answer
time: 0ms
memory: 7676kb
input:
6 6 1 6 3 2 3 4 5 6 4 3 5 1 1 3 4 1 2 4
output:
24
result:
wrong answer 1st lines differ - expected: '6', found: '24'