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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#788742 | #9622. 有限小数 | DarwinA66 | WA | 1ms | 4120kb | C++20 | 1.3kb | 2024-11-27 18:06:50 | 2024-11-27 18:07:01 |
Judging History
answer
#include<bits/stdc++.h>
#define gcd __gcd
using namespace std;
vector<long long>target;
vector<pair<long,long>>assets;
int main()
{
int T;
scanf("%d",&T);
for(int i=0;i<=60;i++)
{
for(int j=0;j<=i;j++)
{
long long number=(1ll*pow(2,j))*(1ll*pow(5,i-j));
if(number>0)target.push_back(number);
}
}
sort(target.begin(),target.end());
while(T--)
{
int a,b;
scanf("%d %d",&a,&b);
int k=b;
while(k%2==0){k=k/2;}
while(k%5==0){k=k/5;}
if(k==1)
{
printf("0 1\n");
}
else
{
for(int i=0;i<target.size();i++)
{
long long p=((b-a)*1ll*target[i])%b;
long long q=(b*1ll)*target[i];
long long o=gcd(p,q);
p/=o;
q/=o;
assets.push_back({p,q});
}
sort(assets.begin(),assets.end());
for(int i=1;;i++)
{
if(assets[i].second<=1e9)
{
printf("%lld %lld\n",assets[i].first,assets[i].second);
break;
}
}
assets.clear();
}
}
return 0;
}
詳細信息
Test #1:
score: 0
Wrong Answer
time: 1ms
memory: 4120kb
input:
4 1 2 2 3 3 7 19 79
output:
0 1 0 1 0 1 0 1
result:
wrong answer The result is not terminating.(Testcase 2)