QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#788393 | #8519. Radars | cjr2010 | WA | 0ms | 3936kb | C++14 | 1.3kb | 2024-11-27 16:46:13 | 2024-11-27 16:46:13 |
Judging History
answer
/*
考虑优化暴力dp的状态
明确可以用啥判断棋盘全被覆盖
就是找到棋盘被覆盖的一些简单的充要条件
发现只要四个角都被覆盖即可 那就做完了
*/
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define inf 0x3f3f3f3f3f3f3f3fll
#define For(i,l,r) for(int i=(l);i<=(r);++i)
#define Rof(i,l,r) for(int i=(l);i>=(r);--i)
bool M_S;
const int N=505;
int n,a[N][N],f[(1<<4)];
void MAIN1(){
cin>>n;
For(i,1,n) For(j,1,n) cin>>a[i][j];
if(n==1){
cout<<a[1][1]<<"\n";
return ;
}
memset(f,0x3f,sizeof(f));
f[0]=0;
For(i,1,n) For(j,1,n){
#define dis(x,y) min(abs((x)-i),abs((y)-j))
For(s,0,(1<<4)-1){
int t=s;
if(dis(1,1)<=n/2) t|=(1<<0);
if(dis(1,n)<=n/2) t|=(1<<1);
if(dis(n,1)<=n/2) t|=(1<<2);
if(dis(n,n)<=n/2) t|=(1<<3);
f[t]=min(f[t],f[s]+a[i][j]);
}
}
cout<<f[(1<<4)-1]<<"\n";
}
void _MAIN1(){}
int T;
void MAIN(){
cin>>T;
For(_,1,T) MAIN1(),_MAIN1();
}
bool M_T;
signed main(){
// freopen(".in","r",stdin);
// freopen(".out","w",stdout);
ios::sync_with_stdio(false);
cin.tie(0),cout.tie(0);
double T_S=clock();MAIN();double T_T=clock();
cerr<<"T:"<<(T_T-T_S)/CLOCKS_PER_SEC<<"s ";
cerr<<"M:"<<(&M_S-&M_T)/1048576<<"MiB\n";
return 0;
}
详细
Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 3936kb
input:
2 3 1 1 1 1 1 1 1 1 1 5 8 5 2 8 3 5 6 9 7 3 7 8 9 1 4 8 9 4 5 5 2 8 6 9 3
output:
1 1
result:
wrong answer 2nd numbers differ - expected: '5', found: '1'