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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#787830#5414. Stop, Yesterday Please No MorexuancaiTL 547ms7776kbC++142.4kb2024-11-27 14:48:392024-11-27 14:48:41

Judging History

你现在查看的是最新测评结果

  • [2024-11-27 14:48:41]
  • 评测
  • 测评结果:TL
  • 用时:547ms
  • 内存:7776kb
  • [2024-11-27 14:48:39]
  • 提交

answer

//
//  main.cpp
//  ICPC2022nanjingA
//
//  Created by Xuan Cai on 2024/11/27.
//

#include <iostream>
using namespace std;
#include <vector>
#include <map>
#include <utility>
void solve(){
    int n , m  , k  ;
    cin >> n >> m >> k ;
    string s; cin >> s;
    int L = 1 , R = m , U = 1 , D = n ;
    int x = 0 , y = 0 ;
    int xl =0;
    int xr = 0 ;
    int yl = 0;
    int yr = 0 ;
    for(int i = 0 ; i < s.size() ; i++){
        if(s[i] == 'L'  ) x--;
        if(s[i] == 'R'  ) x++;
        if(s[i] == 'U'  ) y--;
        if(s[i] == 'D'  ) y++;
        xl = min(xl , x) ;
        xr = max(xr , x) ;
        yl = min(yl ,y) ;
        yr = max(yr , y);
        
    }
    L = 1 + abs(xl);
    R = m - abs(xr);
    U = 1 + abs(yl);
    D = n - abs(yr) ;
    //cout << L  << " " << R <<" " << U << " " << D  <<endl;
    if( L > R   ||  U > D ) {
        if(k == 0 ) {
            cout << m * n  << endl; return;
        }else {
            cout << 0  << endl; return;
        }
    }
    map<pair<int, int> , int > dian;
    map<pair<int, int> , int > sum;
    int X = m - L + 1; int Y = n - U + 1;
    dian[{X , Y  } ] = 1;
    int XL  = m - L + 1 , XR = m - L  + 1 , YU = n - U + 1  ,  YD  = n - U  + 1;
    for(int i = 0 ; i < s.size() ; i++){
        if(s[i] == 'U') Y++;
        if(s[i] == 'D') Y--;
        if(s[i] == 'L') X++;
        if(s[i] == 'R') X--;
        dian[{X, Y}] = 1;
        XL = min(XL , X ) ;
        XR = max(XR , X) ;
        YU = min(YU , Y);
        YD = max(YD , Y) ;
    }
    int shu = (R - L + 1 ) * (D - U + 1);
    for(int i = XL; i <= XR + m ; i++){
        for(int j = YU; j <= YD + n ; j++){
            sum[{i , j}] = sum[{i - 1 ,j }] + sum[{i , j - 1}] + dian[{i ,j}] - sum[{i - 1 , j - 1}];
          //  cout << i << " " << j << " " <<  sum[{i, j}] << endl;
        }
    }
    
    int res = 0 ;
    for(int i = 1; i <= m ; i++){
        for(int j = 1; j <= n ; j++){
            int down = j + D - U;
            int right = i + R - L ;
            shu =  (R - L + 1 ) * (D - U + 1) - sum[{right, down}] +  sum[{ right , j - 1 }] +  sum[{ i - 1, down }] - sum[{ i - 1 , j - 1}] ;
          //  cout << i << " " << j << " " << right << " " << down << " " <<  shu << endl;
            if(shu == k) res++;
        }
    }
    cout << res << endl;
}
int main(int argc, const char * argv[]) {
    int t; cin >> t;
    while(t--) solve();
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3584kb

input:

3
4 5 3
ULDDRR
4 5 0
UUUUUUU
4 5 10
UUUUUUU

output:

2
20
0

result:

ok 3 number(s): "2 20 0"

Test #2:

score: 0
Accepted
time: 547ms
memory: 7776kb

input:

1060
19 12 0
UDLDDUUUUDDDLLRDUDUURULUUUDRDUDRDRLRLRLULULLLDLDDRLUUUURUUUDDRLLRUUUDULURUULLRDRLRDDURDUUURRRLURLRUULRRUDURDLUUURDLURDDLUUURDDRLLURRDLRUDLRDRLLRRDRDDLDRURRRLUDULLLRUUDLRRURRDLLRRRDLLRDDDLRLRURURDDDL
11 1 0
UR
3 18 33
UDRLR
17 11 132
RLDRDLDRUU
6 10 13
UULUDDLRDLUUDLDD
1 15 0
D
6 20 50
D...

output:

228
11
20
99
18
15
34
240
15
0
0
13
14
18
26
16
1
19
108
8
2
2
3
7
0
30
16
21
0
8
10
9
15
5
320
11
7
3
0
0
12
0
11
0
0
14
0
22
36
51
23
7
6
4
2
48
28
8
63
22
49
13
10
4
108
10
18
44
0
15
9
0
4
30
14
99
105
10
14
17
0
66
10
11
28
52
34
56
33
14
56
90
14
0
121
3
48
30
36
13
0
30
7
8
3
11
16
45
20
34
0...

result:

ok 1060 numbers

Test #3:

score: -100
Time Limit Exceeded

input:

1
1000 1000 979065
DDUULULUDULLULLDLUULURRLDURLRDLRRUURUUUDLRLUUDUUDUDLLDDDULU

output:


result: