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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#786524#8717. 骰子KanateTL 1ms3704kbC++171.9kb2024-11-26 21:55:162024-11-26 21:55:22

Judging History

你现在查看的是最新测评结果

  • [2024-11-26 21:55:22]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:3704kb
  • [2024-11-26 21:55:16]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int mod = 1e9 + 7 ;
const int N = 1505;
const int M = 205;
int n , m , q;
ll t[N][205];
ll *r[N];
int cnt[N];
ll ans[205];
ll qpow(ll a,ll b){
    ll ans = 1;
    for(;b;b>>=1,a=a*a%mod) if(b&1) ans = ans * a %mod;
    return ans;
}

ll* inv(int n,ll *a){
    ll *b;
    b = (ll*)malloc(sizeof(ll)*M);
    memset(b,0,sizeof(ll)*M);
    ll inv = qpow(a[0],mod-2);
    b[0] = inv;
    for(int i=1;i<=n;i++){
        for(int j=1;j<=i;j++) 
        b[i] = (b[i] - a[j]*b[i-j] + mod) % mod;
        b[i] = b[i] * inv % mod;
    }
    return b;
}

ll tmp[M],sum[N];

void mul(ll *a,ll *b){
    memset(tmp,0,sizeof tmp);
    for(int i=0;i<=200;i++)
    for(int j=0;j<=200-i;j++)
    tmp[i+j] = (tmp[i+j] + a[i] * b[j] %mod) % mod;
    for(int i=0;i<=200;i++) a[i] = tmp[i];
}
/*
3 3 3
 4 3 2 1
 0 1 0 1000000007
 0 500000004 0 500000004
 0 0 500000004 500000004
 1 1
 1 2
 1 3
*/
int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);cout.tie(0);
    cin >> n >> m >> q;
    t[0][0] = 1;
    for(int i=0;i<=m;i++) cin >> sum[i];
    for(int i=1;i<=n;i++){
        for(int j=0;j<=m;j++) cin >> t[i][j];
        while(cnt[i]<=m){
            if((t[i][cnt[i]]%=mod)!=0) break;
            cnt[i]++;
        }
        for(int j=0;j<=m-cnt[i];j++)
        t[i][j] = t[i][j+cnt[i]];
        for(int j=m-cnt[i]+1;j<=m;j++)
        t[i][j] = 0 ;
        if(cnt[i] == m+1) t[i][0] = 1;
        if(i!=1)mul(t[i],t[i-1]);
        
        r[i] = inv(200,t[i]);
        cnt[i] += cnt[i-1];
    }
    
    while(q-->0){
        int L,R ;
        cin >> L >> R;
        for(int i=0;i<=m;i++) ans[i] = t[R][i];
        int k = cnt[R] - cnt[L-1];
        if(L!=1) mul(ans,r[L-1]);
        ll ANS = 0 ;
        for(int i=k;i<=m;i++)
        ANS =(ANS + ans[i-k] * sum[i] %mod) %mod;
        cout << ANS << endl;
        
    }

    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3704kb

input:

3 3 3
4 3 2 1
0 1 0 1000000007
0 500000004 0 500000004
0 0 500000004 500000004
1 1
1 2
1 3

output:

3
1
0

result:

ok 3 number(s): "3 1 0"

Test #2:

score: 0
Accepted
time: 1ms
memory: 3612kb

input:

3 3 6
4 3 2 1
1000000007 0 1 0
1000000007 1 0 0
1000000007 0 1 0
1 1
1 2
1 3
2 2
2 3
3 3

output:

2
1
0
3
1
2

result:

ok 6 numbers

Test #3:

score: 0
Accepted
time: 1ms
memory: 3552kb

input:

1 1 1
604063100 57375033
742299910 257700098
1 1

output:

148903503

result:

ok 1 number(s): "148903503"

Test #4:

score: -100
Time Limit Exceeded

input:

1500 200 600000
253665324 876103781 804024983 929290295 908790466 176299158 528078340 696679927 416465140 509641654 705083449 361711737 250659645 735832780 35321360 383752049 203979021 178832532 785212637 514502839 169840231 65809146 504755349 516829442 382478309 901925498 142312128 782336477 741339...

output:

66394849
-141956992
-709911495
-566149272
16359498
544692508
495705795
-609141302
-665059892
441003348
589429674
-108749552
-852944969
-50729233
782296292
854444995
608076278
-227008940
609961969
3444634
-465602244
659524291
-615184586
-670036796
-740734196
214554716
662015873
-534383032
355211926
-...

result: