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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#786000#4957. Helping the TransitYarema#WA 1ms5660kbC++202.0kb2024-11-26 19:51:362024-11-26 19:52:03

Judging History

你现在查看的是最新测评结果

  • [2024-11-26 19:52:03]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:5660kb
  • [2024-11-26 19:51:36]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define RFOR(i, a, b) for(int i = (a) - 1; i >= (b); i--)
#define SZ(a) int(a.size())
#define ALL(a) a.begin(), a.end()
#define PB push_back
#define MP make_pair
#define F first
#define S second

typedef long long LL;
typedef vector<int> VI;
typedef vector<LL> VL;
typedef pair<int, int> PII;
typedef pair<LL, LL> PLL;
typedef double db;

struct DSU
{
	int n;
	VI p, sz;
	
	DSU(int _n = 0) 
	{
		n = _n;
		p.resize(n);
		iota(ALL(p), 0);
		sz.assign(n, 1);
	}
	int find(int v)
	{
		if (v == p[v])
			return v;
		return p[v] = find(p[v]);
	}
	bool unite(int u, int v)
	{
		u = find(u);
		v = find(v);
		if (u == v) 
			return false;
		if (sz[u] > sz[v])
			swap(u, v);
		p[u] = v;
		sz[v] += sz[u];
		return true;
	}
};

const int N = 100'447;
int in[N];
int out[N];
VI g[N];
VI gr[N];
bool used[N];
int col[N];
VI tps;

void dfs1(int v)
{
	used[v] = 1;
	for (auto to : g[v])
		if (!used[to])
			dfs1(to);
	tps.PB(v);
}

void dfs2(int v, int c)
{
	used[v] = 1;
	col[v] = c;
	for (auto to : gr[v])
		if (!used[to])
			dfs2(to, c);
}


int main()
{
	ios::sync_with_stdio(0);
	cin.tie(0);
	
	int n, m;
	cin >> n >> m;
	DSU d(n);
	vector<PII> edges(m);
	FOR (i, 0, m)
	{
		int a, b;
		cin >> a >> b;
		a--, b--;
		edges[i] = {a, b};
		g[a].PB(b);
		gr[b].PB(a);
	}
	
	FOR (i, 0, n)
		if (!used[i])
			dfs1(i);
	reverse(ALL(tps));
	int c = 0;
	fill(used, used + n, false);
	for (auto v : tps)
		if (!used[v])
			dfs2(v, c++);
	
	for (auto [a, b] : edges)
	{
		if (col[a] != col[b])
		{
			out[col[a]]++;
			in[col[b]]++;
		}
		d.unite(col[a], col[b]);
	}
	if (c == 1)
	{
		cout << "0\n";
		return 0;
	}
	int ans = 0;
	int cnt = 0;
	FOR (i, 0, c)
	{
		ans += out[i] == 0;
		ans += in[i] == 0;
		cnt += in[i] == 0 && out[i] == 0;
	}
	if (cnt * 2 == ans)
		cout << cnt << '\n';
	else
		cout << ans - cnt - 1 << '\n';
	
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 5660kb

input:

7 7
1 2
2 3
3 1
6 1
6 4
4 5
7 6

output:

2

result:

ok single line: '2'

Test #2:

score: 0
Accepted
time: 1ms
memory: 3656kb

input:

7 7
2 1
3 2
1 3
1 6
4 6
5 4
6 7

output:

2

result:

ok single line: '2'

Test #3:

score: 0
Accepted
time: 1ms
memory: 3624kb

input:

2 1
1 2

output:

1

result:

ok single line: '1'

Test #4:

score: 0
Accepted
time: 1ms
memory: 3612kb

input:

3 3
1 2
2 3
3 1

output:

0

result:

ok single line: '0'

Test #5:

score: 0
Accepted
time: 1ms
memory: 3548kb

input:

2 0

output:

2

result:

ok single line: '2'

Test #6:

score: -100
Wrong Answer
time: 1ms
memory: 3564kb

input:

6 4
1 2
1 3
4 6
5 6

output:

5

result:

wrong answer 1st lines differ - expected: '3', found: '5'