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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#785474#7744. ElevatoradivseAC ✓62ms8308kbC++204.0kb2024-11-26 18:02:202024-11-26 18:02:41

Judging History

你现在查看的是最新测评结果

  • [2024-11-26 18:02:41]
  • 评测
  • 测评结果:AC
  • 用时:62ms
  • 内存:8308kb
  • [2024-11-26 18:02:20]
  • 提交

answer

#include <iostream>
#include <algorithm>
#include <cstring>
#include <cmath>
#include <vector>
#include <set>
#include <queue>
#include <map>
#include <unordered_map>
#include <iomanip>
#define endl '\n'
#define int long long
#define rep(i,a,b) for(int i=(a);i<=(b);i++)
#define rep2(i,a,b) for(int i=(a);i>=(b);i--)
using namespace std;
template<typename T>
void cc(const vector<T>& tem) { for (const auto& x : tem) cout << x << ' '; cout << endl; }
template<typename T>
void cc(const T& a) { cout << a << endl; }
template<typename T1, typename T2>
void cc(const T1& a, const T2& b) { cout << a << ' ' << b << endl; }
template<typename T1, typename T2, typename T3>
void cc(const T1& a, const T2& b, const T3& c) { cout << a << ' ' << b << ' ' << c << endl; }
void cc(const string& s) { cout << s << endl; }
void fileRead() {
#ifdef LOCALL
    freopen("D:\\AADVISE\\cppvscode\\CODE\\in.txt", "r", stdin);
    freopen("D:\\AADVISE\\cppvscode\\CODE\\out.txt", "w", stdout);
#endif
}
void kuaidu() { ios::sync_with_stdio(false), cin.tie(0), cout.tie(0); }
inline int max(int a, int b) { if (a < b) return b; return a; }
inline double max(double a, double b) { if (a < b) return b; return a; }
inline int min(int a, int b) { if (a < b) return a; return b; }
inline double min(double a, double b) { if (a < b) return a; return b; }
void cmax(int& a, const int& b) { if (b > a) a = b; }
void cmin(int& a, const int& b) { if (b < a) a = b; }
void cmin(double& a, const double& b) { if (b < a) a = b; }
void cmax(double& a, const double& b) { if (b > a) a = b; }
using PII = pair<int, int>;
using i128 = __int128;
using vec_int = std::vector<int>;
using vec_char = std::vector<char>;
using vec_double = std::vector<double>;
using vec_int2 = std::vector<std::vector<int>>;
using que_int = std::queue<int>;


//--------------------------------------------------------------------------------
const int N = 1e5 + 10;
const int M = 1e6 + 10;
const int mod = 1e9 + 7;
const int INF = 1e16;
int n, m, T;

//--------------------------------------------------------------------------------
//struct or namespace:
struct node {
    int c;
    int to;
};
//--------------------------------------------------------------------------------

int dfs(vector<node>& A) {
    sort(A.begin(), A.end(), [&](const node& q1, const node& q2) {
        return q1.to > q2.to;
        });
    int len = A.size();
    int ans = 0;
    rep(i, 0, len - 1) {
        if (A[i].c <= 0 and i < len - 1) {
            A[i + 1].c += A[i].c;
            continue;
        }
        if (i == len - 1) {
            ans += (A[i].c + m - 1) / m * A[i].to;
            continue;
        }
        ans += (A[i].c + m - 1) / m * A[i].to;
        if (A[i].c % m) A[i + 1].c -= m - (A[i].c % m);
    }
    return ans;


    int las = 0;
    for (auto [c, to] : A) {
        c -= las;
        if (c <= 0) {
            las = -c;
            continue;
        }
        else las = 0;
        ans += to * (c / m);
        c %= m;

        if (c) {
            ans += to;
            las = m - c;
        }
        else {
            las = 0;
        }

    }

}

signed main() {
    fileRead();
    kuaidu();
    T = 1;
    cin >> T;
    while (T--) {
        cin >> n >> m; m /= 2;
        vector<node> F, A;
        rep(i, 1, n) {
            int c, w, f; cin >> c >> w >> f;
            if (w == 2) {
                A.push_back({ c,f });
                continue;
            }
            F.push_back({ c,f });
        }
        sort(F.begin(), F.end(), [&](const node& q1, const node& q2) {
            return q1.to > q2.to;
            });
        int len = F.size();
        rep(i, 0, len - 1) {
            if (i == len - 1) {
                A.push_back({ (F[i].c + 1) / 2,F[i].to });
                continue;
            }
            A.push_back({ (F[i].c + 1) / 2,F[i].to });
            if (F[i].c % 2) F[i + 1].c -= 1;
        }

        cc(dfs(A));
        // cc(ans);
    }
    return 0;
}
/*


*/

这程序好像有点Bug,我给组数据试试?

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3640kb

input:

2
4 6
1 1 8
7 2 5
1 1 7
3 2 6
8 1200000
100000 1 100000
100000 1 12345
100000 2 100000
100000 2 12345
100000 1 100000
100000 1 12345
100000 2 100000
100000 2 12345

output:

24
100000

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 38ms
memory: 5236kb

input:

5501
8 104
5 2 3
6 2 4
5 2 3
6 2 9
8 2 4
2 1 3
7 2 4
8 2 8
1 290
3 1 1
12 12
6 1 2
1 2 2
1 1 2
1 2 4
6 1 1
1 2 5
6 1 4
4 1 4
6 2 4
6 2 5
4 2 5
4 1 4
5 334
1 1 4
1 2 3
4 2 1
5 1 1
2 1 2
13 218
5 2 3
5 1 4
1 2 1
1 2 5
3 2 2
1 1 3
4 2 2
1 2 5
2 2 1
2 1 5
3 2 1
5 2 1
1 1 4
10 260
7 2 1
5 1 1
5 2 4
6 1 6...

output:

9
1
23
4
5
7
1
3
9
6
1
10
4
9
17
6
4
1
8
5
5
7
1
3
23
6
3
3
2
2
2
3
8
1
5
6
9
11
147
7
10
2
7
7
8
6
5
5
1
7
3
5
10
7
7
10
8
1
4
2
3
9
1
5
2
9
1
6
7
7
6
10
18
8
10
4
10
9
2
8
3
5
9
3
6
5
3
2
6
1
3
2
2
1
6
9
6
3
4
8
9
9
2
6
1
2
6
7
5
2
5
21
8
1
2
3
4
9
3
4
6
5
9
6
1
7
3
7
3
2
2
8
7
3
5
9
7
10
7
3
2
4
...

result:

ok 5501 lines

Test #3:

score: 0
Accepted
time: 51ms
memory: 8148kb

input:

3
100000 8
8 2 6
7 2 8
5 1 10
7 2 7
4 1 7
6 2 9
7 1 2
3 1 1
5 1 10
5 1 1
3 2 10
5 2 5
7 1 6
5 2 7
7 2 1
5 1 6
2 2 10
8 1 7
7 1 1
10 2 6
9 1 1
8 1 4
10 1 4
6 1 1
4 1 4
1 2 9
3 2 6
6 1 3
4 1 7
9 2 5
8 2 4
7 2 1
2 2 10
6 2 9
3 1 3
2 2 3
2 2 4
7 2 4
8 1 1
5 2 3
5 2 7
7 2 9
1 1 4
5 1 2
2 1 9
3 2 1
9 2 2
...

output:

568601
4708350936
93900404329230

result:

ok 3 lines

Test #4:

score: 0
Accepted
time: 62ms
memory: 8308kb

input:

3
100000 174
90429 1 64237
30851 1 44358
63571 2 89174
20391 2 28747
13561 2 88689
81508 2 28383
85733 1 5777
37524 2 34730
10588 2 88519
61493 2 83682
55885 1 65270
17669 2 63015
85387 1 64757
91420 2 74020
9067 2 91750
20809 1 52771
36478 2 17941
62064 1 36433
72912 2 6100
53923 2 73971
65825 2 39...

output:

2156004461915
884586357480
59034901233

result:

ok 3 lines

Test #5:

score: 0
Accepted
time: 57ms
memory: 8028kb

input:

3
100000 4418822
19907 1 13081
59730 2 93611
35050 1 5867
87777 1 21890
18374 1 82418
79526 2 76106
33510 2 45826
75573 1 42240
35449 1 98727
80720 2 65290
32021 2 51348
52399 2 97828
75498 2 51728
89905 1 22825
2855 1 26204
11427 1 99583
55530 2 37895
22256 2 92230
19533 1 9142
16138 1 54018
53102 ...

output:

84699074
270668
100000

result:

ok 3 lines

Extra Test:

score: 0
Extra Test Passed