#include <bits/stdc++.h>

using namespace std;

const int maxn = 2e5 + 5;

int n, ans;
int L[maxn], R[maxn], f[maxn];
vector<pair<int, int> > all;
vector<int> vec[maxn];

inline void solve_contain(){
    vector<pair<int, int> > all_new;
    sort(all.begin(), all.end(), [&] (const pair<int, int> &ths, const pair<int, int> &oth) { return ths.second < oth.second; });
    int mxl = 0;
    for (auto p: all) {
        if (mxl > p.first) continue; // this interval contains others, single point never contain others
        mxl = max(mxl, p.first);
        if (p.first != p.second) all_new.push_back(p);
    }
    all = all_new;
    // for (auto p: all) printf("(%d %d) ", p.first, p.second); puts("");
}

int main(){
    scanf("%d", &n);
    for (int i = 0; i < n; ++i) {
        int cnt; scanf("%d", &cnt);
        int mn = (int)(1e9) + 1, mx = 1;
        for (int j = 0; j < cnt; ++j) {
            int x; scanf("%d", &x);
            vec[i].push_back(x);
            mn = min(mn, x);
            mx = max(mx, x);
        }
        if (cnt >= 2) ans += 2;
        else ans += 1;
        all.push_back(make_pair(mn, mx));
    }

    solve_contain();

    for (int i = 0; i < all.size(); ++i) L[i] = 0, R[i] = (int)(1e9) + 1;

    for (int i = 0, j = -1; i < all.size(); ++i) {
        for (; j + 1 < all.size() && all[j + 1].first < all[i].second; ++j);
        assert(j != -1);
        L[i] = max(L[i], all[j].first);
    }
    for (int i = (int)all.size() - 1, j = (int)all.size(); i >= 0; --i) {
        for (; j - 1 >= 0 && all[j - 1].second > all[i].first; --j);
        assert(j != (int)all.size());
        R[i] = min(R[i], all[j].second);
    }

    vector<pair<int, int> > all_new;
    int res = 0;
    for (int i = 0; i < all.size(); ++i) {
        bool flg = false;
        for (auto x: vec[i]) if (x > L[i] && x < R[i]) flg = true;
        if (flg) all_new.push_back(all[i]);
    }
    all = all_new;
    for (int i = 0, j = -1; i < all.size(); ++i) {
        for (; j + 1 < all.size() && all[j + 1].second < all[i].first; ++j);
        // printf("(%d %d) L = %d R = %d\n", all[i].first, all[i].second, L[i], R[i]);
        // printf("j = %d\n", j);
        if (j == -1) f[i] = 1;
        else f[i] = f[j] + 1;
        // printf("i = %d f = %d\n", i, f[i]);
        res = max(res, f[i]);
    }

    printf("%d\n", ans - res);
    return 0;
}

/*
4
3 4 7 10
2 1 9
4 11 2 8 14
3 6 12 13

4
1 1
1 2
1 3
1 4

9
2 1 10
3 2 5 11
2 3 22
2 21 40
3 32 35 41
2 33 62
2 60 100
3 71 75 101
2 72 102
*/