QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#781346 | #9743. 重心树 | Zpair | WA | 26ms | 15172kb | C++20 | 720b | 2024-11-25 15:48:40 | 2024-11-25 15:48:41 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
const int N=2e5+5;
int n;
vector<int> e[N];
vector<pair<int, int> > ans;
set<int> s[N];
void dfs(int p,int fa){
s[p].insert(p);
for(int t:e[p]){
if(t==fa)continue;
dfs(t,p);
for(int x:s[t])s[p].insert(x);
ans.push_back({p,*(--s[t].lower_bound(p))});
}
}
void solve(){
scanf("%d",&n);
for(int i=1;i<=n;++i)
e[i].clear(),s[i].clear();
for(int i=1;i<=n;++i){
int x,y;
scanf("%d",&x);
while(x--){
scanf("%d",&y);
e[i].push_back(y);
e[y].push_back(i);
}
}
dfs(1,0);
for(auto [x,y]:ans)
printf("%d %d\n",x,y);
ans.clear();
}
int main(){
int T;cin>>T;
while(T--)solve();
}
/*
1
4
2 3 4
1 3
0
0
*/
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 14260kb
input:
2 4 2 3 4 1 3 0 0 3 1 3 1 3 0
output:
3 2 1 2 1 4 3 2 1 2
result:
ok Accepted (2 test cases)
Test #2:
score: -100
Wrong Answer
time: 26ms
memory: 15172kb
input:
40000 3 2 2 3 0 0 2 1 2 0 4 2 4 3 1 4 0 0 5 1 3 2 5 4 1 5 0 0 4 3 2 3 4 0 0 0 2 1 2 0 2 1 2 0 5 1 2 3 3 4 5 0 0 0 2 1 2 0 2 1 2 0 5 4 2 3 4 5 0 0 0 0 4 1 2 2 3 4 0 0 5 2 5 4 1 5 1 4 0 0 2 1 2 0 5 1 2 3 3 4 5 0 0 0 5 2 2 3 0 2 4 5 0 0 5 2 5 4 1 5 1 4 0 0 5 2 2 4 2 3 5 0 0 0 4 1 3 1 4 1 4 0 4 2 4 3 1 ...
output:
1 2 1 3 1 2 4 2 1 2 1 3 2 4 5 4 3 2 1 4 1 2 1 3 1 4 1 2 1 2 2 3 2 4 2 5 1 4 1 2 1 2 1 2 1 3 1 4 1 5 2 3 2 4 1 3 5 2 1 2 4 3 1 2 1 2 2 3 2 4 2 5 1 4 1 2 3 4 3 5 1 3 5 2 1 2 4 3 1 2 2 3 2 5 1 3 1 4 4 2 3 2 1 3 4 2 1 2 1 3 3 2 1 2 4 2 1 2 5 3 1 2 1 2 3 2 1 2 3 2 3 4 3 5 1 4 1 2 4 2 3 2 1 3 5 2 4 2 1 3 ...
result:
wrong answer The index of the node i's father should less than i (test case 4)