#include <bits/stdc++.h>
using namespace std;
#define int long long
#define ios ios::sync_with_stdio(0),cin.tie(0),cout.tie(0)
#define pos string::npos
#define endl '\n'
#define inf 1e18
typedef unsigned long long ull;
const int mod = 998244353;
const int N = 5e5+10;
const int Maxn = 2e5+5;
int min(int a,int b){return a<b?a:b;}
int max(int a,int b){return a>b?a:b;}
int Inv[N],F[N];//组合数C2
int gcd(int a,int b){ return b == 0 ? a : gcd(b,a%b);}
int lcm(int a,int b){return (a/gcd(a,b)*b);}
int km(int a,int b,int mod)
{int ans=1;while(b){if(b&1) ans=ans*a%mod;b>>=1;a=a*a%mod;}return ans;}
int km1(int a,int b,int mod)//指数取模,2^2^i,单求2^i要取模MOD-1
{int ans=1;mod--;while(b){if(b&1) ans=ans*a%mod;b>>=1;a=a*a%mod;}return ans;}
int C(int a,int b,int p){if(b>a) return 0;int res=1;for(int i=b,j=a;i>=1;i--,j--){res=res*j%p;res=res*km(i,p-2,p)%p;}return res;}
int Lucas(int a,int b,int p){if(a<p&&b<p) return C(a,b,p);return C(a%p,b%p,p)*Lucas(a/p,b/p,p)%p;}
int C2(int a,int b,int p){return F[a]*Inv[a-b]%p*Inv[b]%p;}
void C2init(int n,int p){n--;F[0]=F[1]=1;for(int i=2;i<=n;i++)F[i]=F[i-1]*i%p;Inv[n]=km(F[n],p-2,p);for(int i=n-1;i>=0;i--)Inv[i]=Inv[i+1]*(i+1)%p;}
int dx[]={1,-1,0,0},dy[]={0,0,1,-1};
typedef pair<int,int> pii;
typedef pair<double,double> pdd;
int n,m,k,q,a[N],din[N];
void solve() 
{
    //2->3,1->3,1->2
    for(int i=1;i<=100;i++) a[i]=0;
    for(int i=1;i<=9;i++){
        cin>>a[i];
    }
    if(a[2]>=a[1]){
        a[2]-=a[1];
        a[3]+=a[1];
    }
    else{
        a[3]+=a[2];
        a[1]-=a[2];
        a[2]=0;
        a[3]+=a[1]/3;
        a[1]%=3;
        if(a[1]==0) a[1]=0;
        else if(a[1]==2) a[2]++;
        else {
            for(int i=2;i<=9;i++){
                if(a[i]>0){
                    a[i+1]++,a[i]--;
                    break;
                }
            }
        }
    }
    //for(int i=1;i<=9;i++) cout<<a[i]<<" ";
    int ans=1;
    for(int i=2;i<=10;i++){
        for(int j=1;j<=a[i];j++){
            ans=(ans*i)%mod;
        }
    }
    cout<<ans<<endl;
}
// 7
// 5 3 0 0 0 0 0 0 0
// 4 1 1 1 0 0 0 0 0
// 1 0 0 0 0 0 0 0 0
// 1 0 0 0 0 0 0 0 1
// 1 0 0 0 0 0 0 0 2
// 99 88 77 66 55 44 33 22 11
// 100 90 80 70 60 50 40 30 20
signed main()
{
    ios;
    int T=1;
    //C2init(N,mod);
    cin>>T;
    while(T--)
    {
        solve();
    }
    return 0;
}