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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#77889 | #5506. Hyperloop | jeffqi | WA | 132ms | 12384kb | C++14 | 3.0kb | 2023-02-15 20:23:43 | 2023-02-15 20:23:45 |
Judging History
answer
#include<bits/stdc++.h>
#define rep(i,a,b) for (int i = (a); i <= (b); ++i)
#define drep(i,a,b) for (int i = (a); i >= (b); --i)
#define grep(i,u) for (int i = head[u],v = e[i].v; i; v = e[i = e[i].nxt].v)
#define LL long long
#define il inline
#define pii pair<int,int>
#define pll pair<LL,LL>
#define fi first
#define se second
#define pb push_back
#define mp make_pair
using namespace std;
il LL read() {
LL x = 0,y = 1; char ch = getchar(); while (!isdigit(ch)) {if (ch == '-') y = -y; ch = getchar();}
while (isdigit(ch)) {x = x*10+ch-'0'; ch = getchar();} return x*y;
}
namespace qiqi {
const int N = 1e5+5,M = 3e5+5,L = 27,P = 1e9+7; const LL INF = 0x3f3f3f3f3f3f3f3f;
int n,m,ecnt,head[N],cnt,pw[N],rt[N],pool[N*L],tp,pre[N],pos[N]; LL dis[N]; pll p[N]; bool vis[N];
struct Edge {int v,w,nxt;} e[M<<1]; il void add(int u,int v,int w) {e[++ecnt] = (Edge){v,w,head[u]}; head[u] = ecnt;}
il void Dij(int s) {
rep(i,1,n) {dis[i] = INF; vis[i] = 0;}
priority_queue<pll> q; q.push(mp(dis[s] = 0,s));
while (!q.empty()) {
int u = q.top().se; q.pop();
if (vis[u]) continue; vis[u] = 1;
grep(i,u) if (dis[u]+e[i].w < dis[v]) {
q.push(mp(-(dis[v] = dis[u]+e[i].w),v));
}
}
}
struct Node {int lc,rc,h,siz;} a[N*L];
il int new_node() {
int x = tp ? pool[tp--] : ++cnt;
a[x] = (Node){0,0,0,0}; return x;
}
il void init(int n) {
pw[0] = 1; rep(i,1,n) pw[i] = 1LL*N*pw[i-1]%P;
}
il void push_up(int x,int l,int r) {
int mid = l+((r-l)>>1); a[x].siz = a[a[x].lc].siz+a[a[x].rc].siz;
a[x].h = (1LL*a[a[x].lc].h*pw[r-mid]%P+a[a[x].rc].h)%P;
}
void upd(int &x,int y,int l,int r,int p) {
a[x = new_node()] = a[y]; if (l == r) {++a[x].h; ++a[x].siz; return;} int mid = l+((r-l)>>1);
p <= mid ? upd(a[x].lc,a[y].lc,l,mid,p) : upd(a[x].rc,a[y].rc,mid+1,r,p); push_up(x,l,r);
}
void del(int x,int l,int r,int p) {
if (!x) return; pool[++tp] = x; if (l == r) return; int mid = l+((r-l)>>1);
p <= mid ? del(a[x].lc,l,mid,p) : del(a[x].rc,mid+1,r,p);
}
bool qry(int x,int y,int l,int r) {
if (l == r) return a[x].h > a[y].h; int mid = l+((r-l)>>1);
return a[a[x].rc].siz != a[a[y].rc].siz || a[a[x].rc].h != a[a[y].rc].h ? qry(a[x].rc,a[y].rc,mid+1,r) : qry(a[x].lc,a[y].lc,l,mid);
}
il void print(int x,int c) {
if (!x) {
printf("%d\n",c); return;
}
print(pre[x],c+1);
printf("%d ",x);
if (!c) puts("");
}
void main() {
ecnt = cnt = tp = 0; n = read(); m = read();
rep(i,1,n) head[i] = rt[i] = 0;
rep(i,1,m) {
int u = read(),v = read(),w = read();
add(u,v,w); add(v,u,w);
}
Dij(1); rep(i,1,n) p[i] = mp(dis[i],i);
sort(p+1,p+n+1);
rep(i,1,n) {
int u = p[i].se;
grep(i,u) if (dis[u]+e[i].w == dis[v]) {
int x; upd(x,rt[u],1,n,e[i].w);
if (!rt[v] || qry(x,rt[v],1,n)) {
del(rt[v],1,n,pos[v]); rt[v] = x;
pre[v] = u; pos[v] = e[i].w;
}
else {
del(x,1,n,e[i].w);
}
}
}
print(n,0);
}
}
int main() {
qiqi::init(1e5); int T = read(); while (T--) qiqi::main(); return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 12156kb
input:
2 4 6 1 2 1 1 3 2 2 3 1 2 4 2 3 4 1 1 4 4 6 11 1 2 9 2 3 12 3 4 3 4 5 5 5 6 10 6 1 22 2 4 9 3 6 1 4 6 5 2 5 2 3 5 8
output:
3 1 2 4 5 1 2 5 3 6
result:
ok correct (2 test cases)
Test #2:
score: -100
Wrong Answer
time: 132ms
memory: 12384kb
input:
600 320 1547 204 81 13768 232 97 9939 97 249 3719 201 109 14322 183 132 40881 142 143 1 275 186 24548 18 236 7907 30 317 11845 131 130 1 311 300 11704 141 92 41925 174 191 32128 119 120 1 184 183 1 310 309 1 283 270 25477 233 141 36076 212 92 13770 307 110 40656 218 137 14033 180 85 41892 200 199 44...
output:
184 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 89 90 91 92 93 94 95 96 97 98 99 100 101 102 10...
result:
wrong answer Contestant's path is not optimal lexicographically (test case 3)