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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#778223#9570. Binary TreeLanthanmumTL 1ms3624kbC++202.4kb2024-11-24 13:26:192024-11-24 13:26:19

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你现在查看的是最新测评结果

  • [2024-11-24 13:26:19]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:3624kb
  • [2024-11-24 13:26:19]
  • 提交

answer

#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;
typedef pair<int, int> pii;
typedef vector<int> vi;
const int N = 1e5 + 9;
int mxs, sum, n,rt;
int flag;
int del[N], sz[N];
vector<int> e[N];

auto ask(int u, int v) {
	cout << "?" << " " << u << " " << v << endl;
	int x;
	cin >> x;
	return x;
};

auto ok(int x) {
	cout << "!" << " " << x << endl;
};

void add(int u, int v) {
	e[u].push_back(v);
	e[v].push_back(u);
}

void getroot(int u, int f,int &rt) {
	sz[u]=1;
	int s = 0;
	for (auto &i : e[u]) {
		if (i == f || del[i]) {
			continue;
		}
		getroot(i, u,rt);
		sz[u] += sz[i];
		s = max(s, sz[i]);
	}
	s = max(s, sum - sz[u]);
	if (s < mxs) {
		mxs = s;
		rt = u;
	}
	
}
int getsize(int u,int f){
	if(del[u])return 0;
	int res=1;
	for(auto & i :  e[u]){
		if(i==f)continue;
		res+=getsize(i,u);
	}
	return res;
}
int getmxs(int u,int f){
	if(del[u])return 0;
	int res=0;
	for(auto & i : e[u]){
		if(i==f)continue;
		res=max(res,getsize(i,u));
	}
	res=max(res,sum-res);
	return res;
}
void dfs(int u) {
	if (flag) {
		return;
	}
	if (del[u]) {
		return;
	}
	sum=getsize(u,0);
	mxs=getmxs(u,0);
	getroot(u,0,u);
	vi t;
	for (auto &i : e[u]) {
		if (!del[i]) {
			t.push_back(i);
		}
	}
	int SZ = t.size();
	if (!SZ) {
		ok(u);
	} else if (SZ == 1) {
		int x = ask(u, t[0]);
		if (!x) {
			ok(u);
		} else {
			ok(t[0]);
		}
	} else if (SZ == 2) {
		int x = ask(t[0], t[1]);
		if (x == 1) {
			ok(u);
		}else if(x == 0) {
			del[u]=1;
			dfs(t[0]);
			return;
		}else{
			del[u]=1;
			dfs(t[1]);
		}
	} else {
		vector<pii> v;
		for(int i=0;i<3;i++){
			v.push_back({t[i],getsize(t[i],u)});
		}
		sort(v.begin(),v.end(),[](const pii &a,const pii &b){
			return a.second>b.second;
		});
		vi tt;
		for(auto &[x,y] : v){
			tt.push_back(x);
		}
		int x=ask(tt[0],tt[1]);
		if(!x){
			del[u]=1;
			dfs(tt[0]);
		}else if(x==1){
			del[tt[0]]=del[tt[1]]=1;
			dfs(rt);
		}else{
			del[u]=1;
			dfs(tt[1]);	
		}
	}
	return;
}

void solve() {
	cin >> n;
	for(int i=1;i<=n;i++){
		e[i].clear();
		sz[i]=0,del[i]=0;
	}
	for (int i = 1; i <= n; i++) {
		int u, v;
		cin >> u >> v;
		if (u) {
			add(u, i);
		}
		if (v) {
			add(v, i);
		}
	}
	mxs = n, sum = n;
	getroot(1,0,rt);
	dfs(rt);
};

int main() {
	int t;
	cin >> t;
	while (t--) {
		flag = 0;
		solve();
	}
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 3624kb

input:

2
5
0 0
1 5
2 4
0 0
0 0
1
0
2
0 2
0 0
2

output:

? 3 1
? 2 5
! 2
? 2 1
! 1

result:

ok OK (2 test cases)

Test #2:

score: -100
Time Limit Exceeded

input:

5555
8
2 0
8 6
0 0
3 0
0 0
7 0
0 0
5 4
0
2
0
8
0 0
1 4
2 0
0 0
7 8
0 0
3 0
6 0
2
1

output:

? 2 4
? 1 6
? 6 7
! 6
? 5 3
? 1 4

result: