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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#777180#9570. Binary TreeLanthanmumRE 1ms3492kbC++203.1kb2024-11-23 23:21:562024-11-23 23:21:58

Judging History

你现在查看的是最新测评结果

  • [2024-11-23 23:21:58]
  • 评测
  • 测评结果:RE
  • 用时:1ms
  • 内存:3492kb
  • [2024-11-23 23:21:56]
  • 提交

answer

#include <iostream>
#include <algorithm>
#include <array>
#include <vector>
using namespace std;
typedef pair<int, int> pii;
typedef vector<int> vi;
const int N = 1e5 + 9;
int mxs, sum, rt, n;
int flag;
int del[N], sz[N];
vector<int> e[N];

auto ask(int u, int v) {
    cout << "?" << " " << u << " " << v << endl;
    int x;
    cin >> x;
    return x;
};

auto ok(int x) {
    cout << "!" << " " << x << endl;
};

void add(int u, int v) {
    e[u].push_back(v);
    e[v].push_back(u);
}
int get_size(int u,int f){
    if(del[u]){
        return 0;
    }
    int res=1;
    for(auto & i : e[u]){
        if(i==f)continue;
        res+=get_size(i,u);
    }
    return res;
}
void getroot(int u, int f) {
    if (del[u]) {
        sz[u] = 0;
    } else {
        sz[u] = 1;
    }
    int s = 0;
    for (auto &i : e[u]) {
        if (i == f || del[i]) {
            continue;
        }
        getroot(i, u);
        sz[u] += sz[i];
        s = max(s, sz[i]);
    }
    s = max(s, sum - sz[u]);
    if (s < mxs) {
        mxs = s;
        rt = u;
    }
}

void dfs(int rt) {
    if (flag) {
        return;
    }
    if (del[rt]) {
        return;
    }
    vi t;
    for (auto &i : e[rt]) {
        if (!del[i]) {
            t.push_back(i);
        }
    }
    int SZ = t.size();
    if (!SZ) {
        ok(rt);
        flag = 1;
        return;
    } else if (SZ == 1) {
        int x = ask(rt, t[0]);
        if (!x) {
            ok(rt);
            flag = 1;
            return;
        } else {
            ok(t[0]);
            flag=1;
            return;
        }
    } else if (SZ == 2) {
        int x = ask(t[0], t[1]);
        if (x == 1) {
            ok(rt);
            flag = 1;
            return;
        }
        del[rt] = 1;
        if (!x) {
            dfs(t[0]);
            return;
        }
        dfs(t[1]);
        return;
    } else {
        vi szz(3);
        vector<pii> tt;
        for(int i=0;i<3;i++){
            tt.push_back({t[i],get_size(t[i],rt)});
        }
        sort(tt.begin(),tt.end(),[&](const pii &x,const pii &y){
            return x.second>y.second;
        });
        vi ttt;
        for(auto &[x,y] : tt){
            ttt.push_back(x);
        }
        int x = ask(ttt[0], ttt[1]);
        if (x == 0) {
            del[rt] = 1;
            dfs(ttt[0]);
            return;
        } else if (x == 1) {
            del[ttt[0]] = del[ttt[1]] = 1;
            dfs(rt);
            return;
        } else {
            del[rt] = 1;
            dfs(ttt[1]);
            return;
        }
    }
}

void solve() {
    cin >> n;
    for(int i=1;i<=n;i++){
        e[i].clear();
        sz[i]=0,del[i]=0;
    }
    for (int i = 1; i <= n; i++) {
        int u, v;
        cin >> u >> v;
        if (u) {
            add(u, i);
        }
        if (v) {
            add(v, i);
        }
    }
    mxs = n, sum = n;
    getroot(1,0);
    dfs(rt);
};

int main() {
    int t;
    cin >> t;
    while (t--) {
        flag = 0;
        solve();
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3492kb

input:

2
5
0 0
1 5
2 4
0 0
0 0
1
0
2
0 2
0 0
2

output:

? 3 1
? 2 5
! 2
? 2 1
! 1

result:

ok OK (2 test cases)

Test #2:

score: -100
Runtime Error

input:

5555
8
2 0
8 6
0 0
3 0
0 0
7 0
0 0
5 4
0
2
0
8
0 0
1 4
2 0
0 0
7 8
0 0
3 0
6 0
2
2

output:

? 2 4
? 1 6
? 6 7
! 6
? 5 3
? 3 2
! 2

result: