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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#77655 | #5507. Investors | XKError | WA | 2ms | 3632kb | C++ | 2.3kb | 2023-02-15 11:37:54 | 2023-02-15 11:37:55 |
Judging History
answer
#include <bits/stdc++.h>
#define maxn 6005
#define ll long long
using namespace std;
int n, k;
int a[maxn];
int b[maxn];
ll f[maxn];
int g[maxn];
int t1[maxn];
int t2[maxn];
void add(int t[], int x, int k) {
for (; x <= n; x += x & -x) t[x] += k;
}
int qry(int t[], int l, int r) {
int res = 0;
for (int x = l - 1; x; x -= x & -x) res -= t[x];
for (int x = r; x; x -= x & -x) res += t[x];
return res;
}
int vl;
int pl, pr;
void moveto(int ql, int qr) {
while (pl > ql) {
--pl;
add(t1, a[pl], 1);
vl += qry(t2, 1, a[pl] - 1);
}
while (pr < qr) {
add(t2, a[pr], -1);
vl -= qry(t1, a[pr] + 1, n);
add(t1, a[pr], 1);
vl += qry(t2, 1, a[pr] - 1);
++pr;
}
while (pl < ql) {
add(t1, a[pl], -1);
vl -= qry(t2, 1, a[pl] - 1);
++pl;
}
while (pr > qr) {
--pr;
add(t1, a[pr], -1);
vl -= qry(t2, 1, a[pr] - 1);
add(t2, a[pr], 1);
vl += qry(t1, a[pr] + 1, n);
}
// cout<<pl<<" "<<pr<<" "<<vl<<endl;
// assert(vl >= 0 && pl <= pr);
}
pair<ll, int> check(ll x) {
f[n] = 0;
for (int i = n - 1; i; i--) {
f[i] = -1e18;
for (int j = i + 1; j <= n; j++) {
moveto(i, j);
if (f[i] < f[j] + vl - x) {
f[i] = f[j] + vl - x;
g[i] = g[j] + 1;
}
}
}
// cout<<x<<" "<<f[1]<<" "<<g[1]<<endl;
return {f[1], g[1]};
}
int main() {
// freopen("dt.in", "r", stdin);
// freopen("dt.out", "w", stdout);
int T;
scanf("%d", &T);
// int T = 1;
while (T--) {
memset(t1, 0, sizeof t1);
memset(t2, 0, sizeof t2);
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; i++) scanf("%d", &a[i]), b[i] = a[i];
if (k >= n - 1) {
puts("0");
continue;
}
sort(b + 1, b + n + 1);
int tot = unique(b + 1, b + n + 1) - b - 1;
for (int i = 1; i <= n; i++) a[i] = lower_bound(b + 1, b + tot + 1, a[i]) - b;
pl = pr = n + 1;
vl = 0;
ll l = 0, r = 1e18, mid;
while (l < r) {
mid = (l + r) >> 1;
if (check(mid).second <= k) r = mid;
else l = mid + 1;
}
auto res = check(l);
// cout<<l<<" "<<res.first<<" "<<res.second<<endl;
ll ans = res.first + l * res.second;
// printf("%lld\n", ans);
memset(t1, 0, sizeof t1);
for (int i = 1; i <= n; i++) {
ans -= qry(t1, a[i] + 1, n);
add(t1, a[i], 1);
}
printf("%lld\n", -ans);
}
return 0;
}
/*
2
6 1
4 5 6 2 2 1
6 2
4 5 6 2 2 1
*/
詳細信息
Test #1:
score: 0
Wrong Answer
time: 2ms
memory: 3632kb
input:
2 6 1 4 5 6 2 2 1 6 2 4 5 6 2 2 1
output:
6 0
result:
wrong answer 1st lines differ - expected: '2', found: '6'