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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#776032#9788. Shrecklessucup-team159#WA 26ms3728kbC++204.4kb2024-11-23 17:22:142024-11-23 17:22:14

Judging History

你现在查看的是最新测评结果

  • [2024-11-23 17:22:14]
  • 评测
  • 测评结果:WA
  • 用时:26ms
  • 内存:3728kb
  • [2024-11-23 17:22:14]
  • 提交

answer

#include <bits/stdc++.h>
#define rep(i,n) for(int i = 0; i < (n); ++i)
#define rep1(i,n) for(int i = 1; i <= (n); ++i)
#define drep(i,n) for(int i = (n)-1; i >= 0; --i)
#define srep(i,s,t) for (int i = s; i < (t); ++i)
#define rng(a) a.begin(),a.end()
#define rrng(a) a.rbegin(),a.rend()
#define fi first
#define se second
#define pb push_back
#define eb emplace_back
#define em emplace
#define pob pop_back
#define sz(x) (int)(x).size()
#define pcnt __builtin_popcountll
#define snuke srand((unsigned)clock()+(unsigned)time(NULL));
#define newline puts("")
#define vc vector
using namespace std;
template<class T> using vv = vc<vc<T>>;
template<class T> using PQ = priority_queue<T,vc<T>,greater<T>>;
using uint = unsigned; using ull = unsigned long long;
using vi = vc<int>; using vvi = vv<int>; using vvvi = vv<vi>;
using ll = long long; using vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>;
using P = pair<int,int>; using vp = vc<P>; using vvp = vv<P>; using LP = pair<ll,ll>;
int geti(){int x;scanf("%d",&x);return x;}
vi pm(int n, int s=0) { vi a(n); iota(rng(a),s); return a;}
template<class T1,class T2>istream& operator>>(istream&i,pair<T1,T2>&v){return i>>v.fi>>v.se;}
template<class T1,class T2>ostream& operator<<(ostream&o,const pair<T1,T2>&v){return o<<v.fi<<","<<v.se;}
template<class T>istream& operator>>(istream&i,vc<T>&v){rep(j,sz(v))i>>v[j];return i;}
template<class T>string join(const T&v,const string&d=""){stringstream s;rep(i,sz(v))(i?s<<d:s)<<v[i];return s.str();}
template<class T>ostream& operator<<(ostream&o,const vc<T>&v){if(sz(v))o<<join(v," ");return o;}
template<class T>void vin(vc<T>&a){int n;cin>>n;a=vc<T>(n);cin>>a;}
template<class T>void vin(vv<T>&a){int n,m;cin>>n>>m;a=vv<T>(n,vc<T>(m));cin>>a;}
template<class T1,class T2>void operator--(pair<T1,T2>&a,int){a.fi--;a.se--;}
template<class T1,class T2>void operator++(pair<T1,T2>&a,int){a.fi++;a.se++;}
template<class T>void operator--(vc<T>&a,int){for(T&x:a)x--;}
template<class T>void operator++(vc<T>&a,int){for(T&x:a)x++;}
template<class T1,class T2>void operator+=(vc<T1>&a,T2 b){for(T1&x:a)x+=b;}
template<class T1,class T2>void operator-=(vc<T1>&a,T2 b){for(T1&x:a)x-=b;}
template<class T1,class T2>void operator*=(vc<T1>&a,T2 b){for(T1&x:a)x*=b;}
template<class T1,class T2>void operator/=(vc<T1>&a,T2 b){for(T1&x:a)x/=b;}
template<class T>void operator+=(vc<T>&a,const vc<T>&b){a.insert(a.end(),rng(b));}
template<class T1,class T2>pair<T1,T2>operator+(const pair<T1,T2>&a,const pair<T1,T2>&b){return {a.fi+b.fi,a.se+b.se};}
template<class T1,class T2>pair<T1,T2>operator-(const pair<T1,T2>&a,const pair<T1,T2>&b){return {a.fi-b.fi,a.se-b.se};}
template<class T>pair<T,T>operator*(const pair<T,T>&a,T b){return {a.fi*b,a.se*b};}
template<class T1,class T2>bool mins(T1& x,const T2&y){if(y<x){x=y;return true;}else return false;}
template<class T1,class T2>bool maxs(T1& x,const T2&y){if(x<y){x=y;return true;}else return false;}
template<class T>T min(const vc<T>&a){return *min_element(rng(a));}
template<class T>T max(const vc<T>&a){return *max_element(rng(a));}
template<class Tx,class Ty>Tx dup(Tx x, Ty y){return (x+y-1)/y;}
template<class T>ll suma(const vc<T>&a){ll s=0;for(auto&&x:a)s+=x;return s;}
template<class T>ll suma(const vv<T>&a){ll s=0;for(auto&&x:a)s+=suma(x);return s;}
template<class T>void uni(T&a){sort(rng(a));a.erase(unique(rng(a)),a.end());}
template<class T>void prepend(vc<T>&a,const T&x){a.insert(a.begin(),x);}
const double eps = 1e-10;
const ll LINF = 1001002003004005006ll;
const int INF = 1001001001;
#define dame { puts("-1"); return;}
#define yes { puts("YES"); return;}
#define no { puts("NO"); return;}
#define rtn(x) { cout<<(x)<<'\n'; return;} // flush!
#define yn {puts("YES");}else{puts("NO");}

struct Solver {
  void solve() {
    int h,w;
    scanf("%d%d",&h,&w);
    vvi a(w,vi(h));
    rep(i,h)rep(j,w) cin>>a[j][i];
    rep(j,w) sort(rrng(a[j]));
    int cnt = 0;

    rep(j,w-1) {
      vi& b = a[j];
      vi& c = a[j+1];
      int ci = 0;
      rep(bi,h) {
        if (b[bi] == -1) continue;
        while (ci < h && (c[ci] == -1 || c[ci] >= b[bi])) ci++;
        if (ci < h) {
          b[bi] = -1;
          c[ci] = -1;
          cnt++;
        }
      }
    }
    if (cnt >= h) yn;
  }
};

int main() {
  // cin.tie(nullptr); ios::sync_with_stdio(false);
  int ts = 1;
  scanf("%d",&ts);
  rep1(ti,ts) {
    Solver solver;
    solver.solve();
  }
  return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3728kb

input:

3
2 2
69 69
2024 42
3 3
1 1 1
1 1 1
2 2 2
3 4
1 1 1 1
1 1 1 1
2 2 2 2

output:

YES
NO
YES

result:

ok 3 token(s): yes count is 2, no count is 1

Test #2:

score: 0
Accepted
time: 0ms
memory: 3632kb

input:

3
2 2
69 69
2024 42
3 3
1 1 1
1 1 1
2 2 2
3 4
1 1 1 1
1 1 1 1
2 2 2 2

output:

YES
NO
YES

result:

ok 3 token(s): yes count is 2, no count is 1

Test #3:

score: -100
Wrong Answer
time: 26ms
memory: 3672kb

input:

20000
6 2
12 4
8 24
2 10
1 22
3 15
18 20
3 3
3 8 18
2 17 15
13 4 6
3 3
7 17 15
8 6 3
18 13 9
3 3
2 3 14
1 7 17
4 6 13
3 3
6 10 14
3 9 13
1 7 15
2 4
1 3 16 14
6 10 4 2
3 3
3 2 17
7 11 13
16 5 18
2 3
2 3 6
4 1 5
2 4
4 6 13 14
2 11 12 16
3 3
2 8 12
4 9 17
5 7 18
3 2
5 10
8 9
1 6
2 2
2 4
1 3
2 3
12 6 1
...

output:

NO
NO
YES
NO
NO
YES
YES
YES
NO
NO
NO
NO
YES
YES
YES
YES
NO
NO
YES
NO
NO
NO
YES
NO
YES
YES
YES
YES
YES
NO
NO
YES
NO
YES
NO
NO
YES
NO
YES
YES
NO
NO
YES
NO
YES
NO
NO
YES
YES
YES
NO
NO
NO
YES
YES
YES
NO
NO
NO
YES
NO
NO
YES
NO
NO
NO
YES
YES
YES
YES
NO
NO
YES
NO
NO
NO
NO
NO
YES
YES
YES
NO
NO
YES
YES
NO
NO...

result:

wrong answer expected YES, found NO [2nd token]