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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#77190#5504. Flower Garden18MichaelWA 3521ms106972kbC++144.1kb2023-02-13 09:15:572023-02-13 09:15:59

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-02-13 09:15:59]
  • 评测
  • 测评结果:WA
  • 用时:3521ms
  • 内存:106972kb
  • [2023-02-13 09:15:57]
  • 提交

answer

#pragma GCC optimize("O3")
#pragma GCC target("avx2")
#include<bits/stdc++.h>
#define LL long long
#define inf 0x3f3f3f3f
using namespace std;
const int MxV=1200002,MxE=50000002,MxN=100002,MxQ=100002;
int n,n2,n3,q,t,edge_t,dfn_t,st_t,rt_t,s,s2,cnt,e_t,Test_num;
int a[MxQ],b[MxQ],c[MxQ],d[MxQ],lson[MxV],rson[MxV],val[MxV],la[MxV],num[MxN],dfn[MxV],low[MxV],rt[MxV],st[MxV],sum[MxV],lae[MxV],from[MxE],deg[MxV];
bool ins[MxV],u[MxV];
vector<int> vec;
vector<int> vec2[MxV];
queue<int> Q,ept;
struct aaa
{
	int to,nx;
}edge[MxE],e[MxE];
template<class T>void read(T &x)
{
	x=0;int f=0;char ch=getchar();
	while(ch<'0' || ch>'9')f|=(ch=='-'),ch=getchar();
	while(ch>='0' && ch<='9')x=(x<<3)+(x<<1)+(ch^48),ch=getchar();
	x=f? -x:x;return ;
}
inline void add_edge(int x,int y)
{
	//printf("      ADD %d %d\n",x,y);
	edge[++edge_t]=(aaa){y,la[x]},la[from[edge_t]=x]=edge_t;
}
inline void add_e(int x,int y)
{
	if(x^y)e[++e_t]=(aaa){y,lae[x]},lae[x]=e_t;
}
inline int newnode()
{
	return ++t,la[t]=val[t]=dfn[t]=rt[t]=0,t;
}
inline void build(int k,int l,int r)
{
	//if(l==r)printf("num[%d]=%d\n",l,k);
	if(l==r)return (void)(val[num[l]=k]=1);
	int mid=((l+r)>>1);
	build(lson[k]=newnode(),l,mid),build(rson[k]=newnode(),mid+1,r),add_edge(k,lson[k]),add_edge(k,rson[k]);
}
inline void build2(int k,int l,int r)
{
	if(l==r)return ;
	int mid=((l+r)>>1);
	build2(lson[k]=(l==mid? num[l]:newnode()),l,mid),build2(rson[k]=(mid+1==r? num[r]:newnode()),mid+1,r),add_edge(lson[k],k),add_edge(rson[k],k);
}
inline void add(int k,int l,int r,int l1,int r1,int x)
{
	if(l>=l1 && r<=r1)return add_edge(x,k);
	int mid=((l+r)>>1);
	if(l1<=mid)add(lson[k],l,mid,l1,r1,x);
	if(r1>mid)add(rson[k],mid+1,r,l1,r1,x);
}
inline void add2(int k,int l,int r,int l1,int r1,int x)
{
	if(l>=l1 && r<=r1)return add_edge(k,x);
	int mid=((l+r)>>1);
	if(l1<=mid)add2(lson[k],l,mid,l1,r1,x);
	if(r1>mid)add2(rson[k],mid+1,r,l1,r1,x);
}
inline void Tarjan(int x)
{
	dfn[x]=low[x]=(++dfn_t),ins[st[++st_t]=x]=1;
	for(int i=la[x],v;i;i=edge[i].nx)
	{
		v=edge[i].to;
		if(!dfn[v])Tarjan(v),low[x]=min(low[x],low[v]);
		else if(ins[v])low[x]=min(low[x],dfn[v]);
	}
	if(dfn[x]==low[x])for(sum[++rt_t]=0,vec2[rt_t].clear();st[st_t+1]!=x;--st_t)rt[st[st_t]]=rt_t,sum[rt_t]+=val[st[st_t]],vec2[rt_t].push_back(st[st_t]),ins[st[st_t]]=0;
}
inline void print()
{
	puts("TAK");
	for(int i=1;i<=n3;++i)putchar(u[num[i]]? 'R':'F');
	puts("");
}
inline void solve1()
{
	//cerr<<"solve1\n";
	e_t=0,cnt=n3,Q=ept;
	for(int i=1;i<=t;++i)deg[i]=0;
	for(int i=1;i<=edge_t;++i)add_e(rt[from[i]],rt[edge[i].to]);
	for(int i=1;i<=rt_t;++i)if(!deg[i])Q.push(i),ins[i]=1;else ins[i]=0;
	for(int i=1;i<=t;++i)u[i]=0;
	for(int p;Q.size();)
	{
		p=Q.front(),Q.pop(),cnt-=sum[p];
		//printf("p:%d sum:%d\n",p,sum[p]);
		for(int i=0;i<vec2[p].size();++i)u[vec2[p][i]]=1/*,printf(" u[%d]=1\n",vec2[p][i])*/;
		//for(int i=1;i<=n3;++i)printf("%d%c",u[num[i]],i==n3? '\n':' ');
		if(cnt>=n && cnt<=n2)return print();
		for(int i=0;i<vec2[p].size();++i)for(int i=la[vec2[p][i]],v;i;i=edge[i].nx)if(!(--deg[rt[v=edge[i].to]]) && !ins[rt[v]])Q.push(rt[v]),ins[rt[v]]=1;
	}
}
inline void dfs(int x)
{
	ins[x]=1,cnt+=val[x];
	for(int i=la[x],v;i;i=edge[i].nx)if(!ins[v=edge[i].to])dfs(v);
}
inline void solve2()
{
	//cerr<<"solve2\n";
	for(int i=0;i<vec.size();++i)
	{
		for(int j=1;j<=t;++j)ins[j]=0;
		cnt=0,dfs(vec2[vec[i]][0]);
		if(cnt>=n && cnt<=n2)
		{
			for(int j=1;j<=n3;++j)u[j]=ins[num[j]];
			return print();
		}
	}
	puts("NIE");
}
inline void solve()
{
	read(n),read(q),n2=(n<<1),n3=n*3,edge_t=dfn_t=rt_t=t=0,vec.clear(),build(s=newnode(),1,n3),build2(s2=newnode(),1,n3);
	for(int i=1;i<=q;++i)read(a[i]),read(b[i]),read(c[i]),read(d[i]),add(s,1,n3,a[i],b[i],newnode()),add2(s2,1,n3,c[i],d[i],t);
	for(int i=1;i<=t;++i)if(!dfn[i])Tarjan(i);
	/*for(int i=1;i<=rt_t;++i)
	{
		printf(" %d:",i);
		for(int j=0;j<vec2[i].size();++j)printf("%d%c",vec2[i][j],j+1==vec2[i].size()? '\n':' ');
	}*/
	for(int i=1;i<=rt_t;++i)if(sum[i]>n)vec.push_back(i);
	if(!vec.size())solve1();
	else solve2();
}
int main()
{
	read(Test_num);
	while(Test_num--)solve();
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 8ms
memory: 33344kb

input:

2
1 3
1 1 2 2
1 2 3 3
1 1 3 3
1 3
1 1 2 2
2 2 3 3
3 3 1 1

output:

TAK
RFF
NIE

result:

ok good!

Test #2:

score: 0
Accepted
time: 3521ms
memory: 106972kb

input:

10
33333 100000
28701 40192 93418 95143
95902 97908 78378 78461
36823 44196 22268 23996
23977 24786 33315 48829
83965 90411 4923 8445
20235 21177 32543 47454
29598 35414 72477 73049
2014 12632 42163 46466
64305 65518 98825 99552
32331 41625 92772 96224
26500 54122 76990 77126
18249 20335 31165 36080...

output:

NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE

result:

ok good!

Test #3:

score: -100
Wrong Answer
time: 1929ms
memory: 86016kb

input:

10
33333 100000
15207 33614 66276 66276
97173 97173 67589 73960
19673 36626 65207 65207
89825 98169 27079 27079
56067 56966 7560 7560
18170 35477 18752 18752
32621 36748 34460 34460
61595 61700 14117 14117
32395 36710 9064 9064
13172 13172 1728 4640
40462 41878 47171 47171
76965 82414 5767 5767
9225...

output:

NIE
TAK
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR...

result:

wrong answer zla odpowiedz!