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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#77186#5504. Flower Garden18MichaelWA 3120ms120620kbC++143.8kb2023-02-13 08:50:112023-02-13 08:50:29

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-02-13 08:50:29]
  • 评测
  • 测评结果:WA
  • 用时:3120ms
  • 内存:120620kb
  • [2023-02-13 08:50:11]
  • 提交

answer

#pragma GCC optimize("O3")
#pragma GCC target("avx2")
#include<bits/stdc++.h>
#define LL long long
#define inf 0x3f3f3f3f
using namespace std;
const int MxV=1200002,MxE=50000002,MxN=100002,MxQ=100002;
int n,n2,n3,q,t,edge_t,dfn_t,st_t,rt_t,cnt,e_t,Test_num;
int a[MxQ],b[MxQ],c[MxQ],d[MxQ],val[MxV],la[MxV],num[MxN],dfn[MxV],low[MxV],rt[MxV],st[MxV],sum[MxV],lae[MxV],from[MxE],deg[MxV];
bool ins[MxV],u[MxV];
vector<int> vec;
vector<int> vec2[MxV];
queue<int> Q,ept;
struct aaa
{
	int to,nx;
}edge[MxE],e[MxE];
template<class T>void read(T &x)
{
	x=0;int f=0;char ch=getchar();
	while(ch<'0' || ch>'9')f|=(ch=='-'),ch=getchar();
	while(ch>='0' && ch<='9')x=(x<<3)+(x<<1)+(ch^48),ch=getchar();
	x=f? -x:x;return ;
}
inline void add_edge(int x,int y)
{
	//printf("      ADD %d %d\n",x,y);
	edge[++edge_t]=(aaa){y,la[x]},la[from[edge_t]=x]=edge_t;
}
inline void add_e(int x,int y)
{
	if(x^y)e[++e_t]=(aaa){y,lae[x]},lae[x]=e_t;
}
inline int newnode()
{
	return ++t,la[t]=val[t]=dfn[t]=rt[t]=0,t;
}
inline int lson(int x)
{
	return (x<<1);
}
inline int rson(int x)
{
	return ((x<<1)|1);
}
inline void build(int k,int l,int r)
{
	//if(l==r)printf("num[%d]=%d\n",l,k);
	if(l==r)return (void)(val[num[l]=k]=1);
	int mid=((l+r)>>1),ls=lson(k),rs=rson(k);
	build(ls,l,mid),build(rs,mid+1,r),add_edge(k,ls),add_edge(k,rs);
}
inline void build2(int k,int l,int r)
{
	if(l==r)return ;
	int mid=((l+r)>>1),ls=lson(k),rs=rson(k);
	build2(ls,l,mid),build2(rs,mid+1,r),add_edge(k,ls),add_edge(k,rs);
}
inline void add(int k,int l,int r,int l1,int r1,int x)
{
	if(l>=l1 && r<=r1)return add_edge(x,k);
	int mid=((l+r)>>1),ls=lson(k),rs=rson(k);
	if(l1<=mid)add(ls,l,mid,l1,r1,x);
	if(r1>mid)add(rs,mid+1,r,l1,r1,x);
}
inline void add2(int k,int l,int r,int l1,int r1,int x)
{
	if(l>=l1 && r<=r1)return add_edge(k,x);
	int mid=((l+r)>>1),ls=lson(k),rs=rson(k);
	if(l1<=mid)add2(ls,l,mid,l1,r1,x);
	if(r1>mid)add2(rs,mid+1,r,l1,r1,x);
}
inline void Tarjan(int x)
{
	dfn[x]=low[x]=(++dfn_t),ins[st[++st_t]=x]=1;
	for(int i=la[x],v;i;i=edge[i].nx)
	{
		v=edge[i].to;
		if(!dfn[v])Tarjan(v),low[x]=min(low[x],low[v]);
		else if(ins[v])low[x]=min(low[x],dfn[v]);
	}
	if(x==low[x])for(sum[++rt_t]=0,vec2[rt_t].clear();st[st_t+1]!=x;--st_t)rt[st[st_t]]=rt_t,sum[rt_t]+=val[st[st_t]],vec2[rt_t].push_back(st[st_t]);
}
inline void print()
{
	puts("TAK");
	for(int i=1;i<=n3;++i)putchar(u[num[i]]? 'R':'F');
	puts("");
}
inline void solve1()
{
	//cerr<<"solve1\n";
	e_t=cnt=0,Q=ept;
	for(int i=1;i<=t;++i)deg[i]=0;
	for(int i=1;i<=edge_t;++i)add_e(rt[from[i]],rt[edge[i].to]);
	for(int i=1;i<=rt_t;++i)if(!deg[i])Q.push(i),ins[i]=1;else ins[i]=0;
	for(int i=1;i<=n3;++i)u[i]=1;
	for(int p;Q.size();)
	{
		p=Q.front(),cnt+=sum[p];
		for(int i=0;i<vec2[p].size();++i)u[vec2[p][i]]=1;
		if(cnt>=n && cnt<=n2)return print();
		for(int i=0;i<vec2[p].size();++i)for(int i=la[vec2[p][i]],v;i;i=edge[i].nx)if(!(--deg[rt[v=edge[i].to]]) && !ins[rt[v]])Q.push(rt[v]),ins[rt[v]]=1;
	}
}
inline void dfs(int x)
{
	u[x]=1,cnt+=sum[x];
	for(int i=la[x],v;i;i=edge[i].nx)if(!u[v=edge[i].to])dfs(v);
}
inline void solve2()
{
	//cerr<<"solve2\n";
	for(int i=0;i<vec.size();++i)
	{
		for(int j=1;j<=t;++j)u[j]=0;
		cnt=0,dfs(vec[i]);
		if(cnt>=n && cnt<=n2)return print();
	}
	puts("NIE");
}
inline void solve()
{
	for(read(n),read(q),n2=(n<<1),n3=n*3,edge_t=dfn_t=rt_t=t=0,vec.clear();t<=(n3<<2);newnode());
	build(1,1,n3),build2(1,1,n3);
	for(int i=1;i<=q;++i)read(a[i]),read(b[i]),read(c[i]),read(d[i]),add(1,1,n3,a[i],b[i],newnode()),add2(1,1,n3,c[i],d[i],t);
	for(int i=1;i<=t;++i)if(!dfn[i])Tarjan(i);
	for(int i=1;i<=rt_t;++i)if(sum[i]>n)vec.push_back(i);
	if(!vec.size())solve1();
	else solve2();
}
int main()
{
	read(Test_num);
	while(Test_num--)solve();
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 11ms
memory: 31532kb

input:

2
1 3
1 1 2 2
1 2 3 3
1 1 3 3
1 3
1 1 2 2
2 2 3 3
3 3 1 1

output:

TAK
RRF
NIE

result:

ok good!

Test #2:

score: -100
Wrong Answer
time: 3120ms
memory: 120620kb

input:

10
33333 100000
28701 40192 93418 95143
95902 97908 78378 78461
36823 44196 22268 23996
23977 24786 33315 48829
83965 90411 4923 8445
20235 21177 32543 47454
29598 35414 72477 73049
2014 12632 42163 46466
64305 65518 98825 99552
32331 41625 92772 96224
26500 54122 76990 77126
18249 20335 31165 36080...

output:

NIE
NIE
NIE
NIE
NIE
NIE
TAK
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR...

result:

wrong answer zla odpowiedz!