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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#77161 | #5507. Investors | UCSC_Ravioli# | WA | 4ms | 3364kb | C++20 | 2.6kb | 2023-02-13 06:59:27 | 2023-02-13 06:59:28 |
Judging History
answer
// qdd on Feb 12, 2023
#ifdef qdd
#include <ringo>
#else
#include <bits/stdc++.h>
#define dbg(...)
#define dbgr(x, y)
#endif
using namespace std;
using ll = long long;
#define ALL(x) begin(x), end(x)
template <class T>
istream& operator>>(istream& is, vector<T>& v) {
for (T& x : v) is >> x;
return is;
}
template <class T>
ostream& operator<<(ostream& os, const vector<T>& v) {
bool f = 0;
for (const T& x : v) (f ? os << ' ' : os) << x, f = 1;
return os;
}
// repeating elements with same id
template <class T>
vector<int> unique_dc(const vector<T>& a, int start_id) {
int n = a.size();
vector<T> t(a);
sort(t.begin(), t.end());
t.resize(unique(t.begin(), t.end()) - t.begin());
vector<int> id(n);
for (int i = 0; i < n; i++) {
id[i] = start_id + lower_bound(t.begin(), t.end(), a[i]) - t.begin();
}
return id;
}
struct fenwick {
int n;
vector<int> t;
fenwick(int n) : n(n), t(n + 1) {}
void add(int p, int x) {
for (; p <= n; p += p & -p) t[p] += x;
}
int get(int p) {
int a = 0;
for (; p > 0; p -= p & -p) a += t[p];
return a;
}
};
void sol() {
int n, k;
cin >> n >> k;
vector<int> a(n);
cin >> a;
a = unique_dc(a, 1);
int mx = *max_element(ALL(a));
// inv between [0, i-1] and [i,n-1]
vector<int> inv(n + 1);
auto build_inverse = [&](int l, int r) {
if (r - l < 5) {
for (int k = l; k <= r; k++) {
inv[k] = 0;
for (int i = l; i < k; i++) {
for (int j = k; j <= r; j++) {
if (a[i] > a[j]) inv[k]++;
}
}
}
return;
}
fenwick L(mx), R(mx);
for (int i = l; i <= r; i++) {
R.add(a[i], 1);
}
inv[l] = 0;
for (int i = l + 1; i <= r; i++) {
R.add(a[i - 1], -1);
inv[i] = inv[i - 1] + R.get(a[i - 1] - 1) - (L.get(mx) - L.get(a[i - 1]));
L.add(a[i - 1], 1);
}
inv[r + 1] = 0;
};
build_inverse(0, n - 1);
auto global_inverse = [&]() {
fenwick t(mx);
int res = 0;
for (int i = 0; i < n; i++) {
res += t.get(mx) - t.get(a[i]);
t.add(a[i], 1);
}
return res;
};
int ans = global_inverse();
for (int i = 0; i < k; i++) {
int p = max_element(ALL(inv)) - inv.begin();
ans -= inv[p];
int l = p - 1, r = p;
while (inv[l] > 0) l--;
while (inv[r] > 0) r++;
build_inverse(l, p - 1);
build_inverse(p, r - 1);
}
cout << ans << '\n';
}
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
int T;
cin >> T;
while (T--) {
sol();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 2ms
memory: 3364kb
input:
2 6 1 4 5 6 2 2 1 6 2 4 5 6 2 2 1
output:
2 0
result:
ok 2 lines
Test #2:
score: -100
Wrong Answer
time: 4ms
memory: 3336kb
input:
349 6 2 2 1 2 1 2 1 48 12 42 47 39 39 27 25 22 44 45 13 5 48 38 4 37 6 24 10 42 38 12 37 31 19 44 6 29 17 7 12 7 26 35 24 15 9 37 3 27 21 33 29 34 20 14 30 31 21 48 12 1 43 17 46 17 39 40 22 25 2 22 12 4 11 38 12 4 11 1 5 39 44 37 10 19 20 42 45 2 45 37 20 48 34 16 41 23 18 13 44 47 21 29 4 23 18 16...
output:
1 18 15 145 0 2 1 0 14 13 24 0 0 0 1 0 0 0 0 0 0 0 0 161 3 0 0 1 0 0 0 0 0 0 1 0 3 0 0 1 0 0 1 0 0 1 4 0 0 0 0 0 0 0 0 2 0 2 0 0 8 280 0 0 35 4 0 1 0 0 3 0 0 0 0 0 0 0 4 0 0 0 0 0 0 0 0 0 0 0 0 0 3 0 0 0 2 0 0 0 0 0 0 0 8 1 9 0 0 0 0 1 12 5 0 0 0 7 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 14 1 0 0 0 ...
result:
wrong answer 9th lines differ - expected: '13', found: '14'