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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#76770#5503. Euclidean Algorithmheno239ML 0ms0kbC++177.2kb2023-02-12 10:13:172023-02-12 10:13:19

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-02-12 10:13:19]
  • 评测
  • 测评结果:ML
  • 用时:0ms
  • 内存:0kb
  • [2023-02-12 10:13:17]
  • 提交

answer

#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<unordered_set>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
#include<array>
#include<chrono>
using namespace std;

//#define int long long
typedef long long ll;

typedef unsigned long long ul;
typedef unsigned int ui;
constexpr ll mod = 998244353;
//constexpr ll mod = 1000000007;
const ll INF = mod * mod;
typedef pair<int, int>P;

#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;

template<typename T>
void chmin(T& a, T b) {
	a = min(a, b);
}
template<typename T>
void chmax(T& a, T b) {
	a = max(a, b);
}
template<typename T>
void cinarray(vector<T>& v) {
	rep(i, v.size())cin >> v[i];
}
template<typename T>
void coutarray(vector<T>& v) {
	rep(i, v.size()) {
		if (i > 0)cout << " "; cout << v[i];
	}
	cout << "\n";
}
ll mod_pow(ll x, ll n, ll m = mod) {
	if (n < 0) {
		ll res = mod_pow(x, -n, m);
		return mod_pow(res, m - 2, m);
	}
	if (abs(x) >= m)x %= m;
	if (x < 0)x += m;
	//if (x == 0)return 0;
	ll res = 1;
	while (n) {
		if (n & 1)res = res * x % m;
		x = x * x % m; n >>= 1;
	}
	return res;
}
//mod should be <2^31
struct modint {
	int n;
	modint() :n(0) { ; }
	modint(ll m) {
		if (m < 0 || mod <= m) {
			m %= mod; if (m < 0)m += mod;
		}
		n = m;
	}
	operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
bool operator<(modint a, modint b) { return a.n < b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= (int)mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += (int)mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
	if (n == 0)return modint(1);
	modint res = (a * a) ^ (n / 2);
	if (n % 2)res = res * a;
	return res;
}

ll inv(ll a, ll p) {
	return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
modint operator/=(modint& a, modint b) { a = a / b; return a; }
const int max_n = 1 << 2;
modint fact[max_n], factinv[max_n];
void init_f() {
	fact[0] = modint(1);
	for (int i = 0; i < max_n - 1; i++) {
		fact[i + 1] = fact[i] * modint(i + 1);
	}
	factinv[max_n - 1] = modint(1) / fact[max_n - 1];
	for (int i = max_n - 2; i >= 0; i--) {
		factinv[i] = factinv[i + 1] * modint(i + 1);
	}
}
modint comb(int a, int b) {
	if (a < 0 || b < 0 || a < b)return 0;
	return fact[a] * factinv[b] * factinv[a - b];
}
modint combP(int a, int b) {
	if (a < 0 || b < 0 || a < b)return 0;
	return fact[a] * factinv[a - b];
}

ll gcd(ll a, ll b) {
	a = abs(a); b = abs(b);
	if (a < b)swap(a, b);
	while (b) {
		ll r = a % b; a = b; b = r;
	}
	return a;
}
using ld = long double;
//typedef long double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-10;
const ld pi = acosl(-1.0);
template<typename T>
void addv(vector<T>& v, int loc, T val) {
	if (loc >= v.size())v.resize(loc + 1, 0);
	v[loc] += val;
}
/*const int mn = 2000005;
bool isp[mn];
vector<int> ps;
void init() {
	fill(isp + 2, isp + mn, true);
	for (int i = 2; i < mn; i++) {
		if (!isp[i])continue;
		ps.push_back(i);
		for (int j = 2 * i; j < mn; j += i) {
			isp[j] = false;
		}
	}
}*/

//[,val)
template<typename T>
auto prev_itr(set<T>& st, T val) {
	auto res = st.lower_bound(val);
	if (res == st.begin())return st.end();
	res--; return res;
}

//[val,)
template<typename T>
auto next_itr(set<T>& st, T val) {
	auto res = st.lower_bound(val);
	return res;
}
using mP = pair<modint, modint>;
mP operator+(mP a, mP b) {
	return { a.first + b.first,a.second + b.second };
}
mP operator+=(mP& a, mP b) {
	a = a + b; return a;
}
mP operator-(mP a, mP b) {
	return { a.first - b.first,a.second - b.second };
}
mP operator-=(mP& a, mP b) {
	a = a - b; return a;
}
LP operator+(LP a, LP b) {
	return { a.first + b.first,a.second + b.second };
}
LP operator+=(LP& a, LP b) {
	a = a + b; return a;
}
LP operator-(LP a, LP b) {
	return { a.first - b.first,a.second - b.second };
}
LP operator-=(LP& a, LP b) {
	a = a - b; return a;
}

mt19937 mt(time(0));

const string drul = "DRUL";
string senw = "SENW";
//DRUL,or SENW
int dx[4] = { 1,0,-1,0 };
int dy[4] = { 0,1,0,-1 };
//-----------------------------------------

int calc(int n) {
	int ans = 0;
	for (int g = 1; g <= n; g++) {
		for (int a = 1; a * g <= n; a++) {
			for (int b = 1; a * b * g <= n; b++) {
				if (g + a * g + a * b * g <= n) {
					ans++;
				}
			}
		}
	}
	for (int x = 1; x <= n; x++) {
		for (int y = 2 * x; y <= n; y += x) {
			ans++;
		}
	}
	return ans;
}

const int mn = 900000;
ll mem[mn];
void init() {
	for (ll a = 1; a < mn; a++) {
		for (ll b = 1; a * b < mn; b++) {
			if (1 + a + a * b < mn)mem[1 + a + a * b]++;
		}
	}
	rep(i, mn - 1)mem[i + 1] += mem[i];
}
ll calcsub(ll n) {
	if (n < mn)return mem[n];
	n--;
	ll res = 0;
	ll k = sqrt(n);
	while (k * k < n)k++;
	for (ll a = 1; a <= k; a++) {
		if (a + 1 <= n) {
			res += (n - a) / a;
		}
	}
	for (ll d = 1; d <= k; d++) {
		ll le = n / (d + 1) + 1;
		ll ri = n / d + 1;
		chmax(le, k + 1);
		//[le,ri)
		if (le < ri) {
			res += (ri - le) * (d - 1);
		}
	}
	return res;
}
ll calc1(ll n) {
	ll res = 0;
	ll k = sqrt(n);
	while (k * k < n)k++;
	for (ll g = 1; g <= k; g++) {
		res += calcsub(n / g);
	}
	for (ll d = 1; d <= k; d++) {
		ll le = n / (d + 1) + 1;
		ll ri = n / d + 1;
		chmax(le, k + 1);
		//[le,ri)
		if (le < ri) {
			res += (ri - le) * mem[d];
		}
	}
	return res;
}
ll calc2(ll n) {
	ll res = 0;
	ll k = sqrt(n);
	while (k * k < n)k++;
	for (ll g = 1; g <= k; g++) {
		res += n / g;
	}
	for (ll d = 1; d <= k; d++) {
		ll le = n / (d + 1) + 1;
		ll ri = n / d + 1;
		chmax(le, k + 1);
		//[le,ri)
		if (le < ri) {
			res += (ri - le) * d;
		}
	}
	res -= n;
	return res;
}
ll calcsol(ll n) {
	return calc1(n) + calc2(n);
}
void expr() {
	for (int n = 1; n <= 5000; n++) {
		if (calc(n) != calcsol(n)) {
			cout << "?!\n";
			cout << n << " " << calc(n) << " " << calcsol(n) << "\n";
		}
		if (n % 100 == 0) {
			cout << n << " fin" << endl;
		}
		//cout << n << " " << calc(n)<<" "<<calcsol(n) << "\n";
	}
}
void solve() {
	ll n; cin >> n;
	cout << calcsol(n) << "\n";
}


signed main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout << fixed << setprecision(10);
	//init_f();
	init();
	//expr();
	//while(true)
	int t; cin >> t; rep(i, t)
		solve();
	return 0;
}




Details

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Test #1:

score: 0
Memory Limit Exceeded

input:

3
2
5
14

output:


result: