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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#765801 | #7733. Cool, It’s Yesterday Four Times More | DLYdly1105 | WA | 3ms | 12340kb | C++14 | 3.1kb | 2024-11-20 15:18:58 | 2024-11-20 15:19:00 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
const int N=1e3+10;
char s[N][N];
int T,n,m,tot,id[N][N],tot2,id2[N<<1][N<<1];
int fx[10][10],vis[N][N],ok[N][N<<2],ok2[N<<2];
int ans;
queue<pair<int,int>>q;
void bfs(int qx,int qy)
{
for(int i=1;i<=n;i++)for(int j=1;j<=m;j++)vis[i][j]=0;
q.push(make_pair(qx,qy));
vis[qx][qy]=1;
ok[id[qx][qy]][id2[n][m]]=1;
ok2[id2[n][m]]=1;
while(!q.empty())
{
int x=q.front().first,y=q.front().second;
q.pop();
for(int i=0;i<4;i++)
{
int nx=x+fx[i][0],ny=y+fx[i][1];
if(nx>=1&&nx<=n&&ny>=1&&ny<=m&&s[nx][ny]=='.'&&!vis[nx][ny])
{
ok[id[qx][qy]][id2[nx-qx+n][ny-qy+m]]=1;
ok2[id2[nx-qx+n][ny-qy+m]]=1;
vis[nx][ny]=1;
q.push(make_pair(nx,ny));
}
}
}
return;
}
bitset<N>b[N],aa,bb;
void solve()
{
for(int x=1;x<=n;x++)for(int y=1;y<=m;y++)
{
if(s[x][y]!='.')continue;
b[id[x][y]]=0;
for(int i=1;i<=n;i++)for(int j=1;j<=m;j++)
{
b[id[x][y]][(i-1)*m+j]=ok[id[x][y]][id2[i-x+n][j-y+m]];
}
}
int fl,fl2;
for(int i=1;i<=n*m;i++)b[0][i]=1;
for(int i=1;i<=n;i++)
{
for(int j=1;j<=m;j++)
{
if(s[i][j]!='.')continue;
fl2=1;
for(int x=1;x<=n;x++)
{
for(int y=1;y<=m;y++)
{
if(x==i&&j==y)continue;
if(s[x][y]!='.')continue;
fl=0;
for(int r=1+x-i;r<=n+x-i;r++)
{
int ll=max(1,1+y-j),rr=min(m,m+y-j),t=r-(x-i);
aa=((b[id[i][j]]>>((t-1)*m+1))&(b[0]>>(n*m-m+1)));
if(r<1||r>n)bb=0;
else bb=(((b[id[x][y]]>>((r-1)*m+ll))&(b[0]>>(n*m-(rr-ll))))<<(m-rr));
if((aa&bb)!=aa)
{
fl=1;
break;
}
}
if(!fl){fl2=0;;break;}
}
if(!fl)break;
}
if(fl2)ans++;
}
}
return;
}
int main()
{
// freopen("kangaroo.in","r",stdin);
// freopen("kangaroo.out","w",stdout);
fx[0][0]=0,fx[0][1]=-1;
fx[1][0]=0,fx[1][1]=1;
fx[2][0]=-1,fx[2][1]=0;
fx[3][0]=1,fx[3][1]=0;
scanf("%d",&T);
while(T--)
{
tot=tot2=ans=0;
scanf("%d%d",&n,&m);
for(int i=1;i<=2*n-1;i++)for(int j=1;j<=2*m-1;j++)id2[i][j]=++tot2;
for(int i=1;i<=n;i++)scanf("%s",s[i]+1);
for(int i=1;i<=n;i++)for(int j=1;j<=m;j++)if(s[i][j]=='.')id[i][j]=++tot;
for(int i=1;i<=tot;i++)for(int j=1;j<=tot2;j++)ok[i][j]=0;
for(int i=1;i<=tot2;i++)ok2[i]=0;
for(int i=1;i<=n;i++)for(int j=1;j<=m;j++)if(s[i][j]=='.')bfs(i,j);
solve();
printf("%d\n",ans);
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 12264kb
input:
4 2 5 .OO.. O..O. 1 3 O.O 1 3 .O. 2 3 OOO OOO
output:
3 1 0 0
result:
ok 4 lines
Test #2:
score: -100
Wrong Answer
time: 3ms
memory: 12340kb
input:
200 2 4 OOO. OO.. 2 3 OOO .O. 3 3 O.O OOO OO. 4 1 . . O O 1 2 .O 1 1 . 2 5 .OO.. .O.O. 2 1 O O 1 1 O 1 3 .OO 5 1 O O . O . 5 2 O. .. O. .O .. 5 3 ... ... .OO ..O OOO 3 5 ..O.O .O.O. .OO.O 5 2 .O OO O. O. .. 2 1 O O 3 5 .O.OO O...O ..OO. 1 5 ..... 5 1 O . O . . 5 3 OOO OO. .OO OO. O.O 2 1 O . 5 2 O. ...
output:
3 2 0 2 1 1 3 0 0 1 2 7 9 4 4 0 6 5 3 3 1 7 4 5 2 0 0 6 4 3 1 4 1 0 8 5 2 3 7 3 0 6 2 3 2 0 4 6 6 4 3 3 3 5 3 1 2 4 3 4 4 4 2 2 7 7 4 8 5 4 2 6 2 1 2 1 4 0 0 2 5 1 6 6 6 1 7 2 2 7 5 5 2 1 0 1 9 4 4 11 0 4 2 1 2 1 4 3 1 5 3 8 5 0 4 6 2 5 1 3 4 4 0 3 11 2 3 5 0 4 4 8 2 1 2 3 0 5 0 16 4 3 2 6 2 8 4 3 1...
result:
wrong answer 2nd lines differ - expected: '0', found: '2'