//qoj6336
#include <bits/stdc++.h>
using namespace std;

const int N = 3e5 + 10;
int n, m, a[25][N], sum[25], v[N];
pair<int, int> f[N*4], g[N*4];

bool upd(int x, pair<int, int> y){
    if((f[x] > y || (f[x] == y && g[x] > y)) && f[x].second != y.second){
        g[x] = f[x];
        f[x] = y;
        return 1;
    } else if(g[x] > y && f[x].second != y.second){
        g[x] = y;
        return 1;
    }
    return 0;
}

int main(){
    for(int i = 0; i < N; ++ i){
        f[i].first = g[i].first = 2e9;
    }
    scanf("%d%d", &n, &m);
    queue<int> q;
    for(int i = 1; i <= n; ++ i){
        for(int j = 1; j <= m; ++ j){
            scanf("%d", &a[j][i]);
            sum[j] += a[j][i];
            v[i] |= (1 - a[j][i]) << j - 1;
        }
        upd(v[i], make_pair(0, i));
        q.push(v[i]);
    }
    while(!q.empty()){
        int x = q.front();
        q.pop();
        for(int i = 0; i < m; ++ i){
            int v = 1 + (1 - ((x >> i) & 1)) * 2;
            if(upd(x^(1<<i), make_pair(f[x].first+v, f[x].second))){
                q.push(x ^ (1 << i));
            } else if(upd(x^(1<<i), make_pair(g[x].first+v, g[x].second))){
                q.push(x ^ (1 << i));
            }
        }
    }
    for(int i = 1; i <= n; ++ i){
        int val = 0, cnt = 0;
        for(int j = 1; j <= m; ++ j){
            if(sum[j] - a[j][i] == n / 2){
                val |= 1 << j - 1;
            } else if(sum[j] - a[j][i] > n / 2){
                ++ cnt;
            }
        }
        int mx = 0;
        if(n <= 3000)
        for(int j = 1; j <= n; ++ j){
            if(j != i){
                mx = max(mx, __builtin_popcount(val & v[j]));
            }
        } else {

        if(f[val].second == i){
            // printf("%d ", g[val].second);
            mx = val & v[g[val].second];
        } else {
            // printf("%d ", f[val].second);
            mx = val & v[f[val].second];
        }
        mx = __builtin_popcount(mx);
        }
        // printf("%d %d %d\n", cnt, mx, val);
        // printf("%d %d %d\n", val, f[val].second, f[val].first);
        printf("%d\n", mx + cnt);
    }
    return 0;
}