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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#763935 | #7711. Rikka with Lines | crimson231 | TL | 2ms | 7536kb | C++23 | 5.2kb | 2024-11-19 22:51:51 | 2024-11-19 22:51:51 |
Judging History
answer
#include <iostream>
#include <algorithm>
#include <cmath>
#include <vector>
#include <queue>
#include <set>
#include <deque>
#include <cstring>
#include <cassert>
typedef long long ll;
typedef double ld;
typedef std::vector<int> Vint;
typedef std::vector<ll> Vll;
typedef std::vector<ld> Vld;
const int LEN = 1e5 + 5;
ll gcd(ll a, ll b) { while (b) { ll tmp = a % b; a = b; b = tmp; } return a; }
ll gcd(ll a, ll b, ll c) { a = std::abs(a); b = std::abs(b); c = std::abs(c); a = gcd(a, b); return gcd(a, c); }
void norm(ll& x, ll& y) {
ll gcd_ = gcd(std::abs(x), std::abs(y));
x /= gcd_; y /= gcd_;
return;
}
int T, N, CNT[4];
struct Pos {
ll x, y;
Pos(ll x_ = 0, ll y_ = 0) : x(x_), y(y_) {}
bool operator == (const Pos& q) const { return x == q.x && y == q.y; }
};
struct FracPos {
ll x, y;
ll dx, dy;
int qd, i, f;
FracPos(ll x_ = 0, ll dx_ = 0, ll y_ = 0, ll dy_ = 0, int qd_ = 0, int f_ = 0) : x(x_), y(y_), dx(dx_), dy(dy_), qd(qd_), f(f_) {}
ll mod_x() const { return std::abs(x) % std::abs(dx); }
ll mod_y() const { return std::abs(y) % std::abs(dy); }
bool x_int() const { return dx != 0 && !mod_x(); }
ll x_() const { return x / dx; }
bool y_int() const { return dy != 0 && !mod_y(); }
ll y_() const { return y / dy; }
bool is_int() const { return x_int() && y_int(); }
Pos p() const { return Pos(x / dx, y / dy); }
} P1, P2, P3, P4 ;
typedef std::vector<FracPos> Polygon;
bool x_eq(const FracPos& p, const FracPos& q) { return p.x * q.dx == q.x * p.dx; }
bool y_eq(const FracPos& p, const FracPos& q) { return p.y * q.dy == q.y * p.dy; }
bool eq(const FracPos& p, const FracPos& q) { return x_eq(p, q) && y_eq(p, q); }
bool comp(const FracPos& p, const FracPos& q) {
if (p.qd != q.qd) return p.qd < q.qd;
//if (eq(p, q)) return p.f < q.f;
if (p.qd == 0) return p.x * q.dx > q.x * p.dx;
if (p.qd == 1) return p.y * q.dy > q.y * p.dy;
if (p.qd == 2) return p.x * q.dx < q.x * p.dx;
if (p.qd == 3) return p.y * q.dy < q.y * p.dy;
assert(0);
return 0;
}
struct Line {
ll a, b;
Line(ll a_ = 0, ll b_ = 0) : a(a_), b(b_) {}
} L[LEN];
struct Seg {
int l, r;
bool operator<(const Seg& o) const { return l == o.l ? r < o.r : l < o.l; }
} SEG[LEN]; int sp;
Polygon intersections(const Line& l, const FracPos& p1, const FracPos& p2) {
FracPos a, b, c, d;
ll x1 = p2.y - l.b, d1 = l.a; norm(x1, d1);
a = FracPos(x1, d1, p2.y, 1);
if (x1 <= p1.x * d1 || p2.x * d1 < x1) a.dx = a.dy = 0;
ll x3 = p1.y - l.b, d3 = l.a; norm(x3, d3);
c = FracPos(x3, d3, p1.y, 1);
if (x3 < p1.x * d3 || p2.x * d3 <= x3) c.dx = c.dy = 0;
ll y2 = p1.x * l.a + l.b;
b = FracPos(p1.x, 1, y2, 1);
if (b.y_() <= p1.y || p2.y < b.y_()) b.dx = b.dy = 0;
ll y4 = p2.x * l.a + l.b;
d = FracPos(p2.x, 1, y4, 1);
if (d.y_() < p1.y || p2.y <= d.y_()) d.dx = d.dy = 0;
a.qd = 0, b.qd = 1, c.qd = 2, d.qd = 3;
//if (a.is_int() && (b.is_int() && a.p() == b.p())) a.dx = a.dy = 0;
//if (b.is_int() && (c.is_int() && b.p() == c.p())) b.dx = b.dy = 0;
//if (c.is_int() && (d.is_int() && c.p() == d.p())) c.dx = c.dy = 0;
//if (d.is_int() && (a.is_int() && d.p() == a.p())) d.dx = b.dy = 0;
Polygon v;
if (a.dx) v.push_back(a);
if (b.dx) v.push_back(b);
if (c.dx) v.push_back(c);
if (d.dx) v.push_back(d);
return v;
}
ll fenwick[LEN * 2];
ll sum(int idx) {
ll s = 0;
while (idx > 0) {
s += fenwick[idx];
idx -= idx & -idx;
}
return s;
}
void update(int idx, int diff) {
while (idx < LEN * 2) {
fenwick[idx] += diff;
idx += idx & -idx;
}
}
void query() {
std::cin >> N >> P3.x >> P3.y >> P1.x >> P1.y;
/*
P2 -- P1
| |
P3 -- P4
*/
P2.x = P3.x; P2.y = P1.y; P4.x = P1.x; P4.y = P3.y;
memset(CNT, 0, sizeof CNT);
memset(fenwick, 0, sizeof fenwick);
memset(SEG, 0, sizeof SEG);
for (int i = 0; i < N; i++) std::cin >> L[i].a >> L[i].b;
std::priority_queue<Seg> PQ;
Polygon P;
for (int i = 0; i < N; i++) {
Polygon V = intersections(L[i], P3, P1);
if (V.empty()) continue;
if (V.size() == 1) {
P.push_back(V[0]);
P.back().i = i;
P.push_back(V[0]);
P.back().i = i; P.back().f = 1;
}
if (V.size() == 2) {
P.push_back(V[0]);
P.back().i = i;
P.push_back(V[1]);
P.back().i = i; P.back().f = 1;
}
}
std::sort(P.begin(), P.end(), comp);
// for (int i = 0; i < P.size(); ++i) std::cout << "index: " << P[i].i << ' ' << P[i].f << '\n';
//assert(P[0].f == 0);
SEG[P[0].i].l = 1;
for (int i = 1, idx = 1; i < P.size(); ++i) {
if (!eq(P[i], P[i - 1])) idx++;
// std::cout << i << ' ' << P[i].i << ' ' << P[i].f << ' ' << idx << '\n';
(!P[i].f ? SEG[P[i].i].l : SEG[P[i].i].r) = idx;
}
// for (int i = 0; i < N; ++i) std::cout << SEG[i].l << ' ' << SEG[i].r << '\n';
std::sort(SEG, SEG + N);
ll ret = 0;
for (int i = 0; i < N; ++i) {
if (!SEG[i].l) continue;
ret += sum(SEG[i].r) - sum(SEG[i].l - 1);
update(SEG[i].r, 1);
}
std::cout << ret << '\n';
}
void solve() {
P1.dx = 1; P1.dy = 1; P2.dx = 1; P2.dy = 1;
P3.dx = 1; P3.dy = 1; P4.dx = 1; P4.dy = 1;
std::cin.tie(0)->sync_with_stdio(0);
std::cout.tie(0);
std::cout << std::fixed;
std::cout.precision(3);
std::cin >> T;
while (T--) query();
return;
}
int main() { solve(); return 0; }
详细
Test #1:
score: 100
Accepted
time: 2ms
memory: 7536kb
input:
1 4 0 0 2 2 2 -1 1 0 -1 2 2 2
output:
4
result:
ok 1 number(s): "4"
Test #2:
score: -100
Time Limit Exceeded
input:
1000 99981 -729383395 -411431000737086146 -663099572 622842060014806018 6815159 -4872972553264521 -44664715 3425012672809037 -896158824 -386342591542384 -375531970 1040294806535662 483111943 -6742268275140254 611052273 -1055860484502308 434838119 6111752598959468 848557869 532300694586514 857250003 ...