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QOJ
| ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
|---|---|---|---|---|---|---|---|---|---|
| #762800 | #9430. Left Shifting 2 | HaijieTan | WA | 3ms | 3628kb | C++23 | 2.2kb | 2024-11-19 16:43:30 | 2024-11-19 16:43:35 |
Judging History
answer
#include<iostream>
#include<vector>
#include<bitset>
#include<algorithm>
#include<cmath>
#include<queue>
#include<numeric>//iota -- iota(all(a), x) a从头到尾从x开始递增
#include<cstring>
#include<ctime>
#include<array>
#include<list>
#include<random>
#include<tuple>
#include<deque>
#include<map>
#include<stack>
#include<set>
using namespace std;
template <typename Dtype>
unsigned int __builtin_popcount(Dtype u)
{
u = (u & 0x55555555) + ((u >> 1) & 0x55555555);
u = (u & 0x33333333) + ((u >> 2) & 0x33333333);
u = (u & 0x0F0F0F0F) + ((u >> 4) & 0x0F0F0F0F);
u = (u & 0x00FF00FF) + ((u >> 8) & 0x00FF00FF);
u = (u & 0x0000FFFF) + ((u >> 16) & 0x0000FFFF);
return u;
}//wishchin!!!
#define IOS ios::sync_with_stdio(false);cin.tie(0), cout.tie(0)
#define int long long
#define all(x) x.begin(), x.end()
#define pb push_back
#define pf push_front
#define lowbit(x) (x & (-x))
const int xy[][2] = { 0,1, 0, -1, 1, 0, -1, 0 };
#define mem(a, x) memset(a, x, sizeof a)
typedef long long ll;
typedef pair<int, int> PII;
typedef pair<double, double> PDD;
typedef pair<char, char> PCC;
typedef pair<int, char> PIC;
typedef pair<char, int> PCI;
#define x first
#define y second
#define NO cout << "NO\n"
#define YES cout << "YES\n"
inline int read();
const int INF = 0x3f3f3f3f, N = 1e6 + 10, MOD = 1e9 + 7, M = 1e4 + 10, K = 131;
const double PI = acos(-1.0);
void solve() {
string s; cin >> s;
int n = s.size(), index = 0, sum = 0, cnt = 0;
if (n == 1)return cout << "0\n", void();
while (index < n) {
int t = 1;
while (index < n - 1 && s[index] == s[index + 1])index++, t++;
sum += t / 2;
if (t % 2 == 0) {
//cnt = max(cnt, t / 2 - 1);
cnt = 1;
}
index++;
}
if (s[0] == s[n - 1])cout << sum << endl;
else cout << sum - cnt << endl;
//if (cnt)cnt -= s[0] == s[n - 1];
//cout << sum - cnt << endl;
}
signed main() {
IOS;
int _ = 1;
cin >> _;
while (_--)solve();
return 0;
}
inline int read()
{
int x = 0, f = 1; char ch = getchar();
while (ch < '0' || ch>'9') { if (ch == '-') f = -1; ch = getchar(); }
while (ch >= '0' && ch <= '9') { x = x * 10 + ch - 48; ch = getchar(); }
return x * f;
}
/* /\_/\
* (= ._.)
* / > \>
*/
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3628kb
input:
3 abccbbbbd abcde x
output:
2 0 0
result:
ok 3 lines
Test #2:
score: -100
Wrong Answer
time: 3ms
memory: 3628kb
input:
5000 lfpbavjsmppdppkfwnyfmbdhptdswsoulrbhyjh cfliuqnynejgnxolzbdoztclzbozqomvioszk eiivcoqoymonrqgrjdtkts mdcvservaxcbioopfungsgkiftchwlmtbzqgaraovjknsgiegkvdbolmeunvrxrpscnf ujeqtidwtoikkqtygo llma qjfvgwrdhaazejsfgilnpmmhkefndzvyon kzwwpdpbrudqmwmjscllnnjyoepxophcoopvfepikouinuxx vftculoorxskpkxoz...
output:
1 0 0 0 0 0 1 4 0 0 1 1 1 1 1 3 1 0 5 6 0 0 5 2 0 1 3 2 0 3 0 1 0 1 1 0 1 4 1 3 1 0 1 5 3 0 3 0 0 1 8 1 0 6 1 2 0 1 0 0 4 1 2 4 3 1 3 2 3 1 2 1 0 0 2 0 2 2 0 4 0 5 5 0 3 0 4 1 0 2 1 0 2 0 1 6 1 2 1 3 3 3 5 2 3 0 3 5 1 3 0 0 3 0 4 5 3 2 1 1 0 0 2 0 1 1 3 3 3 1 2 0 1 1 4 3 1 3 1 1 1 2 0 1 2 0 4 0 1 1 ...
result:
wrong answer 591st lines differ - expected: '2', found: '3'