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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#762276 | #5441. Quartz Collection | SGColin# | WA | 3ms | 66928kb | C++14 | 2.7kb | 2024-11-19 14:24:06 | 2024-11-19 14:24:07 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef tuple<int, int, int> tii;
#define eb emplace_back
#define pb push_back
#define all(s) (s).begin(), (s).end()
#define rep(i, a, b) for (int i = (a); i <= (b); ++i)
#define per(i, a, b) for (int i = (a); i >= (b); --i)
inline int rd() {
int x = 0;
bool f = 0;
char c = getchar();
for (; !isdigit(c); c = getchar()) f |= (c == '-');
for (; isdigit(c); c = getchar()) x = x * 10 + (c ^ 48);
return f ? -x : x;
}
constexpr int N = 200007;
struct node {
ll sum[4];
int cnt;
node(){cnt = 0; memset(sum, 0, sizeof(sum));};
node operator + (const node &obj) const {
node ret;
ret.cnt = cnt + obj.cnt;
rep(i, 0, 3) ret.sum[i] = sum[i];
rep(i, 0, 3) ret.sum[(i + cnt) % 4] += obj.sum[i];
return ret;
}
};
struct segtree {
#define ls (rt << 1)
#define rs (rt << 1 | 1)
#define mid ((l + r) >> 1)
node c[N << 2];
void upd(int rt, int l, int r, int pos, bool w) {
if (l == r) {
if (w) {
c[rt].cnt++;
c[rt].sum[c[rt].cnt % 4] += pos;
} else {
c[rt].sum[c[rt].cnt % 4] -= pos;
c[rt].cnt--;
}
return;
}
pos <= mid ? upd(ls, l, mid, pos, w) : upd(rs, mid + 1, r, pos, w);
c[rt] = c[ls] + c[rs];
}
} t1, t2;
int a[N], b[N];
ll sumb = 0;
int main() {
int n = rd(), q = rd();
rep(i, 1, n) {
a[i] = rd(); b[i] = rd(); sumb += b[i];
if (a[i] > b[i]) t2.upd(1, 1, 100000, a[i] - b[i], 1);
else t1.upd(1, 1, 100000, b[i] - a[i], 1);
}
auto calc = [&]() {
node A = t1.c[1], B = t2.c[1];
//printf("%d %lld %lld %lld %lld\n", A.cnt, A.sum[0], A.sum[1], A.sum[2], A.sum[3]);
// printf("%d %lld %lld %lld %lld\n", B.cnt, B.sum[0], B.sum[1], B.sum[2], B.sum[3]);
int cnt = A.cnt;
ll ans = sumb;
ans -= A.sum[cnt % 4];
ans -= A.sum[(cnt + 1) % 4];
//printf("%lld\n", ans);
ans += B.sum[(cnt + 1) % 2];
ans += B.sum[(cnt + 1) % 2 + 2];
return ans;
};
printf("%lld\n", calc());
rep(t, 1, q) {
int i = rd();
if (a[i] > b[i]) t2.upd(1, 1, 100000, a[i] - b[i], 0);
else t1.upd(1, 1, 100000, b[i] - a[i], 0);
sumb -= b[i];
a[i] = rd(); b[i] = rd(); sumb += b[i];
if (a[i] > b[i]) t2.upd(1, 1, 100000, a[i] - b[i], 1);
else t1.upd(1, 1, 100000, b[i] - a[i], 1);
printf("%lld\n", calc());
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 3ms
memory: 66928kb
input:
4 5 2 4 5 7 1 7 2 1 4 5 2 1 6 2 4 4 3 2 1 3 3 6 6
output:
13 14 15 14 10 13
result:
ok 6 numbers
Test #2:
score: 0
Accepted
time: 3ms
memory: 66272kb
input:
1 1 1 1 1 1 1
output:
1 1
result:
ok 2 number(s): "1 1"
Test #3:
score: -100
Wrong Answer
time: 3ms
memory: 66340kb
input:
100 100 6 7 100 8 5 61 5 75 59 65 51 47 83 37 34 54 87 46 4 26 21 87 12 97 86 68 60 11 62 76 14 83 29 31 91 62 57 80 47 75 85 97 62 77 91 86 14 25 48 77 83 65 39 61 78 77 45 46 90 74 100 91 86 98 55 5 84 42 91 69 100 4 74 98 60 37 75 44 41 12 15 34 36 1 99 16 7 87 36 26 79 42 41 84 17 98 72 16 38 55...
output:
5109 5066 5061 5007 4975 4993 4950 4927 4922 4929 4948 4915 4885 4863 4897 4863 4837 4787 4793 4775 4730 4709 4660 4617 4546 4618 4655 4687 4677 4685 4714 4732 4728 4700 4659 4630 4627 4681 4742 4776 4764 4772 4754 4760 4715 4743 4671 4686 4700 4649 4611 4542 4523 4555 4605 4585 4532 4519 4488 4505 ...
result:
wrong answer 2nd numbers differ - expected: '5065', found: '5066'