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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#761835#6733. Moniphant SleepXfJbUhpyzgaWTL 1ms5572kbC++173.2kb2024-11-19 10:38:262024-11-19 10:38:26

Judging History

你现在查看的是最新测评结果

  • [2024-11-19 10:38:26]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:5572kb
  • [2024-11-19 10:38:26]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

#define F(i, a, b) for (int i = (a), iee = (b); i <= iee; i++)

const int N = 500100, inf = 0x3f3f3f3f;
int n, q;

struct info {
    int x, y, d1, d2;
    friend info operator + (const info &a, const info &b) {
        return {min(a.x, b.x), min(a.y, b.y), min(a.d1, b.d1), max(a.d2, b.d2)};
    }
    static const info id;
} arr[N << 2];
const info info::id = {inf, inf, inf, -inf};

struct tag_t {
    int xx, xy, yx, yy, _d, dd;
    friend info operator * (const info &a, const tag_t &b) {
        return {
            min({a.x + b.xx, a.y + b.yx, inf}),
            min({a.x + b.xy, a.y + b.yy, inf}),
            min({a.d1 + b.dd, b._d}),
            min({a.d2 + b.dd, b._d})
        };
    }
    friend tag_t operator * (const tag_t &a, const tag_t &b) {
        return {
            min({a.xx + b.xx, a.xy + b.yx, inf}),
            min({a.xx + b.xy, a.xy + b.yy, inf}),
            min({a.yx + b.xx, a.yy + b.yx, inf}),
            min({a.yx + b.xy, a.yy + b.yy, inf}),
            min({a._d + b.dd, b._d}),
            min({a.dd + b.dd, inf})
        };
    }
    static const tag_t id;
} tag[N << 2];
const tag_t tag_t::id = {0, inf, inf, 0, inf, 0};

#define lc p << 1
#define rc lc | 1
#define mid ((l + r) >> 1)
void build(int l, int r, int p) {
    arr[p] = {500000, inf, inf, inf};
    tag[p] = tag_t::id;
    if (l == r) return;
    build(l, mid, lc), build(mid + 1, r, rc);
}
void up(int p) { arr[p] = arr[lc] + arr[rc]; }
void modify(int p, const tag_t &t) { arr[p] = arr[p] * t, tag[p] = tag[p] * t; }
void down(int p) { modify(lc, tag[p]), modify(rc, tag[p]), tag[p] = tag_t::id; }

info query(int x, int y, int l, int r, int p) {
    if (x > r || y < l) return info::id;
    if (x <= l && y >= r) return arr[p];
    return (query(x, y, l, mid, lc) + query(x, y, mid + 1, r, rc)) * tag[p];
}
void modify(int x, int y, const tag_t &k1, const tag_t &k2, int l, int r, int p) {
    if (x > r || y < l) return;
    if (x <= l && y >= r && l == r) { // debug!
        auto ti = arr[p] * k1;
        if (ti.d2 <= 0)
            return modify(p, k1);
        if (ti.d1 > 0)
            return modify(p, k2);
        //if (l == 1) cerr << arr[p].x << " " << arr[p].y << " " << arr[p].d1 << " " << arr[p].d2 << "\n";
        //return;
    }
    down(p);
    modify(x, y, k1, k2, l, mid, lc);
    modify(x, y, k1, k2, mid + 1, r, rc);
    up(p);
}
// (v1+v2)*A=v1*A+v2*A

/*
(x, y, y - x) -> (+1, =, -1)
(x, y, y - x) -> (-1, =, +1); (x, y, 0) -> (x - 1, inf, inf) // min >= 0 ??
(x, y, y - x) -> (=, min(x, y), min(y - x, 0))
(x, y, y - x) -> (min(x, y), inf, inf)
 */

const tag_t op[5][2] = {
    {tag_t::id, tag_t::id},
    {{1, inf, inf, 0, inf, -1}, tag_t::id},
    {{-1, inf, inf, 0, inf, 1}, {-1, inf, inf, inf, inf, inf}},
    {{0, 0, inf, 0, 0, 0}, tag_t::id},
    {{0, inf, 0, inf, inf, inf}, tag_t::id}
};

int main() {
    cin >> n >> q;
    build(1, n, 1);
    F(i, 1, q) {
        int p, x, y;
        cin >> p >> x >> y;
        if (p <= 4) {
            modify(x, y, op[p][0], op[p][p == 2], 1, n, 1);
        } else {
            auto ret = query(x, y, 1, n, 1);
            cout << ret.x << "\n";
        }
    }
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 5572kb

input:

1 9
1 1 1
1 1 1
1 1 1
3 1 1
2 1 1
1 1 1
1 1 1
4 1 1
5 1 1

output:

500004

result:

ok 1 number(s): "500004"

Test #2:

score: 0
Accepted
time: 1ms
memory: 5568kb

input:

3 7
2 1 3
3 1 3
1 1 3
1 1 3
5 1 1
4 1 3
5 1 1

output:

500001
499999

result:

ok 2 number(s): "500001 499999"

Test #3:

score: -100
Time Limit Exceeded

input:

500000 500000
2 132991 371170
5 15281 15281
1 278642 397098
2 152103 176573
2 13797 47775
3 139320 370045
3 79054 432340
3 82556 212775
4 270171 469418
5 148000 148000
3 371255 401414
5 71051 71051
2 358945 473071
2 231663 265401
2 20243 58131
1 247710 313373
5 154549 154549
1 17317 233265
5 37602 3...

output:

500000
499999
500000
499998
499999
500000
500000
499997
500000
499997
499997
499999
499998
500000
499997
500000
499999
500001
499999
499999
499997
499997
499996
499998
500000
500001
500001
499996
499998
499999
499996
499999
500001
500000
500000
500002
500002
499997
500001
499997
499995
499999
500004...

result: