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#759137#9573. Social MediazaqmjuCompile Error//C++201.6kb2024-11-17 21:58:572024-11-17 21:58:57

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  • [2024-11-17 21:58:57]
  • 评测
  • [2024-11-17 21:58:57]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
typedef pair<int, int> PII;
#define int long long
#define pb push_back
#define endl '\n'
struct node {
	int x, id;
	bool operator <(const node &a) const {
		return x < a.x;
	}
};
void solve() {
	int n, m, k;
	cin >> n >> m >> k;
	map<int, int>mp;
	for(int i = 1; i <= n; i++) {
		int x;
		cin >> x;
		mp[x]++;
	}
	vector<node>sum(k + 1);
	for(int i = 1; i <= k; i++) {
		sum[i].id = i;
	}
	int ans = 0;
	vector<vector<int>> e(k + 1);
	vector<int> uu(m + 1), vv(m + 1);
	map<PII, int>mpp;
	for(int i = 1; i <= m; i++) {
		int u, v;
		cin >> u >> v;
		uu[i] = u;
		vv[i] = v;
		if(mp[u] && mp[v]) ans++;
		else if(mp[u]) {
			sum[v].x++;
		}
		else if(mp[v]) {
			sum[u].x++;
		}
		else {
			mpp[{u, v}]++;
			mpp[{v, u}]++;
			e[u].push_back(v);
			e[v].push_back(u);
		}
	}
	int sum1 = 0;
	for(int i = 1; i <= m; i++) {
		int u = uu[i], v = vv[i];
		if(mp[u] && mp[v])continue;
		if(u == v)continue;
		/*else if(mp[u])
		{
			if(k!=v)
				sum1 = max(sum1,sum[v].x+sum[k].x);
			else 
				sum1 = max(sum1,sum[v].x+sum[k-1].x);
		}
		else if(mp[v])
		{
			if(k!=u)
				sum1 = max(sum1,sum[u].x+sum[k].x);
			else 
				sum1 = max(sum1,sum[u].x+sum[k-1].x);
		}
		else*/
		sum1 = max(sum1, sum[u].x + sum[v].x + mpp[{u, v}]);
	}
	sort(sum.begin() + 1, sum.end());
	sum1 = max(sum1, sum[k].x + sum[k - 1].x + mpp[{sum[k].id, sum[k - 1].id}]);
	cout << min(m, ans + sum1) <<endl;
}

#undef int
int main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
	int t = 1;
	cin >> t;
	while(t--) {
		solve();
	}
	return 0;
}

Details

answer.code: In function ‘void solve()’:
answer.code:53:27: error: ‘continue;’ was not declared in this scope
   53 |                 if(u == v)continue;
      |                           ^~~~~~~~~~
answer.code:69:66: error: expected primary-expression before ‘]’ token
   69 |                 sum1 = max(sum1, sum[u].x + sum[v].x + mpp[{u, v}]);
      |                                                                  ^