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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#758853#9574. StripsWTR2007TL 1ms3968kbC++201.9kb2024-11-17 20:04:022024-11-17 20:04:02

Judging History

你现在查看的是最新测评结果

  • [2024-11-17 20:04:02]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:3968kb
  • [2024-11-17 20:04:02]
  • 提交

answer

#include<bits/stdc++.h>
#define int long long
#define fi first
#define se second
#define MULT_TEST 1
using namespace std;
typedef long double ldb;
typedef unsigned long long ull;
const int INF = 0x3f3f3f3f;
const int MOD = 998244353;
inline int read() {
    int w = 0, f = 1;
    char ch = getchar();
    while (ch < '0' || ch > '9') {
        if (ch == '-') f = -1;
        ch = getchar();
    }
    while (ch >= '0' && ch <= '9') {
        w = (w << 1) + (w << 3) + ch - 48;
        ch = getchar();
    }
    return w * f;
}
inline void Solve() {
    int n, m, k, w;
    n = read(), m = read(), k = read(), w = read();
    vector<int> a(n + 2), b(m + 2);
    a[0] = 0, a[n + 1] = INF;
    for (int i = 1; i <= n; i++) a[i] = read();
    sort(a.begin() + 1, a.end());
    b[0] = 0, b[m + 1] = w + 1;
    for (int i = 1; i <= m; i++) b[i] = read();
    sort(b.begin(), b.end());
    vector<int> A;
    for (int i = 1; i <= m + 1; i++) {
        if (b[i] - b[i - 1] == 1) continue;
        int C = *lower_bound(a.begin() + 1, a.end(), b[i - 1] + 1);
        int pos = C, sum = 0, flag = 0;
        vector<int> B;
        while (pos < b[i]) {
            sum++, B.push_back(pos), pos += k;
            if (pos >= b[i]) flag = 1;
            pos = *lower_bound(a.begin() + 1, a.end(), pos);
        }
        if (b[i] - b[i - 1] - 1 < sum * k)
            return printf("-1\n"), void();
        if (flag) {
            reverse(B.begin(), B.end());
            int top = b[i];
            for (auto &u : B) {
                if (u + k - 1 >= top) u = top - k;
                else break;
                top = u;
            }
        }
        for (auto u : B) A.push_back(u);
    }
    printf("%lld\n", (int)A.size());
    for (auto u : A) printf("%lld ", u);
    puts("");
}
signed main() {
    int _ = 1;
#if MULT_TEST
    _ = read();
#endif 
    while (_--) Solve();
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3968kb

input:

4
5 2 3 16
7 11 2 9 14
13 5
3 2 4 11
6 10 2
1 11
2 1 2 6
1 5
3
2 1 2 6
1 5
2

output:

4
2 10 7 14 
-1
2
1 5 
-1

result:

ok ok 4 cases (4 test cases)

Test #2:

score: -100
Time Limit Exceeded

input:

11000
3 8 2 53
32 3 33
35 19 38 20 1 30 10 6
7 10 1 42
3 14 4 36 28 40 22
17 20 12 41 27 7 1 19 13 9
6 6 13 78
55 76 53 32 54 58
62 45 21 4 7 61
8 7 3 68
9 26 54 31 22 3 38 65
34 16 58 47 52 29 53
5 8 4 33
33 5 30 6 15
27 12 9 28 19 2 13 10
6 1 2 48
8 12 48 1 41 31
40
7 6 7 61
20 19 30 52 49 17 40
3...

output:

2
3 32 
7
3 4 14 22 40 36 28 
3
32 48 66 
8
3 9 26 22 31 38 54 65 
3
5 15 30 
6
1 8 12 31 47 41 
4
17 39 30 49 
2
52 67 
1
27 
1
22 
1
62 
5
24 43 33 48 60 
2
4 31 
3
20 11 31 
3
3 16 33 
3
30 25 42 
3
3 17 60 
4
21 11 1 33 
2
66 54 
3
50 59 65 
3
50 62 78 
1
81 
4
2 11 16 23 
5
3 7 36 17 49 
2
1 45...

result: