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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#758126#5051. Namomo Subsequence_xqy_ML 0ms3884kbC++202.1kb2024-11-17 16:02:472024-11-17 16:02:47

Judging History

你现在查看的是最新测评结果

  • [2024-11-17 16:02:47]
  • 评测
  • 测评结果:ML
  • 用时:0ms
  • 内存:3884kb
  • [2024-11-17 16:02:47]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
using LL = long long;
constexpr int mod = 998244353;

void solve() {
	
	string s;
	cin >> s;

	int n = s.size();
	s = " " + s;

	auto get = [&] (char c) {
		if (c >= 'a' && c <= 'z') return c - 'a';
		else if (c >= 'A' && c <= 'Z') return c - 'A' + 26;
		else return c - '0' + 52;
	};

	vector<int> t(n + 1);
	for (int i = 1 ; i <= n ; ++i) {
		t[i] = get(s[i]);
	}

	constexpr int M = 62;
	vector<int> cnt(M) , sum(n + 1);
	vector<vector<int>> pos(M);
	vector<vector<LL>> Pre(n + 1 , vector<LL>(M));
	vector<vector<LL>> lst(n + 1 , vector<LL>(M));
	for (int i = 1 ; i <= n ; ++i) {
		for (int j = 0 ; j < M ; ++j) {
			Pre[i][j] = Pre[i - 1][j];
			lst[i][j] = lst[i - 1][j];
		}
		Pre[i][t[i]] += 1;
		pos[t[i]].emplace_back(i);
		sum[i] = sum[i - 1] + cnt[t[i]];
		lst[i][t[i]] = lst[i][t[i]] + cnt[t[i]];
		cnt[t[i]] += 1;
	}

	LL ans = 0;
	for (int i = 0 ; i < M ; ++i) {
		
		if (pos[i].empty()) continue;
		int m1 = pos[i].size() , k1 = m1 - 1;
		vector<int> dp(m1);
		LL cnt_1_0 = 0;

		for (int j = 0 ; j < M ; ++j) {

			if (i == j || pos[j].empty()) continue;
			LL cnt_0_0 = 0 , cnt_0_1 = 0;
			int m2 = pos[j].size() , k2 = m2 - 1;

			while (k1 >= 0  || k2 >= 0) {
				if (k1 >= 0 && k2 >= 0) {
					if (pos[i][k1] > pos[j][k2]) {
						cnt_1_0 += cnt_0_0;
						dp[k1] = cnt_0_1 % mod;
						k1 --;
					} else {
						cnt_0_0 += 1;
						cnt_0_1 += cnt_1_0;
						k2 --;
					}
				} else if (k1 >= 0) {
					cnt_1_0 += cnt_0_0;
					dp[k1] = cnt_0_1 % mod;
					k1 --;
				} else {
					break;
				}
			}
			
			for (int k = 0 ; k < m1 ; ++k) {
				LL p = pos[i][k];
				LL a = (p - 1) - Pre[p - 1][i] - Pre[p - 1][j];
				a = a * (a - 1) / 2 % mod;
				LL b = lst[p - 1][i] + lst[p - 1][j] - sum[p - 1];
				a = (a + b) * dp[k] % mod;
				ans += a;
				dp[k] = 0;
			}
			cnt_1_0 = 0 , k1 = m1 - 1;
		}
	}

	ans = (ans % mod + mod) % mod;
	cout << ans << "\n";
}

int main() {

	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	int t = 1;
	while (t--) {
		solve();
	}

	return 0;

}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3672kb

input:

wohaha

output:

1

result:

ok 1 number(s): "1"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3576kb

input:

momomo

output:

0

result:

ok 1 number(s): "0"

Test #3:

score: 0
Accepted
time: 0ms
memory: 3884kb

input:

gshfd1jkhaRaadfglkjerVcvuy0gf

output:

73

result:

ok 1 number(s): "73"

Test #4:

score: 0
Accepted
time: 0ms
memory: 3532kb

input:

retiredMiFaFa0v0

output:

33

result:

ok 1 number(s): "33"

Test #5:

score: -100
Memory Limit Exceeded

input:

bcdccccacccabdbdaddcabddbaccaaaaaabaccbbbcbbddabcbccabacdacbcbabccbcbddcdcbcaaadddddccdbabaabcbbcaaadadacdaadbdccbddddabcbaaddbcadadcbcbaaccacabdababaabdccadaddacdcacdaabbadadaddbbcccbcddaccaadbbcaaccccdcacbdbdddbaccaacbcaccaaabccdadddbaabdbcaaccacdcdcbcdddacbcacdbbbdccdddccccabdbacddacbaacbbcaccdcd...

output:

31291096

result: