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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#757049#5141. Identical ParityryxWA 44ms3620kbC++232.3kb2024-11-16 23:41:212024-11-16 23:41:22

Judging History

你现在查看的是最新测评结果

  • [2024-11-16 23:41:22]
  • 评测
  • 测评结果:WA
  • 用时:44ms
  • 内存:3620kb
  • [2024-11-16 23:41:21]
  • 提交

answer

#include <bits/stdc++.h>
#define int long long
#define endl '\n'
using namespace std;
int a,b,x,y;
int exgcd(int a,int b,int &x,int &y)
{
    if(b==0)
    {
        x=1,y=0;
        return a;
    }
    int d=exgcd(b,a%b,x,y);
    int k=x;
    x=y;
    y=k-a/b*y;
    return d;
}

signed main(){
    int t;
    cin>>t;
    while(t--){
        int n,k;
        cin>>n>>k;
        if(n==1) cout<<"YES"<<endl;
        else if(n==2){
            if(k==1) cout<<"NO"<<endl;
            else cout<<"YES"<<endl;
        }
        else{
            if(n%k==0){
                if(k%2==0||n==k) cout<<"YES"<<endl;
                else cout<<"NO"<<endl;
            }
            else{
                //a<b
                a = n/k,b = a+1;
                int t = n/2;
                int d = exgcd(a,b,x,y);
                x*=t,y*=t;
                if(x<=0&&y<=0) cout<<"NO"<<endl;
                else{
                    if(x>0){
                        int l = x%b,r = k-n%k;
                        int ok = 0;
                        while(l<=r){
                            int mid = (l+r)/2;
                            int ny = (t-a*mid)/b;
                            if(ny<0) r = mid-1;
                            else if(ny>n%k) l = mid+1;
                            else {
                                ok = 1;
                                break;
                            }
                        }
                        if(ok) cout<<"YES"<<endl;
                        else cout<<"NO"<<endl;
                    }
                    else if(y>0){
                        int l = y%a,r = n%k;
                        int ok = 0;
                        while(l<=r){
                            int mid = (l+r)/2;
                            int nx = (t-b*mid)/a;
                            if(nx<0) r = mid-1;
                            else if(nx>k-n%k) l = mid+1;
                            else {
                                ok = 1;
                                break;
                            }
                        }
                        if(ok) cout<<"YES"<<endl;
                        else cout<<"NO"<<endl;
                    }
                }
            }
            
        }
    }
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3620kb

input:

3
3 1
4 2
5 3

output:

NO
YES
YES

result:

ok 3 token(s): yes count is 2, no count is 1

Test #2:

score: -100
Wrong Answer
time: 44ms
memory: 3596kb

input:

100000
1 1
2 1
2 2
3 1
3 2
3 3
4 1
4 2
4 3
4 4
5 1
5 2
5 3
5 4
5 5
6 1
6 2
6 3
6 4
6 5
6 6
7 1
7 2
7 3
7 4
7 5
7 6
7 7
8 1
8 2
8 3
8 4
8 5
8 6
8 7
8 8
9 1
9 2
9 3
9 4
9 5
9 6
9 7
9 8
9 9
10 1
10 2
10 3
10 4
10 5
10 6
10 7
10 8
10 9
10 10
11 1
11 2
11 3
11 4
11 5
11 6
11 7
11 8
11 9
11 10
11 11
12 1
...

output:

YES
NO
YES
NO
YES
YES
NO
YES
YES
YES
NO
YES
YES
YES
YES
NO
YES
NO
YES
YES
YES
NO
YES
YES
YES
YES
YES
YES
NO
YES
YES
YES
YES
YES
YES
YES
NO
YES
NO
YES
YES
YES
YES
YES
YES
NO
YES
NO
YES
NO
YES
YES
YES
YES
YES
NO
YES
NO
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
NO
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YE...

result:

wrong answer expected NO, found YES [31st token]