QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#756987#5141. Identical Parityfrankly6WA 6ms3712kbC++171.8kb2024-11-16 23:16:472024-11-16 23:16:48

Judging History

你现在查看的是最新测评结果

  • [2024-11-16 23:16:48]
  • 评测
  • 测评结果:WA
  • 用时:6ms
  • 内存:3712kb
  • [2024-11-16 23:16:47]
  • 提交

answer

#include<iostream>
#include<cstdio>
#define int long long
using namespace std;
const int MX=100050;

int T, N, K;
int read()
{
    int r=0, f=1; char ch=getchar();
    while(ch<'0'||ch>'9') {if(ch=='-') f=-1; ch=getchar();}
    while(ch>='0'&&ch<='9') {r=r*10+ch-'0'; ch=getchar();}
    return r*f;
}
int exgcd(int a, int b, int &x, int &y)
{
    if(b==0){x=1, y=0; return a;}
    else{int tmp; int d=exgcd(b,a%b,tmp,x); y=tmp-a/b*x; return d;}
}
signed main()
{
    // freopen("testdata.in","r",stdin);
    T=read();
    while(T--)
    {
        N=read(), K=read();
        if(K%2==0||N==1) cout << "Yes\n";
        else
        {
            int tx, ty;
            int a=N/K+1, b=N/K, c=N/2;
            int la=N%K, lb=K-N%K;
            int d=exgcd(a,b,tx,ty);
            if(c%d) {cout << "No\n"; continue;}
            a/=d; b/=d; c/=d;
            tx=tx*(c%b)%b;
            if(tx<0) tx+=b;
            ty=(c-a*tx)/b;
            if(ty<0||tx>la) {cout << "No\n"; continue;}
            // cout << "a=" << a << ", b=" << b << ", c=" << c << ", x=" << tx << ", y=" << ty << '\n';
            int L1=-tx*a, R1=(N%K-tx)*a, L2=(N%K+ty-K)*b, R2=ty*b;
            // cout << "L1=" << L1 << ", R1=" << R1 << ", L2=" << L2 << ", R2=" << R2 << '\n';
            if(L1>R2||R1<L2) {cout << "No\n"; continue;}
            if(R1-L1<a*b&&R1/a/b==L1/a/b&&L1%(a*b)) {cout << "No\n"; continue;}
            if(R2-L2<a*b&&R2/a/b==L2/a/b&&L2%(a*b)) {cout << "No\n"; continue;}
            if(R1>R2&&R2/a/b!=L1/a/b) cout << "Yes\n";
            else if(R1/a/b!=L2/a/b) cout << "Yes\n";
            else cout << "No\n";
        }
    }
    return (0-0);
}
/*
    n/k full length k parts
    n-n/k :(n/k+1 same parity)
    k-(n-n/k) :(n/k same parity) 

    n/2 : even
    n-n/2 : odd
    \det <= 1
*/

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3712kb

input:

3
3 1
4 2
5 3

output:

No
Yes
Yes

result:

ok 3 token(s): yes count is 2, no count is 1

Test #2:

score: -100
Wrong Answer
time: 6ms
memory: 3636kb

input:

100000
1 1
2 1
2 2
3 1
3 2
3 3
4 1
4 2
4 3
4 4
5 1
5 2
5 3
5 4
5 5
6 1
6 2
6 3
6 4
6 5
6 6
7 1
7 2
7 3
7 4
7 5
7 6
7 7
8 1
8 2
8 3
8 4
8 5
8 6
8 7
8 8
9 1
9 2
9 3
9 4
9 5
9 6
9 7
9 8
9 9
10 1
10 2
10 3
10 4
10 5
10 6
10 7
10 8
10 9
10 10
11 1
11 2
11 3
11 4
11 5
11 6
11 7
11 8
11 9
11 10
11 11
12 1
...

output:

Yes
No
Yes
No
Yes
Yes
No
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
N...

result:

wrong answer expected YES, found NO [24th token]