QOJ.ac
QOJ
| ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
|---|---|---|---|---|---|---|---|---|---|
| #756804 | #5141. Identical Parity | frankly6 | WA | 5ms | 3652kb | C++17 | 955b | 2024-11-16 22:01:07 | 2024-11-16 22:01:07 |
Judging History
answer
#include<iostream>
#include<cstdio>
using namespace std;
const int MX=100050;
int T, N, K;
int read()
{
int r=0, f=1; char ch=getchar();
while(ch<'0'||ch>'9') {if(ch=='-') f=-1; ch=getchar();}
while(ch>='0'&&ch<='9') {r=r*10+ch-'0'; ch=getchar();}
return r*f;
}
int main()
{
// freopen("testdata.in","r",stdin);
T=read();
while(T--)
{
N=read(), K=read();
if(K%2==0) cout << "Yes\n";
else
{
int seg=N/K, det=N-N/K*K;
int n1=N/2, n2=N-N/2;
// cout << "det=" << det << ", n1=" << n1 << ", n2=" << n2 << ", seg=" << seg << '\n';
if(n1-(n1/seg*seg)<=det||n2-(n2/seg*seg)<=det) cout << "Yes\n";
else cout << "No\n";
}
}
return (0-0);
}
/*
n/k full length k parts
n-n/k :(n/k+1 same parity)
k-(n-n/k) :(n/k same parity)
n/2 : even
n-n/2 : odd
\det <= 1
*/
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3580kb
input:
3 3 1 4 2 5 3
output:
No Yes Yes
result:
ok 3 token(s): yes count is 2, no count is 1
Test #2:
score: -100
Wrong Answer
time: 5ms
memory: 3652kb
input:
100000 1 1 2 1 2 2 3 1 3 2 3 3 4 1 4 2 4 3 4 4 5 1 5 2 5 3 5 4 5 5 6 1 6 2 6 3 6 4 6 5 6 6 7 1 7 2 7 3 7 4 7 5 7 6 7 7 8 1 8 2 8 3 8 4 8 5 8 6 8 7 8 8 9 1 9 2 9 3 9 4 9 5 9 6 9 7 9 8 9 9 10 1 10 2 10 3 10 4 10 5 10 6 10 7 10 8 10 9 10 10 11 1 11 2 11 3 11 4 11 5 11 6 11 7 11 8 11 9 11 10 11 11 12 1 ...
output:
Yes No Yes No Yes Yes No Yes Yes Yes No Yes Yes Yes Yes No Yes No Yes Yes Yes No Yes Yes Yes Yes Yes Yes No Yes Yes Yes Yes Yes Yes Yes No Yes No Yes Yes Yes Yes Yes Yes No Yes No Yes No Yes Yes Yes Yes Yes No Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes No Yes No Yes Yes Yes Yes Yes Yes Yes Yes Yes No Y...
result:
wrong answer expected NO, found YES [31st token]