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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#756795 | #7904. Rainbow Subarray | wkr | TL | 0ms | 3676kb | C++20 | 3.5kb | 2024-11-16 21:58:29 | 2024-11-16 21:58:32 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define endl '\n'
#define close ios::sync_with_stdio(false), cin.tie(0), cout.tie(0)
const int N = 1e5 + 5;
int n, k, m;
vector<int> input;
int a[N];
struct SEG
{
#define lson id << 1
#define rson id << 1 | 1
int sum;
int sz;
} seg[N << 2];
int getIndex(int v)
{
return lower_bound(input.begin(), input.end(), v) - input.begin() + 1;
}
void up(int id)
{
seg[id].sum = seg[lson].sum + seg[rson].sum;
seg[id].sz = seg[lson].sz + seg[rson].sz;
}
void build(int id, int l, int r)
{
seg[id].sum = 0;
seg[id].sz = 0;
if (l == r)
return;
int mid = (l + r) >> 1;
build(lson, l, mid);
build(rson, mid + 1, r);
}
void change(int id, int l, int r, int x, int v, int le)
{
if (l == r)
{
seg[id].sum += v;
seg[id].sz += le;
return;
}
int mid = (l + r) >> 1;
if (x <= mid)
change(lson, l, mid, x, v, le);
else
change(rson, mid + 1, r, x, v, le);
up(id);
}
int querySum(int id, int l, int r, int ql, int qr)
{
if (ql <= l && r <= qr)
return seg[id].sum;
int mid = (l + r) >> 1, res = 0;
if (ql <= mid)
res += querySum(lson, l, mid, ql, qr);
if (qr > mid)
res += querySum(rson, mid + 1, r, ql, qr);
return res;
}
int querySz(int id, int l, int r, int ql, int qr)
{
if (ql <= l && r <= qr)
return seg[id].sz;
int mid = (l + r) >> 1, res = 0;
if (ql <= mid)
res += querySz(lson, l, mid, ql, qr);
if (qr > mid)
res += querySz(rson, mid + 1, r, ql, qr);
return res;
}
int findKth(int id, int l, int r, int index)
{
if (l == r)
return l;
int mid = (l + r) >> 1;
if (seg[lson].sz >= index)
return findKth(lson, l, mid, index);
else
return findKth(rson, mid + 1, r, index - seg[lson].sz);
}
bool check(int len)
{
build(1, 1, m);
for (int i = 1; i <= len; i++)
{
change(1, 1, m, getIndex(a[i]), a[i], 1);
}
int index = findKth(1, 1, m, (len + 1) / 2);
int nowMid = input[index - 1];
int cnt = querySz(1, 1, m, 1, index) * nowMid - querySum(1, 1, m, 1, index) +
querySum(1, 1, m, index, m) - querySz(1, 1, m, index, m) * nowMid;
for (int i = 1; i + len <= n; i++)
{
change(1, 1, m, getIndex(a[i]), -a[i], -1);
change(1, 1, m, getIndex(a[i + len]), a[i + len], 1);
index = findKth(1, 1, m, (len + 1) / 2);
nowMid = input[index - 1];
int ans = querySz(1, 1, m, 1, index) * nowMid - querySum(1, 1, m, 1, index) +
querySum(1, 1, m, index, m) - querySz(1, 1, m, index, m) * nowMid;
cnt = min(cnt, ans);
}
return cnt <= k;
}
void solved()
{
cin >> n >> k;
input.clear();
for (int i = 1; i <= n; i++)
{
cin >> a[i];
a[i] -= i;
input.push_back(a[i]);
}
sort(input.begin(), input.end());
input.erase(unique(input.begin(), input.end()), input.end());
m = input.size();
int l = 1, r = n, ans = 0;
while (l <= r)
{
int mid = (l + r) >> 1;
if (check(mid))
{
ans = mid;
l = mid + 1;
}
else
{
r = mid - 1;
}
}
cout << ans << endl;
}
signed main()
{
close;
int T;
cin >> T;
while (T--)
{
solved();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3676kb
input:
5 7 5 7 2 5 5 4 11 7 6 0 100 3 4 5 99 100 5 6 1 1 1 1 1 5 50 100 200 300 400 500 1 100 3
output:
4 3 5 1 1
result:
ok 5 lines
Test #2:
score: -100
Time Limit Exceeded
input:
11102 2 167959139 336470888 134074578 5 642802746 273386884 79721198 396628655 3722503 471207868 6 202647942 268792718 46761498 443917727 16843338 125908043 191952768 2 717268783 150414369 193319712 6 519096230 356168102 262263554 174936674 407246545 274667941 279198849 9 527268921 421436316 3613460...
output:
1 4 3 2 6 5 7 2 4 1 4 1 1 3 2 2 7 8 7 7 1 7 6 2 4 3 1 6 7 7 3 4 3 9 3 8 6 6 3 1 6 3 1 2 4 6 4 6 4 1 4 7 1 6 3 5 6 6 1 7 5 3 1 6 4 5 3 2 2 6 2 3 10 1 4 3 2 4 5 1 7 5 5 5 8 5 3 6 3 5 5 8 5 4 5 2 1 5 2 3 3 4 8 1 3 1 2 2 8 3 1 6 8 1 8 4 5 6 6 8 4 8 3 2 8 4 5 6 2 6 2 4 1 5 4 5 3 2 4 1 2 1 4 5 8 3 7 3 3 3...