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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#753647#9568. Left Shifting 3AlucardAC ✓2ms3860kbC++141.6kb2024-11-16 13:22:492024-11-16 13:22:50

Judging History

你现在查看的是最新测评结果

  • [2024-11-16 13:22:50]
  • 评测
  • 测评结果:AC
  • 用时:2ms
  • 内存:3860kb
  • [2024-11-16 13:22:49]
  • 提交

answer

#include <bits/stdc++.h>
#include <iostream>
 
using namespace std;
 
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
typedef pair<int,int> PII;
typedef pair<ll,ll> PLL;
#define i128 _int128
#define fi first
#define se second 
#define pb push_back
#define endl '\n'
//#define int long long

const ll INF=0x3f3f3f3f;
const ll N=1e5+9,M=1e9+9;
const ll mod=998244353;


int read(){
	int s=0,w=1;
	char c=getchar();
	while(!isdigit(c)) (c=='-')?w=-1:w=1,c=getchar();
	while(isdigit(c)) s=(s<<1)+(s<<3)+(c^48),c=getchar();
	return s*w;
}

int qpow(int a,int b){
    a%=mod;
    int res=1;
    while(b){
        if(b&1){res=(res*a)%mod;}
        a=(a*a)%mod;
        b>>=1;
    }
    return res%mod;
}

// int inverse(int a){
//     a%=mod;
// 	return qpow(fac[a%mod],mod-2)%mod;
// }

// int C(int n,int r){
//     n%=mod,r%=mod;
//     if(r>n)return 0;
//     return ((fac[n%mod]*inverse(r))%mod*inverse(n-r))%mod;
// }

// int Lucas(int n,int r){
//     if(r==0)return 1;
//     return C(n%mod,r%mod)%mod*Lucas(n/mod,r/mod)%mod;
// }

int n,k,ans;
string s,t="nanjing";

void solve(){
    cin>>n>>k>>s;ans=0;
    s+=s.substr(0,min(k,6));
    int idx=0;
    while(1){
        idx=s.find(t,idx);
        if(idx==-1)break;
        idx+=7,ans++;
    }
    cout<<ans<<endl;
}
 
 
signed main(){
    ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
    
    int _=1;
    // fac[0]=1;
    // for(int i=1;i<=N-9;++i)fac[i]=(fac[i-1]*i)%mod;
    cin>>_;
    
    while(_--)solve();
 
    return 0;
}

这程序好像有点Bug,我给组数据试试?

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3860kb

input:

4
21 10
jingicpcnanjingsuanan
21 0
jingicpcnanjingsuanan
21 3
nanjingnanjingnanjing
4 100
icpc

output:

2
1
3
0

result:

ok 4 number(s): "2 1 3 0"

Test #2:

score: 0
Accepted
time: 2ms
memory: 3604kb

input:

2130
39 7
nnananjingannanjingngnanjinganjinggjina
1 479084228
g
33 2
gqnanjinggrjdtktnanjingcvsenanjin
24 196055605
ginganjingnanjingnanjing
23 3
ngnanjinganjingjinnanji
40 3
njingaaznannanjingnananjingyonwpnanjinga
40 207842908
nanjinggphconanjingkonanjinannanjinglxna
46 3
ingjingnnanjingnanjinging...

output:

3
0
3
2
2
3
3
4
3
4
0
2
4
3
2
1
1
1
4
2
0
3
3
0
0
1
0
0
0
5
4
0
1
2
1
2
2
1
1
1
3
3
1
3
2
0
1
2
4
1
2
1
2
1
2
3
0
1
0
0
1
1
3
2
2
1
0
3
1
2
1
1
4
4
1
1
1
1
0
1
1
1
1
2
0
4
4
3
1
1
2
1
1
1
1
5
1
4
0
1
2
1
3
4
3
3
3
3
1
3
2
1
3
1
2
0
0
1
0
5
0
2
0
3
1
0
2
2
3
2
1
2
0
1
1
1
2
4
1
3
2
0
1
1
2
2
2
1
0
3
...

result:

ok 2130 numbers

Test #3:

score: 0
Accepted
time: 0ms
memory: 3672kb

input:

3
100000 998244353
gbppzfsncqyzmuwrcvtxsciucxusskcjhaanwhqmyncytwhkubrvcqxgcehdxyewdyvpqjcmrnmlgrytrucexmmfulqbtfctehphmrzkosyvhtvjrromqncbgsjcwhmlqidkycaxyhsrduoxayntuhqubvboseeziwjvrfagsbvtxjjbexnajqapgxydwtztzbbdpoydnjipfizdfpmczgqvdmpvxbqubtygkfpdeonegfzsttirbhzkobbigwneyvtcxndfkljdvbbcfnadtfhgo...

output:

4
1649
3651

result:

ok 3 number(s): "4 1649 3651"

Extra Test:

score: 0
Extra Test Passed