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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#752795#7780. Dark LaTeX vs. Light LaTeXyspmTL 0ms3828kbC++202.4kb2024-11-16 09:48:582024-11-16 09:48:58

Judging History

你现在查看的是最新测评结果

  • [2024-11-25 20:53:52]
  • hack成功,自动添加数据
  • (/hack/1258)
  • [2024-11-16 09:48:58]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:3828kb
  • [2024-11-16 09:48:58]
  • 提交

answer

#include <bits/stdc++.h>
#include <bits/extc++.h>
using namespace std; using namespace __gnu_pbds; using namespace __gnu_cxx;
#define For(i,x,y,...) for(int i=x,##__VA_ARGS__;i<=(y);++i)
#define rFor(i,x,y,...) for(int i=x,##__VA_ARGS__;i>=(y);--i)
#define Rep(i,x,y,...) for(int i=x,##__VA_ARGS__;i<(y);++i)
#define pb emplace_back
#define sz(a) int((a).size())
#define all(a) (a).begin(),(a).end()
#define fi first
#define se second
#define mkp make_pair
#define mem(a,x,n) memset(a,x,sizeof(*a)*(n+2))
typedef long long LL; typedef vector<int> Vi; typedef pair<int,int> Pii;
auto ckmax=[](auto &x,auto y) { return x<y ? x=y,true : false; };
auto ckmin=[](auto &x,auto y) { return y<x ? x=y,true : false; };
sfmt19937 mt(chrono::steady_clock::now().time_since_epoch().count());
int rnd(int l,int r) { return uniform_int_distribution<>(l,r)(mt); }

const int N = 5e3+5;
int n,m;
char s[N],t[N];
LL ans;

struct Hash {
	static const LL M = (1ll<<61)-1, B;
	static vector<LL> pw;
	vector<LL> h;
	LL add(LL x,LL y) { return x+y<M ? x+y : x+y-M; }
	LL mul(LL x,LL y) { __int128 z = (__int128)x*y; return add(z>>61,z&M); }
	Hash(char s[]):h(strlen(s+1)+1) {
		while( sz(pw) < sz(h) ) pw.pb(mul(pw.back(),B));
		h[0] = 0; Rep(i,1,sz(h)) h[i] = add(mul(h[i-1],B),s[i]);
	}
	LL operator () (int l,int r) { return add(h[r],M-mul(h[l-1],pw[r-l+1])); }
};
const LL Hash::B = uniform_int_distribution<LL>(M/2,M-1)(mt);
vector<LL> Hash::pw = {1};

struct Ft {
	int t[N*2];
	void clr() { mem(t,0,n*2); }
	void add(int i,int x) { for(;i;i-=i&-i)t[i]+=x; }
	int sum(int i) { int res=0; for(;i<=2*n;i+=i&-i)res+=t[i]; return res; }
} ft;

void slv(bool op) {
	n = strlen(s+1), m = strlen(t+1);
	vector<Vi> f(n+2,Vi(n+2,0));
	rFor(r,n,1) rFor(l,r,1) if( s[l] == s[r] ) f[l][r] = 1 + f[l+1][r+1];
	// For(i,1,n) { For(j,i,n) cerr<<f[i][j]<<" "; cerr<<'\n'; }
	Hash hs(s), ht(t);
	map<LL,int> cnt;
	rFor(r,n,1) {
		ft.clr();
		For(l,1,r) {
			cnt[hs(l,r)] += ft.sum(l) + op;
			// cerr<<l<<","<<r<<": "<<ft.sum(l) + op<<'\n';
			ft.add(f[l][r+1]+l,1);
		}
	}
	For(l,1,m) For(r,l,m) {
		auto it = cnt.find(ht(l,r));
		if( it != cnt.end() ) ans += it->se;
	}
}

void MAIN() {
scanf("%s%s",s+1,t+1);
	slv(0), swap(s,t), slv(1);
	cout<<ans<<'\n';
} signed main() {
#ifdef FS
	freopen("in","r",stdin); //freopen("out","w",stdout);
#endif
	ios::sync_with_stdio(0);cin.tie(0);
	int lft=1; while( lft-- ) {
		MAIN();
	}
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3748kb

input:

abab
ab

output:

8

result:

ok 1 number(s): "8"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3808kb

input:

abab
abaaab

output:

29

result:

ok 1 number(s): "29"

Test #3:

score: 0
Accepted
time: 0ms
memory: 3772kb

input:

abcd
abcde

output:

10

result:

ok 1 number(s): "10"

Test #4:

score: 0
Accepted
time: 0ms
memory: 3708kb

input:

aaba
ba

output:

6

result:

ok 1 number(s): "6"

Test #5:

score: 0
Accepted
time: 0ms
memory: 3828kb

input:

babababaaabbaabababbbaabbbababbaaaaa
aaaabbaababbab

output:

1161

result:

ok 1 number(s): "1161"

Test #6:

score: -100
Time Limit Exceeded

input:

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa...

output:


result: