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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#751744#7906. Almost ConvexguodongWA 403ms4348kbC++172.1kb2024-11-15 20:25:462024-11-15 20:25:46

Judging History

你现在查看的是最新测评结果

  • [2024-11-15 20:25:46]
  • 评测
  • 测评结果:WA
  • 用时:403ms
  • 内存:4348kb
  • [2024-11-15 20:25:46]
  • 提交

answer

#include<iostream>
#include <bits/stdc++.h>

#include<algorithm>
#include<cstdio>
#include<cmath>
#define For(i,a,b) for(int i = a; i <= b; ++i)

using namespace std;
int n;
struct ben
{
    int x,y,id;
}p[10005],s[10005];
double check(ben a1,ben a2,ben b1,ben b2)//检查叉积是否大于0,如果是a就逆时针转到b 
{
    return (a2.x-a1.x)*(b2.y-b1.y)-(b2.x-b1.x)*(a2.y-a1.y);
}
double d(ben p1,ben p2)//两点间距离。。。 
{
    return sqrt((p2.y-p1.y)*(p2.y-p1.y)+(p2.x-p1.x)*(p2.x-p1.x));
}
bool cmp(ben p1,ben p2)//排序函数,这个函数别写错了,要不然功亏一篑 
{
    double tmp=check(p[1],p1,p[1],p2);
    if(tmp>0) 
		return 1;
    if(tmp==0&&d(p[0],p1)<d(p[0],p2)) 
		return 1;
    return 0;
}
signed main()
{
#ifdef NICEGUODONG
freopen("data.in","r",stdin);
#endif	
    scanf("%d",&n);
    double mid;
    for(int i=1;i<=n;i++)
    {
        scanf("%d%d",&p[i].x,&p[i].y);
        p[i].id = i;
        if(i!=1&&p[i].y<p[1].y)//这是是去重 
        {
            mid=p[1].y;p[1].y=p[i].y;p[i].y=mid;
            mid=p[1].x;p[1].x=p[i].x;p[i].x=mid;
        }
    } 
    sort(p+2,p+1+n,cmp);//系统快排 
    s[1]=p[1];//最低点一定在凸包里 
    int cnt=1;
    for(int i=2;i<=n;i++)
    {
        while(cnt>1&&check(s[cnt-1],s[cnt],s[cnt],p[i])<=0) //判断前面的会不会被踢走,如果被踢走那么出栈
			cnt--;
        cnt++;
        s[cnt]=p[i];
    }
    s[cnt+1]=p[1];//最后一个点回到凸包起点
    vector<int> Mark(n + 1);
    For(i,1,cnt + 1){
        Mark[s[i].id] = 1;
    }
int ans = 1;
    for(int i = 1; i <= n; ++i){
        vector<pair<long double,int>> a;
        if(Mark[p[i].id]) continue;
        for(int j = 1; j <= n; ++j){
            if(i == j) continue;
            a.push_back(make_pair(atan2(p[j].x - p[i].x,p[j].y - p[i].y),p[j].id));
        }
        sort(a.begin(),a.end());
        for(int i = 0;i < (int)a.size(); ++i)
            if(Mark[a[i].second] && Mark[a[(i + 1) % a.size()].second]){
ans++;
            }
    }
    cout << ans << '\n';
    // printf("%.2lf\n",ans);
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 4256kb

input:

7
1 4
4 0
2 3
3 1
3 5
0 0
2 4

output:

9

result:

ok 1 number(s): "9"

Test #2:

score: 0
Accepted
time: 0ms
memory: 4176kb

input:

5
4 0
0 0
2 1
3 3
3 1

output:

5

result:

ok 1 number(s): "5"

Test #3:

score: 0
Accepted
time: 0ms
memory: 3960kb

input:

3
0 0
3 0
0 3

output:

1

result:

ok 1 number(s): "1"

Test #4:

score: 0
Accepted
time: 0ms
memory: 4192kb

input:

6
0 0
3 0
3 2
0 2
1 1
2 1

output:

7

result:

ok 1 number(s): "7"

Test #5:

score: 0
Accepted
time: 0ms
memory: 3748kb

input:

4
0 0
0 3
3 0
3 3

output:

1

result:

ok 1 number(s): "1"

Test #6:

score: -100
Wrong Answer
time: 403ms
memory: 4348kb

input:

2000
86166 617851
383354 -277127
844986 386868
-577988 453392
-341125 -386775
-543914 -210860
-429613 606701
-343534 893727
841399 339305
446761 -327040
-218558 -907983
787284 361823
950395 287044
-351577 -843823
-198755 138512
-306560 -483261
-487474 -857400
885637 -240518
-297576 603522
-748283 33...

output:

11729

result:

wrong answer 1st numbers differ - expected: '718', found: '11729'