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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#748752 | #7904. Rainbow Subarray | surenjamts# | TL | 971ms | 16964kb | C++17 | 2.7kb | 2024-11-14 21:19:06 | 2024-11-14 21:19:06 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
#include<ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
#define int long long
typedef tree<
int,
null_type,
less_equal<int>,
rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;
#define ll long long
#define pb push_back
#define mk make_pair
#define S second
#define F first
map<int, int> mp;
vector<int> t[2];
int n, k;
void upd(int v, int tl, int tr, int pos, int val, int psda){
if(tl == tr) t[psda][v] += val;
else {
int tm = (tl + tr)/2;
if(pos <= tm) upd(2 * v, tl, tm , pos, val, psda);
else upd(2 * v + 1, tm + 1, tr, pos, val, psda);
t[0][v] = t[0][2 * v] + t[0][2 * v + 1];
t[1][v] = t[1][2 * v] + t[1][2 * v + 1];
}
}
int get(int v, int tl, int tr, int l, int r, int psda){
if(l > r) return 0;
if(l == tl && r == tr) return t[psda][v];
int tm = (tl + tr)/2;
return get(2 *v, tl, tm, l, min(tm, r), psda) +
get(2 *v + 1, tm + 1, tr, max(tm + 1, l), r, psda);
}
void add(int val){
int i = mp[val];
// cout << "adding :" << i << " " << val << endl;
upd(1, 0, n - 1, i, val, 0);
upd(1, 0, n - 1, i, 1, 1);
}
void del(int val){
int i = mp[val];
upd(1, 0, n - 1, i, -val, 0);
upd(1, 0, n - 1, i, -1, 1);
}
void solve(){
cin >> n >> k;
mp.clear();
t[0].assign(4 * n + 5, 0);
t[1].assign(4 * n + 5, 0);
vector<int> v(n);
ordered_set s;
for(auto &i : v) cin >> i;
for(int i = 0; i < n; i++) v[i] -= i, mp[v[i]]++;
int index = 0;
for(auto it : mp){
mp[it.first] = index;
index++;
}
int l = 0;
int ans = 1;
for(int r = 0; r < n; r++){
s.insert(v[r]);
add(v[r]);
while(l < r){
int le=(r-l+1);
int med=*s.find_by_order(le/2);
//cout << "med :" << med << endl;
int sum1 = get(1, 0, n - 1, 0, mp[med] - 1, 0);
int sum2 = get(1, 0, n - 1, mp[med] + 1, n - 1, 0);
int cnt1 = get(1, 0, n - 1, 0, mp[med] - 1, 1);
int cnt2 = get(1, 0, n - 1, mp[med] + 1, n - 1, 1);
int cost = abs(cnt1 * med - sum1) + abs(sum2 - cnt2 * med);
// cout << l << " " << r << " " << sum1 << " " << sum2 << " " << cost << '\n';
if(cost <= k){
ans = max(ans, r - l + 1);
break;
}
s.erase(s.upper_bound(v[l]));
del(v[l]);
l++;
}
}
cout << ans << '\n';
}
int32_t main(){
ios::sync_with_stdio(0); cin.tie(NULL); cout.tie(NULL);
int t; cin >> t; while(t--) solve();
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3532kb
input:
5 7 5 7 2 5 5 4 11 7 6 0 100 3 4 5 99 100 5 6 1 1 1 1 1 5 50 100 200 300 400 500 1 100 3
output:
4 3 5 1 1
result:
ok 5 lines
Test #2:
score: 0
Accepted
time: 971ms
memory: 16964kb
input:
11102 2 167959139 336470888 134074578 5 642802746 273386884 79721198 396628655 3722503 471207868 6 202647942 268792718 46761498 443917727 16843338 125908043 191952768 2 717268783 150414369 193319712 6 519096230 356168102 262263554 174936674 407246545 274667941 279198849 9 527268921 421436316 3613460...
output:
1 4 3 2 6 5 7 2 4 1 4 1 1 3 2 2 7 8 7 7 1 7 6 2 4 3 1 6 7 7 3 4 3 9 3 8 6 6 3 1 6 3 1 2 4 6 4 6 4 1 4 7 1 6 3 5 6 6 1 7 5 3 1 6 4 5 3 2 2 6 2 3 10 1 4 3 2 4 5 1 7 5 5 5 8 5 3 6 3 5 5 8 5 4 5 2 1 5 2 3 3 4 8 1 3 1 2 2 8 3 1 6 8 1 8 4 5 6 6 8 4 8 3 2 8 4 5 6 2 6 2 4 1 5 4 5 3 2 4 1 2 1 4 5 8 3 7 3 3 3...
result:
ok 11102 lines
Test #3:
score: -100
Time Limit Exceeded
input:
1 500000 17244641009859 54748096 75475634 204928248 276927808 84875072 103158867 27937890 322595515 186026685 45468307 69240390 139887597 188586447 373764525 121365644 310156469 185188306 60350786 211308832 384695957 370562147 208427221 35937909 267590963 126478310 275357775 55361535 335993561 36696...