// Such a destiny was not desired.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
constexpr int N = 1e3 + 5;
int n, p[N];

inline int ask(int m, int x, int y) {
  cout << 0 << " ";
  for(int i = 1; i <= m; i++) cout << x << " ";
  for(int i = m + 1; i <= n; i++) cout << y << " ";
  cout << endl;
  int ret; cin >> ret;
  return ret;
}

struct DUS {
  int f[N];
  inline void init(int n) {iota(f + 1, f + n + 1, 1);}
  inline int find(int x) {while(x != f[x]) x = f[x] = f[f[x]]; return x;}
  inline void merge(int x, int y) {
    x = find(x), y = find(y);
    f[y] = x;
  }
} D;

int g[N];
void solve(int l, int r, vector<int> S) {
  if(l == r) return p[l] = S[0], void();
  int m = l + r >> 1;
  vector<int> o = S;

  vector<int> L, R;
  while(S.size() > 1) {
    int itx = rng() % S.size(), ity = rng() % S.size();
    while(itx == ity) itx = rng() % S.size(), ity = rng() % S.size();
    int x = S[itx], y = S[ity];

    int e = ask(m, x, y);
    if(e == 0) {
      g[x] = 1, g[y] = 0;
      if(itx < ity) swap(itx, ity);
      S.erase(S.begin() + itx), S.erase(S.begin() + ity);
    } else if(e == 2) {
      g[x] = 0, g[y] = 1;
      if(itx < ity) swap(itx, ity);
      S.erase(S.begin() + itx), S.erase(S.begin() + ity);
    } else {
      D.merge(x, y);
      S.erase(S.begin() + ity);
    }
  }
  if(S.size() == 1) {
    int x = -1;
    for(auto y : o) {
      if(y != S[0]) {
        x = y;
        break;
      }
    }
    int e = ask(m, S[0], x);
    if(e == 0) g[S[0]] = 1;
    else if(e == 2) g[S[0]] = 0;
    else D.merge(x, S[0]);
  }

  for(auto x : o) {
    g[x] = g[D.find(x)];
    if(g[x] == 0) L.push_back(x);
    else R.push_back(x);
  }
  for(auto x : o) {
    D.f[x] = x;
  }
  solve(l, m, L);
  solve(m + 1, r, R);
}

int main() {
  // ios::sync_with_stdio(false);
  // cin.tie(nullptr), cout.tie(nullptr);
  
  cin >> n;
  vector<int> U(n);
  iota(U.begin(), U.end(), 1);
  D.init(n);
  solve(1, n, U);
  cout << 1 << " ";
  for(int i = 1; i <= n; i++) cout << p[i] << " ";
  cout << endl;
}