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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#74409#5422. Perfect Palindromemagicduck#AC ✓9ms3456kbC++14971b2023-02-01 12:39:082023-02-01 12:39:09

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-02-01 12:39:09]
  • 评测
  • 测评结果:AC
  • 用时:9ms
  • 内存:3456kb
  • [2023-02-01 12:39:08]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
template <typename T> inline void read(T &F) {
    int R = 1; F = 0; char CH = getchar();
    for(; !isdigit(CH); CH = getchar()) if(CH == '-') R = -1;
    for(; isdigit(CH); CH = getchar()) F = F * 10 + CH - 48;
    F *= R;
}
inline void file(string str) {
    freopen((str + ".in").c_str(), "r", stdin);
    freopen((str + ".out").c_str(), "w", stdout);
}
const int N = 30, M = 1e6 + 10;
int cnt[N]; char s[M];
int main() {
    //file("");
    int T; read(T);
    while(T--) {
        memset(cnt, 0, sizeof(cnt));
        scanf("%s", s + 1); int n = strlen(s + 1);
        for(int i = 1; i <= n; i++) cnt[s[i] - 'a']++;
        int res = 0;
        for(int i = 0; i < 26; i++) res = max(res, cnt[i]);
        cout << n - res << '\n';
    }
    
    #ifdef _MagicDuck
        fprintf(stderr, "# Time: %.3lf s", (double)clock() / CLOCKS_PER_SEC);
    #endif
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 2ms
memory: 3456kb

input:

2
abcb
xxx

output:

2
0

result:

ok 2 number(s): "2 0"

Test #2:

score: 0
Accepted
time: 9ms
memory: 3372kb

input:

11107
lfpbavjsm
pdtlkfwn
fmb
hptdswsoul
bhyjhp
pscfliuqn
nej
nxolzbd
z
clzb
zqomviosz
u
ek
vco
oymonrq
rjd
ktsqti
mdcvserv
x
birnpfu
gsgk
ftchwlm
bzqgar
ovj
nsgiegk
dbolme
nvr
rpsc
fprodu
eqtidwto
j
qty
o
jknssmabwl
qjfv
wrd
aa
ejsf
i
npmmhkef
dzvyon
p
zww
dp
ru
qmwm
sc
wnnjyoepxo
hc
opvfepiko
inuxx...

output:

8
7
2
8
4
8
2
6
0
3
7
0
1
2
5
2
4
6
0
6
2
6
5
2
5
5
2
3
5
6
0
2
0
8
3
2
0
3
0
6
5
0
1
1
1
2
1
8
1
7
5
3
4
4
1
8
5
5
8
8
6
3
0
2
3
2
1
5
0
0
9
3
3
4
8
4
0
4
2
6
6
0
8
7
4
3
9
3
4
2
5
8
8
8
6
1
4
4
2
7
2
8
6
4
4
8
7
8
4
9
3
8
0
7
7
2
6
0
0
5
4
0
7
5
4
2
1
6
7
5
2
4
4
7
3
3
2
5
4
8
5
0
3
5
1
2
3
0
4
7
...

result:

ok 11107 numbers