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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#744072#8986. Call for Problemst-aswathAC ✓0ms3680kbC++141.1kb2024-11-13 20:45:442024-11-13 20:45:44

Judging History

This is the latest submission verdict.

  • [2024-11-13 20:45:44]
  • Judged
  • Verdict: AC
  • Time: 0ms
  • Memory: 3680kb
  • [2024-11-13 20:45:44]
  • Submitted

answer

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> 
#include <ext/pb_ds/tree_policy.hpp>

using namespace __gnu_pbds;
using namespace std;

#ifdef LOCAL
#include "debug.h"
#else
#define deb(x...) 42
#endif

#define fast_io ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define ll long long
#define F first
#define S second
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()

typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;


void solve(int t) {
    ll n;
    cin>>n;
    ll ans=0;
    for(ll i=0;i<n;i++){
        ll x;
        cin>>x;
        ans+=(x%2);
    }
    cout<<ans<<endl;

}

int main() {
  fast_io;
#ifdef LOCAL
  freopen("input.txt", "r", stdin);
  freopen("output.txt", "w", stdout);
  freopen("output.txt", "w", stderr);
#endif
  ll t = 1;
  //cin >> t;
  for(ll i = 0; i < t; i++) {
#ifdef LOCAL
    cout << "CASE " << i + 1 << ":\n";
#endif
    solve(i);
  }
#ifdef LOCAL
  cout << endl << "Finished in " << clock() * 1.0 / CLOCKS_PER_SEC << " sec\n\n";
#endif
  return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3552kb

input:

2
2
3

output:

1

result:

ok single line: '1'

Test #2:

score: 0
Accepted
time: 0ms
memory: 3680kb

input:

3
2
4
5

output:

1

result:

ok single line: '1'

Test #3:

score: 0
Accepted
time: 0ms
memory: 3680kb

input:

1
3

output:

1

result:

ok single line: '1'

Test #4:

score: 0
Accepted
time: 0ms
memory: 3552kb

input:

4
5
7
8
9

output:

3

result:

ok single line: '3'

Test #5:

score: 0
Accepted
time: 0ms
memory: 3676kb

input:

50
4
29
3
10
69
82
74
34
89
62
55
34
30
24
58
81
10
22
39
80
94
29
46
8
18
12
18
87
100
92
21
19
13
92
95
52
30
97
85
71
49
68
42
59
97
44
5
98
42
87

output:

21

result:

ok single line: '21'