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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#743309 | #9432. Permutation | KellyWLJ | RE | 0ms | 3840kb | C++17 | 2.5kb | 2024-11-13 18:54:28 | 2024-11-13 18:54:29 |
Judging History
answer
#include <bits/stdc++.h>
#define fi first
#define se second
#define pb push_back
using namespace std;
const int N = 1010; using pii = pair<int, int>;
mt19937 rnd(std::chrono::steady_clock().now().time_since_epoch().count());
int n, vis[N], b[N], a[N], p[N];
int ask(int x, int y, int els, int l, int mid, int r) {
memset(p, 0, sizeof(p));
static int T = 0; ++T;
assert(T <= 6666);
for(int i = l; i <= mid; ++i) p[i] = x;
for(int i = mid + 1; i <= r; ++i) p[i] = y;
for(int i = 1; i <= n; ++i) if(!p[i]) p[i] = els;
cout << "0 ";
for(int i = 1; i <= n; ++i) cout << p[i] << " ";
cout << endl; int res = 0;
#ifdef Kelly
for(int i = 1; i <= n; ++i) res += p[i] == b[i];
return res;
#endif
cin >> res; return res;
}
void solve(int l, int r, vector<int> p) {
if(l > r || p.empty()) return;
if(l == r) return void(a[l] = p[0]);
int mid = (l + r) >> 1;
if((r - l + 1) % 2 && (mid - l + 1) % 2) --mid;
else if((mid - l + 1) % 2 == 0 && (r - mid) % 2 == 0) ++mid;
vector<int> tmpl, tmpr; vector<pii> lsh;
int nw = p[0];
auto del = [&](int x) -> void {swap(p[x], p.back()), p.pop_back();};
// cerr << l << " " << r << " " << mid << "\n";
// for(int x : p) cerr << x << " ";
// cerr << "\n";
while(p.size() > 1) {
int x = rnd() % p.size(), y = rnd() % p.size();
while(y == x) y = rnd() % p.size();
if(x > y) swap(x, y);
int sum = ask(p[x], p[y], nw, l, mid, r);
if(sum == 0) tmpl.pb(p[y]), tmpr.pb(p[x]);
else if(sum == 2) tmpl.pb(p[x]), tmpr.pb(p[y]);
else lsh.pb({p[x], p[y]});
del(y), del(x);
}
if(tmpr.empty() && p.size()) nw = p[0];
for(auto [x, y] : lsh) {
int res = ask(tmpr.size() ? tmpr[0] : nw, x, nw, l, mid, r);
if(res == 0) tmpl.pb(x), tmpl.pb(y);
else tmpr.pb(x), tmpr.pb(y);
}
if(p.size()) tmpl.size() != mid - l + 1 ? tmpl.pb(p[0]) : tmpr.pb(p[0]);
solve(l, mid, tmpl), solve(mid + 1, r, tmpr);
}
int main() {
#ifdef Kelly
freopen("in.txt", "r", stdin);
freopen("out.txt", "w", stdout);
freopen("err.txt", "w", stderr);
#endif
cin >> n;
#ifdef Kelly
for(int i = 1; i <= n; ++i) cin >> b[i];
#endif
vector<int> tmp;
for(int i = 1; i <= n; ++i) tmp.pb(i);
solve(1, n, tmp);
cout << "1 ";
for(int i = 1; i <= n; ++i) cout << a[i] << " ";
cout << endl;
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3840kb
input:
5 2 1 1 2 1 0 0
output:
0 3 3 5 5 5 0 1 1 2 2 2 0 5 5 1 1 1 0 3 4 3 3 3 0 5 5 1 1 2 0 5 5 5 5 1 0 1 1 1 2 1 1 3 4 2 1 5
result:
ok Accepted
Test #2:
score: -100
Runtime Error
input:
1000 1 1 1 2 1 1 1 1 0 0 1 0 1 2 2 1 2 1 1 0 2 1 0 1 1 2 2 1 2 1 2 1 1 1 1 0 2 1 1 1 1 1 1 0 2 0 2 1 2 1 0 2 0 1 1 1 1 0 1 2 1 0 0 0 1 1 1 1 1 2 1 1 1 0 1 1 0 0 1 0 0 0 2 1 2 1 2 1 0 2 1 0 1 2 1 2 0 1 2 0 2 1 0 1 1 0 1 0 1 2 2 1 2 1 0 1 1 2 0 1 1 0 1 1 0 2 1 1 2 1 0 2 1 0 1 1 2 2 0 1 2 0 1 0 1 1 2 1...
output:
0 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 281 28...