QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#742721 | #9738. Make It Divisible | Godwang | WA | 0ms | 3556kb | C++23 | 9.8kb | 2024-11-13 17:09:35 | 2024-11-13 17:09:40 |
Judging History
你现在查看的是最新测评结果
- [2024-11-27 18:44:44]
- hack成功,自动添加数据
- (/hack/1263)
- [2024-11-14 09:10:13]
- hack成功,自动添加数据
- (/hack/1178)
- [2024-11-13 17:09:35]
- 提交
answer
#include <iostream>
using namespace std;
#include <set>
#include <algorithm>
#include <cmath>
#include <map>
#include <cstdio>
#include <string>
#include <cstring>
#include <string.h>
#include <stdlib.h>
#include <iomanip>
#include <fstream>
#include <stdio.h>
#include <stack>
#include <queue>
#include <ctype.h>
#include <vector>
#include <random>
#include<list>
#define ll long long
#define ull unsigned long long
#define pb push_back
#define rep(i, a, n) for (int i = a; i <= n; i++)
#define per(i, a, n) for (int i = n; i >= a; i--)
#define pii pair<int, int>
#define pli pair<ll, int>
#define pil pair<int, ll>
#define pll pair<ll, ll>
#define lowbit(x) ((x)&(-x))
ll extend_gcd(ll a, ll b, ll &x, ll &y)
{
if (b == 0)
{
x = 1;
y = 0;
return a;
}
ll d = extend_gcd(b, a % b, y, x);
y -= a / b * x;
return d;
}
ll fastpow(ll a, ll n, ll mod)
{
ll ans = 1;
a %= mod;
while (n)
{
if (n & 1)
ans = (ans * a) % mod; //% mod
a = (a * a) % mod; //% mod
n >>= 1;
}
return ans;
}
inline void write(__int128 x)
{
if (x > 9)
{
write(x / 10);
}
putchar(x % 10 + '0');
}
__int128 sqrt(__int128 m)
{
__int128 leftt = 0, rightt = ((__int128)1) << 51, ret = -1, mid;
while (leftt < rightt)
{
mid = (leftt + rightt) / 2;
if (mid * mid > m)
{
rightt = mid;
}
else
{
leftt = mid + 1;
ret = mid;
}
}
return ret;
}
const double eps = 1e-6;
int sgn(double x)
{
if(fabs(x)<eps)
{
return 0;
}
else return x<0?-1:1;
}
struct Point
{
double x,y;
Point()
{
}
Point(double x,double y):x(x),y(y)
{
}
Point operator + (Point B)
{
return Point(x+B.x,y+B.y);
}
Point operator - (Point B)
{
return Point(x-B.x,y-B.y);
}
bool operator == (Point B)
{
return sgn(x-B.x)==0&&sgn(y-B.y)==0;
}
bool operator < (Point B)
{
return sgn(x-B.x)<0||(sgn(x-B.x)==0&&sgn(y-B.y)<0);
}
};
typedef Point Vector;
double Cross(Vector A,Vector B)//叉积
{
return A.x*B.y-A.y*B.x;
}
double Distance(Point A,Point B)
{
return hypot(A.x-B.x,A.y-B.y);
}
int Convex_hull(Point *p,int n,Point *ch)
{
n=unique(p,p+n)-p;
sort(p,p+n);
int v=0;
for(int i=0;i<n;i++)
{
while (v>1&&sgn(Cross(ch[v-1]-ch[v-2],p[i]-ch[v-1]))<=0)
{
v--;
}
ch[v++]=p[i];
}
int j=v;
for(int i=n-2;i>=0;i--)
{
while (v>j&&sgn(Cross(ch[v-1]-ch[v-2],p[i]-ch[v-1]))<=0)
{
v--;
}
ch[v++]=p[i];
}
if(n>1)
{
v--;
}
return v;
}
int kmp(string s, string p)
{
int ans = 0, lastt = -1;
int lenp = p.size();
vector<int > Next(lenp+3,0);
rep(i, 1, lenp - 1)
{
int j = Next[i];
while (j && p[j] != p[i])
{
j = Next[j];
}
if (p[j] == p[i])
{
Next[i + 1] = j + 1;
}
else
{
Next[i + 1] = 0;
}
}
int lens = s.size();
int j = 0;
rep(i, 0, lens - 1)
{
while (j && s[i] != p[j])
{
j = Next[j];
}
if (s[i] == p[j])
{
j++;
}
if (j == lenp)
{
ans++;
}
}
return ans;
}
int dir[4][2] =
{
{-1, 0}, {0, 1}, {1, 0}, {0, -1}}; // 左右上下
// int dir[8][2]={
// {-1, 0}, {0, 1}, {1, 0}, {0, -1},{-1,-1},{-1,1},{1,-1},{1,1}
// };
#define endl '\n'//交互题请删除本行
const ll inf = 1000000000000000000ll;
const ll mod1 = 998244353ll, P1 = 131, mod2 = 1e9 + 7ll, P2 = 13331;
ll inverse(ll x)
{
return fastpow(x,mod1-2,mod1);
}
const int N = 1e5 + 10, M = 1e6 + 10;
///////////////////////////////////
#define i64 ll
int tt;
int n;
ll k;
ll b[N],cnt,num[N];
ll yinshu[N],cntyinshu;
ll cntt;
ll zhi[N];
///////////////////////////////////
i64 mul(i64 a,i64 b,i64 m)
{
return static_cast<__int128>(a)*b%m;
}
i64 power(i64 a,i64 b,i64 m)
{
i64 res=1%m;
for(;b;b>>=1,a=mul(a,a,m))
if(b&1)
res=mul(res,a,m);
return res;
}
bool isprime(i64 n)
{
if(n<2)
return false;
static constexpr int A[]={2,3,5,7,11,13,17,19,23};
int s=__builtin_ctzll(n-1);
i64 d=(n-1)>>s;
for(auto a:A)
{
if(a==n)
return true;
i64 x=power(a,d,n);
if(x==1||x==n-1)
continue;
bool ok=0;
for(int i=0;i<s-1;i++)
{
x=mul(x,x,n);
if(x==n-1)
{
ok=1;
break;
}
}
if(!ok)
return 0;
}
return 1;
}
std::vector<i64> p;
void f(i64 n)
{
if(n<=10000)
{
for(int i=2;i*i<=n;i++)
for(;n%i==0;n/=i)
p.pb(i);
if(n>1)
p.pb(n);
return;
}
if(isprime(n))
{
p.pb(n);
return;
}
auto g=[&](i64 x)
{
return (mul(x,x,n)+1)%n;
};
i64 x0=2;
while (true)
{
i64 x=x0;
i64 y=x0;
i64 d=1;
i64 power=1,lam=0;
i64 v=1;
while (d==1)
{
y=g(y);
++lam;
v=mul(v,abs(x-y),n);
if(lam%127==0)
{
d=__gcd(v,n);
v=1;
}
if(power==lam)
{
x=y;
power*=2;
lam=0;
d=__gcd(v,n);
v=1;
}
}
if(d!=n)
{
f(d);
f(n/d);
return;
}
++x0;
}
};
std::vector<i64> factorize(i64 n)
{
p.clear();
f(n);
sort(p.begin(),p.end());
return p;
}
void dfs(int ceng,ll shu)
{
if(ceng==cnt+1)
{
yinshu[++cntyinshu]=shu;
return;
}
ll temp=1;
rep(i,0,num[ceng])
{
dfs(ceng+1,shu*temp);
temp*=b[ceng];
}
}
///////////////////////////////////
void init()
{
}
///////////////////////////////////
int main()
{
ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);//交互题请删除本行
// freopen("ain.txt", "r", stdin); freopen("aout.txt", "w", stdout);
cin>>tt;
while (tt--)
{
ll minn=1000000000ll,gcdd=0,maxx=0;
cin>>n>>k;
rep(i,1,n)
{
cin>>zhi[i];
if(i>1)
gcdd=__gcd(gcdd,abs(zhi[i-1]-zhi[i]));
minn=min(minn,zhi[i]);
}
if(gcdd==0)
{
ll ans=(1+k)*k/2;
cout<<k<<" "<<ans<<endl;
continue;
}
//
// cout<<gcdd<<endl;
vector<ll > a=factorize(gcdd);
cntt=a.size();
cnt=0;
for(int i=0;i<cntt;i++)
{
if(i==0||a[i]!=a[i-1])
{
cnt++;
b[cnt]=a[i];
num[cnt]=1;
}
else
{
num[cnt]++;
}
}
cntyinshu=0;
dfs(1,1);
int geshu=0;
ll sum=0;
rep(j,1,cntyinshu)
{
// cout<<yinshu[j]<<" ";
if(yinshu[j]>=minn+1)
{
ll add=yinshu[j]-minn;
if(add>k)
{
continue;
}
rep(ii,1,n)
{
zhi[ii]+=add;
}
bool flag=1;
set<ll > se;
se.insert(zhi[1]);
rep(ii,2,n)
{
auto it=se.lower_bound(zhi[ii]);
ll temp;
if(it==se.end())
{
--it;
temp=*it;
if(zhi[ii]%temp)
{
flag=0;
break;
}
}
else
{
temp=*it;
if(temp%zhi[ii])
{
flag=0;
break;
}
if(it!=se.begin())
{
--it;temp=*it;
if(temp%zhi[ii])
{
flag=0;
break;
}
}
}
se.insert(zhi[ii]);
}
rep(ii,1,n)
{
zhi[ii]-=add;
}
if(flag)
{
geshu++;
sum+=add;
}
}
}
// cout<<endl;
cout<<geshu<<" "<<sum<<endl;
}
return 0;
}
詳細信息
Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 3556kb
input:
3 5 10 7 79 1 7 1 2 1000000000 1 2 1 100 1000000000
output:
0 0 0 0 100 5050
result:
wrong answer 1st lines differ - expected: '3 8', found: '0 0'