QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#742656#7757. Palm Islandqikala7777WA 1ms5600kbC++231.2kb2024-11-13 17:01:212024-11-13 17:01:22

Judging History

你现在查看的是最新测评结果

  • [2024-11-13 17:01:22]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:5600kb
  • [2024-11-13 17:01:21]
  • 提交

answer

//16:35
#include<bits/stdc++.h>
#define IOS ios::sync_with_stdio(false);cin.tie(0);
#define endl '\n'
using namespace std;
typedef long long LL;
typedef unsigned long long ULL;
typedef tuple<int,LL,LL> TPL;
typedef pair<LL,LL> PII;
const int N=1e6+7,inf=0x3f3f3f3f;const LL Linf=0x3f3f3f3f3f3f3f3fLL;
LL qsm(LL a,LL b,LL p){LL res=1;while(b){if(b&1)res=res*a%p;a=a*a%p;b>>=1;}return res;}
LL lowbit(LL x){return x&-x;}
int n;
int a[N],b[N];
deque<int>q;
string ans;
void op1(){
    int x=q.front();
    q.pop_front();
    q.push_back(x);
    ans+='1';
}
void op2(){
    int x=q.front();
    q.pop_front();
    int y=q.front();
    q.pop_front();
    q.push_back(y);
    q.push_front(x);
    ans+='2';
}
void solve(){
    cin>>n;
    q.clear();
    for(int i=1;i<=n;i++)cin>>a[i],q.push_back(a[i]);
    for(int i=1;i<=n;i++)cin>>b[i];
    for(int i=1;i<=n;i+=2){
        while(q.front()!=b[i]){
            op1();
        }
        while(i+1<=n&&q[1]!=b[i+1]){
            op2();
        }
        op1();
        if(i+1<=n)op1();
    }
    while(q[0]!=b[1]){
        op1();
    }
    cout<<ans<<endl;
}
int main(){
   IOS
   int T=1;
   cin>>T;
    while(T--)solve();

    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 5584kb

input:

2
3
1 2 3
2 3 1
4
1 2 3 4
2 1 3 4

output:

1111
11111221111

result:

ok Correct. (2 test cases)

Test #2:

score: -100
Wrong Answer
time: 0ms
memory: 5600kb

input:

200
3
3 1 2
2 3 1
4
2 4 1 3
2 1 4 3
4
1 4 2 3
2 1 3 4
5
4 3 2 1 5
2 4 5 3 1
5
2 1 5 4 3
5 2 4 1 3
4
4 3 1 2
1 2 4 3
3
1 2 3
3 1 2
4
1 4 2 3
2 1 4 3
4
1 3 2 4
1 4 3 2
3
3 2 1
1 3 2
3
2 3 1
1 3 2
4
1 4 3 2
3 1 2 4
3
1 2 3
1 3 2
3
3 2 1
2 3 1
5
5 1 3 2 4
2 4 5 1 3
4
4 3 1 2
1 4 3 2
4
1 3 4 2
2 4 3 1
3
...

output:

11111
1111121112211
11111211122111121112211
111112111221111211122111122111122111
1111121112211112111221111221111221111122111222111
1111121112211112111221111221111221111122111222111111111
111112111221111211122111122111122111112211122211111111111111
1111121112211112111221111221111221111122111222111111...

result:

wrong answer On Case#2: After your operations, a[1] = 4 but a[1] = 2. (test case 2)