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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#742222 | #9619. 乘积,欧拉函数,求和 | lywyw | TL | 0ms | 1604kb | C++14 | 729b | 2024-11-13 16:07:32 | 2024-11-13 16:07:32 |
Judging History
answer
#include <stdio.h>
#define MOD 998244353
long long oula(int n) {
int a,b,r,ans=0;
int i;
for(i=1;i<=n;i++){
a=n;
b=i;
while(b!=0){
r=a%b;
a=b;
b=r;
}
if(a==1) ans++;
}
return ans;
}
int a[2000];
int n;
long long result = 0;
void dfs(int step, int sum) {
if (step == n) {
if (sum == 1) {
result = (result + 1) ;
} else {
result = (result + oula(sum)) ;
}
return;
}
dfs(step + 1, sum);
dfs(step + 1, sum * a[step]);
}
int main() {
scanf("%d", &n);
for (int i = 0; i < n; i++) {
scanf("%d", &a[i]);
}
dfs(0, 1);
printf("%lld\n", result%MOD);
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 1604kb
input:
5 1 6 8 6 2
output:
892
result:
ok single line: '892'
Test #2:
score: 0
Accepted
time: 0ms
memory: 1536kb
input:
5 3 8 3 7 8
output:
3157
result:
ok single line: '3157'
Test #3:
score: -100
Time Limit Exceeded
input:
2000 79 1 1 1 1 1 1 2803 1 1 1 1 1 1 1609 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2137 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 613 1 499 1 211 1 2927 1 1 1327 1 1 1123 1 907 1 2543 1 1 1 311 2683 1 1 1 1 2963 1 1 1 641 761 1 1 1 1 1 1 1 1 1 1 1 1489 2857 1 1 1 1 1 1 1 1 1 1 1 1 1 967 1 821 1 1 1 1 2143 1861...