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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#741832#9432. PermutationremmymilkywayRE 1ms3804kbC++231.9kb2024-11-13 15:19:062024-11-13 15:19:07

Judging History

你现在查看的是最新测评结果

  • [2024-11-13 15:19:07]
  • 评测
  • 测评结果:RE
  • 用时:1ms
  • 内存:3804kb
  • [2024-11-13 15:19:06]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int maxn = 1e3 + 5;
mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count());
int n, ans[maxn];
int ask(int mid, int x, int y) {
    printf("0 ");
    for (int i = 1; i <= mid; i++) {
        printf("%d ", x);
    }
    for (int i = mid + 1; i <= n; i++) {
        printf("%d ", y);
    }
    printf("\n");
    fflush(stdout);
    int res;
    scanf("%d", &res);
    return res;
}
void query(int l, int r, vector<int> val) {
    if (l == r) {
        ans[l] = val[0];
        return;
    }
    int mid = (l + r) >> 1;
    shuffle(val.begin(), val.end(), rng);
    vector<int> pos0, pos1;
    int idx = 0, lst = 0;
    while (idx + 1 < (int)val.size()) {
        int cur = ask(mid, val[idx], val[idx + 1]);
        if (cur == 0) {
            for (int i = lst; i <= idx; i++) {
                pos1.push_back(val[i]);
            }
            pos0.push_back(val[idx + 1]);
            idx += 2;
            lst = idx;
        } else if (cur == 2) {
            for (int i = lst; i <= idx; i++) {
                pos0.push_back(val[i]);
            }
            pos1.push_back(val[idx + 1]);
            idx += 2;
            lst = idx;
        } else {
            idx++;
        }
    }
    if ((int)pos0.size() < mid - l + 1) {
        for (int i = lst; i <= idx; i++) {
            pos0.push_back(val[i]);
        }
    } else {
        for (int i = lst; i <= idx; i++) {
            pos1.push_back(val[i]);
        }
    }
    query(l, mid, pos0);
    query(mid + 1, r, pos1);
}
int main() {
    scanf("%d", &n);
    vector<int> cur;
    for (int i = 1; i <= n; i++) {
        cur.push_back(i);
    }
    query(1, n, cur);
    printf("1 ");
    for (int i = 1; i <= n; i++) {
        printf("%d ", ans[i]);
    }
    printf("\n");
    fflush(stdout);
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3804kb

input:

5
0
0
0
2
0

output:

0 1 1 1 4 4 
0 5 5 5 3 3 
0 2 2 3 3 3 
0 3 4 4 4 4 
0 5 5 5 5 1 
1 3 4 2 1 5 

result:

ok Accepted

Test #2:

score: -100
Runtime Error

input:

1000
1
2
0
2
0
1
2
1
0
1
1
2
0
1
1
2
2
1
1
0
0
1
1
2
1
1
2
2
2
2
1
2
1
0
1
1
1
1
0
1
1
0
0
0
2
0
1
2
0
2
1
0
1
1
0
0
1
0
0
2
1
0
0
2
1
2
1
1
1
2
0
1
1
1
1
1
2
1
0
2
2
1
1
1
1
2
1
2
2
0
0
0
2
0
0
1
0
1
1
1
0
2
2
2
2
1
2
1
0
1
1
1
1
0
0
1
1
1
1
2
0
1
2
2
2
0
0
2
2
0
1
1
1
0
2
2
1
2
2
1
1
1
1
1
1
1
1
1...

output:

0 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 243 24...

result: