#include <bits/stdc++.h>
#define ms(x, v) memset(x, v, sizeof(x))
#define il __attribute__((always_inline)) static
#define U(i,l,r) for(int i(l),END##i(r);i<=END##i;++i)
#define D(i,r,l) for(int i(r),END##i(l);i>=END##i;--i)
using namespace std;
using ll = long long;

#define IC isdigit(c)
#define GC c=getchar()
void rd(auto &x) { x = 0; char GC; bool f = 0;
	for (; !IC; GC) f |= c == '-';
	for (; IC; GC) x = x * 10 + c - 48;
	if (f) x = -x;
}
void rd(auto &x, auto &...y) { rd(x); rd(y...); }
#define meow(...) fprintf(stderr, __VA_ARGS__)
#define Assert(e, v) if (!(e)) { meow("AF@%d\n", __LINE__ ); exit(v); }

#define vc vector
#define eb emplace_back
#define pb push_back

const int N = 1003;
int n, a[N], p[N];
int q[N];

int ask() {
	printf("0");
	U (i, 1, n) printf(" %d", q[i]);
	puts(""); fflush(stdout);
	int x; rd(x);
	return x;
}
void report() {
	printf("1");
	U (i, 1, n) printf(" %d", p[i]);
	puts(""); fflush(stdout);
	exit(0);
}

mt19937 rng(114514);

int b[N];
void solve(int l, int r) {
	if (l == r) { p[l] = a[l]; return; }
	shuffle(a + l, a + r + 1, rng);
	U (i, 1, n) q[i] = a[l];
	int mid((l + r) >> 1), x = l, y = mid + 1;
	for (int i = l, j; i <= r; i = j + 1) {
		j = i + 1; int las = 1;
		do {
			if (j > r) break;
			U (k, l, mid) q[k] = a[i];
			U (k, mid + 1, r) q[k] = a[j];
			las = ask();
		} while ((las == 1) && ++j);
		if (j > r) {
			// 要么 i 在左边，剩下的全在右边
			// 要么 i 在右边，剩下的全在左边
			if (i == r - 1) {
				assert(i != l); // 要么两个都对，要么两个都不对
				if (x + 1 == mid) {
					b[x++] = a[i];
					b[x++] = a[i + 1];
				} else {
					assert(y + 1 == r);
					b[y++] = a[i];
					b[y++] = a[i];
				}
			} else {
				if (x == mid) {
					b[x++] = a[i];
					U (k, i + 1, j - 1) b[y++] = a[k];
				} else {
					b[y++] = a[i];
					U (k, i + 1, j - 1) b[x++] = a[k];
				}
			}
		} else if (las == 0) {
			// i 在右边
			b[y++] = a[i];
			b[x++] = a[j];
			U (k, i + 1, j - 1) b[y++] = a[k];
		} else if (las == 2) {
			// i 在左边
			b[x++] = a[i];
			b[y++] = a[j];
			U (k, i + 1, j - 1) b[x++] = a[k];
		}
	}
	
	U (i, l, r) a[i] = b[i];
	solve(l, mid);
	solve(mid + 1, r);
}

int main() {
	rd(n);
	U (i, 1, n) a[i] = i;
	solve(1, n);
	report();
}