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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#740095#5414. Stop, Yesterday Please No MorezxkWA 15ms4600kbC++172.5kb2024-11-13 01:07:172024-11-13 01:07:17

Judging History

你现在查看的是最新测评结果

  • [2024-11-13 01:07:17]
  • 评测
  • 测评结果:WA
  • 用时:15ms
  • 内存:4600kb
  • [2024-11-13 01:07:17]
  • 提交

answer

#include <bits/stdc++.h>
#define int long long

using namespace std;

typedef pair<int, int> PII;
typedef long long LL;

const int inf = 1e18, mod = 1e9 + 7;

void solve(int cnt)
{
    int n, m, k;
	cin >> n >> m >> k;
    string s;
    cin >> s;
    int x = 0, y = 0; 
    int up = 0, down = 0, left = 0, right = 0;
    for (auto c : s)
    {
        if (c == 'U') 
        {
            y -- ;
            down = max(down, -y);
        }
        else if (c == 'D')
        {
            y ++ ;
            up = max(up, y);
        }
        else if (c == 'L') 
        {
            x ++ ;
            right = max(right, x);
        }
        else
        {
            x -- ;
            left = max(left, -x);
        }
    }
    if (up + down >= n || left + right >= m)
    {
        if (k == 0) cout << n * m << '\n';
        else cout << 0 << '\n';
        // cout << '?' << '\n';
        return;
    }
    if ((n - up - down) * (m - left - right) < k)
    {
        cout << 0 << '\n';
        cout << up << ' ' << down << '\n';
        cout << left << ' ' << right << '\n'; 
        return;
    }
    
    vector<vector<int>> a(n*4+11, vector<int>(m*4+11));
    int xx = 2*n+5, yy = 2*m+5;
    a[xx][yy] = 1;
    x = n - (up + down), y = m - (left + right);
    up = down = xx;
    left = right = yy;
    for (auto c : s)
    {
        if (c == 'U') xx ++ ;
        else if (c == 'D') xx -- ;
        else if (c == 'R') yy -- ;
        else yy ++ ;
        a[xx][yy] = 1;
        up = min(up, xx);
        left = min(left, yy);
        down = max(down, xx);
        right = max(right, yy);
    }
    for (int i = 1; i <= n*4+10; i ++ )
    {
        for (int j = 1; j <= m*4+10; j ++ )
        {
            a[i][j] += a[i-1][j] + a[i][j-1] - a[i-1][j-1];
            // cout  << a[i][j] << ' ';
        }
        // cout << '\n';
    }

    auto check = [&](int i, int j) {
    	if (i+x-1 >= up && j+y-1 >= left && i <= down && j <= right) return true;
    	else return false;
    };
    int ans = 0;
    for (int i = 1; i + x - 1 <= n*4+10; i ++ )
    {
        for (int j = 1; j + y - 1 <= m*4+10; j ++ )
        {
        	if (!check(i, j)) continue;
			if (a[i+x-1][j+y-1] - a[i+x-1][j-1] - a[i-1][j+y-1] + a[i-1][j-1] == x*y - k) 
			{
				ans ++ ;
			}
        }
    }
    cout << ans << '\n';
}

signed main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	
	int T;
	cin >> T;
	int cnt = 1;
	while (T -- )
	{
		solve(cnt);
		cnt ++ ;
	}
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3560kb

input:

3
4 5 3
ULDDRR
4 5 0
UUUUUUU
4 5 10
UUUUUUU

output:

2
20
0

result:

ok 3 number(s): "2 20 0"

Test #2:

score: -100
Wrong Answer
time: 15ms
memory: 4600kb

input:

1060
19 12 0
UDLDDUUUUDDDLLRDUDUURULUUUDRDUDRDRLRLRLULULLLDLDDRLUUUURUUUDDRLLRUUUDULURUULLRDRLRDDURDUUURRRLURLRUULRRUDURDLUUURDLURDDLUUURDDRLLURRDLRUDLRDRLLRRDRDDLDRURRRLUDULLLRUUDLRRURRDLLRRRDLLRDDDLRLRURURDDDL
11 1 0
UR
3 18 33
UDRLR
17 11 132
RLDRDLDRUU
6 10 13
UULUDDLRDLUUDLDD
1 15 0
D
6 20 50
D...

output:

228
11
20
99
18
15
34
240
15
0
4 0
2 2
0
1 1
1 0
13
14
18
26
16
1
19
108
8
2
2
3
7
0
30
16
21
0
0 3
0 1
8
10
9
15
5
320
11
7
3
0
0
12
0
0 1
3 0
11
0
0
14
0
22
36
51
23
7
6
4
2
48
28
8
63
22
49
13
10
4
108
10
18
44
0
15
9
0
3 0
0 0
4
30
14
99
105
10
14
17
0
66
10
11
28
52
34
56
33
14
56
90
14
0
121
3...

result:

wrong answer 11th numbers differ - expected: '0', found: '4'