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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#738413#9532. 长野原龙势流星群urosk0 0ms0kbC++172.3kb2024-11-12 19:00:222024-11-12 19:00:23

Judging History

你现在查看的是最新测评结果

  • [2024-11-12 19:00:23]
  • 评测
  • 测评结果:0
  • 用时:0ms
  • 内存:0kb
  • [2024-11-12 19:00:22]
  • 提交

answer

#define here cerr<<"===========================================\n"
#define dbg(x) cerr<<#x<<": "<<x<<endl;
#include <bits/stdc++.h>
#define llinf 100000000000000000LL // 10^17
#define iinf 2000000000 // 2*10^9
#define pb push_back
#define eb emplace_back
#define popb pop_back
#define fi first
#define sc second
#define endl '\n'
#define all(a) a.begin(),a.end()
#define ceri(a,l,r) {cerr<<#a<<": ";for(ll i_ = l;i_<=r;i_++) cerr<<a[i_]<< " ";cerr<<endl;}
#define cer(a) {cerr<<#a<<": ";for(ll x_ : a) cerr<<x_<< " ";cerr<<endl;}
#define si(a) (ll)(a.size())
using namespace std;
using ld = double;
using ll = long long;
using ull = unsigned long long;
using pii = pair<int,int>;
using pll = pair<ll,ll>;
using pld = pair<ld,ld>;

#define mod 1
ll add(ll x,ll y){
    x+=y;
    if(x<0){
        x%=mod;
        x+=mod;
    }else{
        if(x>=mod) x%=mod;
    }
    return x;
}
ll mul(ll a,ll b){
	a = add(a,0);
	b = add(b,0);
	ll ans = (a*b)%mod;
	if(ans<0) ans+=mod;
	return ans;
}



const ll maxn = 200005;
ll n;
ll a[maxn];
ll par[maxn];
ll dsu[maxn];

ll sz[maxn];

ll root(ll x) {
	while(dsu[x]!=x) {
		dsu[x] = dsu[dsu[x]];
		x = dsu[x];
	}
	return x;
}
ll dub[maxn];
bool cmp(ll i,ll j) {
	i = root(i),j = root(j);
	pll c = {a[i],sz[i]};
	pll b = {a[j],sz[j]};
	if(c.fi*b.sc==c.sc*b.fi) return dub[i]<dub[j];
	return c.fi*b.sc<c.sc*b.fi;
}

ld ans[maxn];

/**
6
1 2 2 1 4
3 1 5 6 6 7
 */
vector<ll> g[maxn];
void dfs(ll u) {
	for(ll s : g[u]) {
		dub[s] = dub[u] + 1;
		dfs(s);
	}
}
void tc(){
	cin >> n;
	cout<<fixed<<setprecision(10);
	for(ll i = 2;i<=n;i++) cin >> par[i];
	for(ll i = 2;i<=n;i++) g[par[i]].pb(i);
	dfs(1);
	for(ll i = 1;i<=n;i++) cin >> a[i];
	set<ll,decltype(&cmp)> pq(cmp);
	for(ll i = 1;i<=n;i++) {
		dsu[i] = i;
		sz[i] = 1;
		pq.insert(i);
	}
	while(si(pq)) {
		ll i = *prev(pq.end());
		pq.erase(prev(pq.end()));
		ans[i] = a[i]*1.0/sz[i];
		//dbg(i);
		if(i==1) continue;
		ll j = par[i];
		i = root(i),j = root(j);
		pq.erase(pq.find(j));
		dsu[i] = j;
		sz[j]+=sz[i];
		a[j]+=a[i];
		pq.insert(j);
	}
	for(ll i = 1;i<=n;i++) cout<<ans[i]<<endl;
}

int main(){
	ios_base::sync_with_stdio(false);cerr.tie(0);cout.tie(0);cin.tie(0);
	int t; t = 1;
	while(t--){
		tc();
	}
	return (0-0);
}

詳細信息

Subtask #1:

score: 0
Runtime Error

Test #1:

score: 0
Runtime Error

input:

2000
1 2 2 4 5 2 3 6 4 2 7 2 8 14 8 12 1 14 4 14 8 18 9 2 7 22 20 22 14 29 28 16 6 21 23 6 21 14 13 9 1 4 18 13 2 39 21 33 18 20 38 27 27 1 49 5 51 3 31 24 10 42 2 44 13 9 35 66 27 60 67 59 29 40 53 2 33 43 26 43 62 16 78 45 14 10 73 69 41 35 25 26 2 70 54 1 54 48 5 36 44 28 90 29 51 51 93 82 95 45 ...

output:


result:


Subtask #2:

score: 0
Runtime Error

Test #32:

score: 0
Runtime Error

input:

200000
1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10 10 11 11 12 12 13 13 14 14 15 15 16 16 17 17 18 18 19 19 20 20 21 21 22 22 23 23 24 24 25 25 26 26 27 27 28 28 29 29 30 30 31 31 32 32 33 33 34 34 35 35 36 36 37 37 38 38 39 39 40 40 41 41 42 42 43 43 44 44 45 45 46 46 47 47 48 48 49 49 50 50 51 51 52 52...

output:


result:


Subtask #3:

score: 0
Skipped

Dependency #1:

0%

Subtask #4:

score: 0
Skipped

Dependency #2:

0%