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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#738358#8230. SubmissionsThe_cosmosWA 76ms15048kbC++146.4kb2024-11-12 18:49:022024-11-12 18:49:29

Judging History

你现在查看的是最新测评结果

  • [2024-11-12 18:49:29]
  • 评测
  • 测评结果:WA
  • 用时:76ms
  • 内存:15048kb
  • [2024-11-12 18:49:02]
  • 提交

answer

// A
#include <bits/stdc++.h>
using namespace std;
using db = double;
using lb = long double;
using ull = unsigned long long;
using uint = unsigned int;
using ll = long long;
//using i128 = __int128;
//using ui128 = unsigned __int128;
#define REP(i, first, last) for(int i = (first); i <= (last); ++ i)
#define DOW(i, first, last) for(int i = (first); i >= (last); -- i)
#define int long long
#define pb emplace_back
#define ob pop_back
#define pii pair<int, int>
#define MPR make_pair
#define fi first
#define se second
#define tpl tuple<int, int, int>
#define MTP make_tuple
#define poly vector<int>
#define polyp vector<pii>
#define polyt vector<tpl>
#define all(x) x.begin(), x.end()
#define CVR(a, q) memset(a, q, sizeof a)
#define CLR(a) memset(a, 0, sizeof a)
#define CPY(a, q) memcpy(a, q, sizeof a)
#define PCT __builtin_popcount
const int N = 2e5 + 5, M = 1e6 + 5;
const int mod1 = 1e9 + 7, mod2 = 998244353, mod = 1e9 + 7;
const long long inf = 1e18;
const int dx[] = {-1, -1, -1, 0, 0, 0, 1, 1, 1};
const int dy[] = {-1, 0, 1, -1, 0, 1, -1, 0, 1};
mt19937 rnd(chrono::steady_clock::now().time_since_epoch().count());
unordered_map<string, int> mp;
unordered_map<int, string> pre;
// opt 表示当前题目哪些队过了
int idx = 0;
int id(string s) {
	if(!mp.count(s)) return pre[idx + 1] = s, mp[s] = ++ idx;
	return mp[s];
}
int cnt[N][30];// cnt 表示当前题目有多少个人通过了
pair<pii, string> po[N];// po 表示第 i 个队伍的 {过题数,时间}
// bool check(pair<pii, string> x, pair<pii, string> y) {
	// return x.fi.fi > y.fi.fi || x.fi.se < y.fi.se;
// }
bool cmp(pair<pii, string> x, pair<pii, string> y) {
	if(x.fi.fi != y.fi.fi) return x.fi.fi > y.fi.fi;
	return x.fi.se < y.fi.se;
}
void Solve() {
	int m; cin >> m;
	mp.clear(), idx = 0;
	REP(i, 1, 26) REP(j, 1, m) cnt[j][i] = 0;
	poly acc[m + 1][30], rej[m + 1][30];
	REP(i, 1, m) {
		char p;
		int t;
		string c, s;
		cin >> c >> p >> t >> s;
		// cerr << t << '\n';
		int x = id(c);
		int nt = t + cnt[x][p - 64] * 20;
		if(s[0] == 'a') acc[x][p - 64].pb(nt);
		else rej[x][p - 64].pb(nt);
		cnt[x][p - 64] ++;
	}
	int n = idx;
	// cerr << "qwq";
	//团队个数
	REP(i, 1, n) {
		int w = 0, sum = 0;
		REP(j, 1, 26) if(acc[i][j].size()) w ++, sum += acc[i][j][0];
		po[i] = {{w, sum}, pre[i]};
		// cerr << pre[i] << ' ' << w << '\n';
	}
	sort(po + 1, po + n + 1, cmp);
	int dddn = n;
	// cerr << n << '\n';
	REP(i, 1, n) {
		int x = id(po[i].se);
		REP(j, 1, 26) if(acc[x][j].size()) goto p1;
		n = i - 1; break;
		p1 : continue;
	}
	// cerr << n << '\n';
	unordered_map<string, bool> se;
	int Auline = min((int)ceil(0.1 * n), 35ll);
	REP(i, 1, n) {
		// cerr << po[i].se << ' ' << po[i].fi.fi << ' ' << po[i].fi.se << '\n';
		if(po[i].fi.fi > po[Auline].fi.fi) se[po[i].se] = 1;
		else if(po[i].fi.fi == po[Auline].fi.fi && po[i].fi.se <= po[Auline].fi.se)
			se[po[i].se] = 1;
	}
	// cerr << n << '\n';
	//1.本来就可以拿 Au 的。
	// cout << se.size() << '\n';
	// for(auto it : se) cout << (it.first) << ' ';
	// cout << '\n';
	REP(i, 1, n) {
		if(po[i].fi.fi != po[Auline].fi.fi - 1) continue;
		int ti = po[i].fi.se, x = id(po[i].se);
		REP(j, 1, 26) {
			if(!rej[x][j].size() || acc[x][j].size()) continue;
			if(ti + rej[x][j][0] <= po[Auline].fi.se) se[po[i].se] = 1;
		}
	}
	// cout << se.size() << '\n';
	// for(auto it : se) cout << (it.first) << ' ';
	// cout << '\n';
	//2. 自己改掉可以拿 Au 的。
	// cerr << po[3].se << '\n' << po[3].fi.se << ' ' << po[3].fi.fi << '\n';
	if(Auline < n) {
		// cerr << po[Auline].se << '\n' << po[Auline + 1].se << ' ' << po[Auline + 1].fi.se << '\n';
		REP(i, 1, Auline) {
			int w = po[i].fi.fi, sum = po[i].fi.se;
			int x = id(po[i].se);
			REP(j, 1, 26) {
				if(!acc[x][j].size()) continue;
				if(acc[x][j].size() == 1) {
					int nw = w - 1, ns = sum - acc[x][j][0];
					if(!nw) {
						int ppip = Auline;
						ppip = min((int)ceil(0.1 * (n - 1)), 35ll);
						// cerr << ppip << ' ' << Auline << '\n';
						if(ppip == Auline) {
							se[po[Auline + 1].se] = 1;
							break;
						}
					}
					else if(!cmp({{nw, ns}, ""}, po[Auline + 1])) {
						se[po[Auline + 1].se] = 1;
						// cerr << nw << ' ' << ns << '\n';
						break;
					}
				}
				else {
					int nw = w, ns = sum - acc[x][j][0] + acc[x][j][1];
					if(!cmp({{nw, ns}, ""}, po[Auline + 1])) {
						se[po[Auline + 1].se] = 1;
						break;
					}
				}
			}
			if(se.count(po[Auline + 1].se)) break;
		}
		if(se.count(po[Auline + 1].se))
			REP(i, Auline + 2, n) {
				if(po[i].fi.fi == po[Auline + 1].fi.fi && po[i].fi.se == po[Auline + 1].fi.se)
					se[po[i].se] = 1;
			}
	}
	// cout << se.size() << '\n';
	// for(auto it : se) cout << (it.first) << ' ';
	// cout << '\n';
	//3.别人退下来。
	// cerr << n << '\n';
	if(n < dddn) {
		pair<pii, string> maxn = {{1, inf}, ""};
		Auline = min((int)ceil(0.1 * (n + 1)), 35ll);
		if(po[Auline].fi.fi == 1)
			REP(t, n + 1, dddn) {
				int x = id(po[t].se);
				int minn = inf;
				REP(i, 1, 26) 
					if(rej[x][i].size()) {
						minn = min(minn, rej[x][i][0]);
					}
						
				REP(i, 1, 26) 
					if(rej[x][i].size() && minn == rej[x][i][0]) {
						if(minn <= po[Auline].fi.fi) {
							se[po[t].se] = 1;
							break;
						}
					}
					// acc[x][i].pb(minn);
			}
		REP(t, n + 1, dddn) {
			int x = id(po[t].se);
			REP(i, 1, 26) 
				if(rej[x][i].size()) {
					if(maxn.fi.se == inf || !cmp({{1, rej[x][i].back()}, po[t].se}, maxn))
						maxn = {{1, rej[x][i].back()}, po[t].se};
				}
			}
		n ++, po[n] = maxn;
		// cerr << maxn.se << ' ' << maxn.fi.fi << ' ' << maxn.fi.se << '\n';
		sort(po + 1, po + n + 1, cmp);
		
		// cerr << po[Auline].se << ' ' << po[Auline].fi.fi << ' ' << po[Auline].fi.se << '\n';
		// cerr << Auline << '\n';
		// cerr << n << '\n';
		REP(i, 1, n) {
			// cerr << po[i].se << ' ' << po[i].fi.fi << ' ' << po[i].fi.se << '\n';
			if(po[i].fi.fi > po[Auline].fi.fi) se[po[i].se] = 1;
			else if(po[i].fi.fi == po[Auline].fi.fi && po[i].fi.se <= po[Auline].fi.se)
				se[po[i].se] = 1;
		}
	}
	
	cout << se.size() << '\n';
	for(auto it : se) cout << (it.first) << ' ';
	cout << '\n';
}
signed main() {
//	freopen(".in", "r", stdin);
//	freopen(".out", "w", stdout);
	ios_base::sync_with_stdio(false);
	cin.tie(nullptr), cout.tie(nullptr);
	int T = 1;
	cin >> T;
	while (T --) {
		Solve();
	}
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 3ms
memory: 13300kb

input:

2
5
TSxingxing10 G 0 rejected
TSxingxing10 B 83 accepted
aoliaoligeiliao J 98 accepted
TS1 J 118 accepted
TS1 B 263 accepted
12
AllWayTheNorth A 0 rejected
YaoYaoLingXian Y 10 accepted
XuejunXinyoudui1 X 200 rejected
XuejunXinyoudui1 X 200 accepted
LetItRot L 215 accepted
AllWayTheNorth W 250 accept...

output:

2
TSxingxing10 TS1 
4
ImYourFan LetItRot XuejunXinyoudui1 AllWayTheNorth 

result:

ok 2 test cases ok. (2 test cases)

Test #2:

score: 0
Accepted
time: 3ms
memory: 15048kb

input:

2
2
jiangly_fan A 1 accepted
jiangly B 23 accepted
3
conqueror_of_tourist A 1 accepted
conqueror_of_tourist A 2 accepted
tourist B 23 accepted

output:

2
jiangly jiangly_fan 
1
conqueror_of_tourist 

result:

ok 2 test cases ok. (2 test cases)

Test #3:

score: 0
Accepted
time: 0ms
memory: 14028kb

input:

2
13
A A 1 accepted
A X 1 accepted
K K 1 rejected
B B 2 accepted
C C 2 accepted
D D 2 accepted
E E 2 accepted
F F 2 accepted
G G 2 accepted
H H 2 accepted
I I 2 accepted
J J 2 accepted
K K 2 rejected
12
A A 1 accepted
A X 1 accepted
B B 2 accepted
C C 2 accepted
D D 2 accepted
E E 2 accepted
F F 2 a...

output:

11
J G F H B E K I D C A 
1
A 

result:

ok 2 test cases ok. (2 test cases)

Test #4:

score: 0
Accepted
time: 2ms
memory: 14268kb

input:

2
11
A A 1 accepted
B B 1 accepted
C C 2 accepted
D D 2 accepted
E E 2 accepted
F F 2 accepted
G G 2 accepted
H H 2 accepted
I I 2 accepted
J J 2 accepted
K K 2 accepted
12
A A 1 accepted
A X 1 accepted
K K 1 rejected
B B 2 accepted
C C 2 accepted
D D 2 accepted
E E 2 accepted
F F 2 accepted
G G 2 a...

output:

2
B A 
2
K A 

result:

ok 2 test cases ok. (2 test cases)

Test #5:

score: 0
Accepted
time: 76ms
memory: 14700kb

input:

100000
1
M3JytWoaEXxkACy_mBAQ R 111 accepted
1
sQ O 151 accepted
1
JinbrcS58gNEE5yTSkT B 140 accepted
1
cklwBY V 243 accepted
1
v_o42YmvEKFwy Q 260 rejected
1
ftQVK8S_um22w K 265 accepted
1
_bQBeFeDpYQhvZcLf9l3 Z 147 accepted
1
KvDcEAIDN A 75 rejected
1
H3MUK6 A 101 rejected
1
gxYo_oCFn2J8aIben U 54...

output:

1
M3JytWoaEXxkACy_mBAQ 
1
sQ 
1
JinbrcS58gNEE5yTSkT 
1
cklwBY 
1
v_o42YmvEKFwy 
1
ftQVK8S_um22w 
1
_bQBeFeDpYQhvZcLf9l3 
1
KvDcEAIDN 
1
H3MUK6 
1
gxYo_oCFn2J8aIben 
1
_isnlUGK0ddI 
1
BERcVjyCp 
1
6In2do_50ylch 
1
f0r3SXc6brMjT 
1
7njYOapSwvogA 
1
x 
1
y1w3KvxylfxwprRBYw 
1
aGedzS 
1
iPo0GDhIF 
1
4Vf...

result:

ok 100000 test cases ok. (100000 test cases)

Test #6:

score: -100
Wrong Answer
time: 64ms
memory: 13412kb

input:

10000
42
Bzs0PiQMXGZ5rRZ_2D G 2 accepted
9XtB_VIfbRRL E 11 accepted
FVJL M 13 rejected
a S 19 accepted
tsd Z 20 rejected
MyCqVEg1ONjZ U 22 accepted
6SgZMn N 51 rejected
Qua1Pti3vKhyQKDUm P 54 accepted
i29 M 63 accepted
zPqu D 68 rejected
xx2yiu6x C 71 rejected
fYuK1KNkuyO5HRCq L 76 rejected
tXWpYVqj...

output:

4
xiLm0TUOF3T tsd fYuK1KNkuyO5HRCq Qua1Pti3vKhyQKDUm 
2
JP t3 
2
77sgqpbTIr_Zt1 fhYPGC8W82NwJTQL 
1
3BQ 
1
buCeoOotAkV8DaFD6 
1
UkXQ3iaNJ 
2
ALTqPt7JUSLrl vwfw 
1
QTEzV6tp 
3
wJlbqIU 4e1l0pO8eFjZwkDo 9cy_y_RNRwex8j7224hz 
2
6mbCu5zA eiuF7a_ 
1
xy6QBr8ECi 
2
PezeyUurYoz7N1iGU ldaKLZb1oS1sS 
4
idqV8Np...

result:

wrong answer the numbers are different in the case 4. (test case 4)